I am a physics student at Warwick University, although for the first 2 years of my degree I studied joint honours Maths and Physics. I have always had a real passion for the sciences and hope that my tutorials can inspire your scientific curiosity too!
I am a patient and friendly person, sometimes funny too! I have been tutoring friends and school mates since I was 15, so along with a lot of babysitting jobs I have experience teaching a range of ages.
The aim of these sessions if to cover whatever you feel you need to work on, so you will guide the syllabus as much as you are comfortable with. Generally we will focus on consolidating basic understanding before moving onto exam style questions.
I will use as many ways as I can think of to explain different concepts; be it diagrams, words, or analogies until you are confident enough to explain things back to me and use them in situations.
Hopefully the sessions will be fun, too! Science is amazing and despite your cranky old school teachers, it can be exciting! Or at least there are some excellent puns to be made...
Can you help me apply to University?
Of course! I've been through the university application process so am familiar with how stressful it can be. Whether you need personal statement help or general advice I'd love to lend a hand!!
If you have any questions, feel free to send me a 'WebMail' or book a 'Meet the Tutor Session' both of which are accessible through this website. Make sure to tell me your exam board and any particular syllabus concerns you have and I can get back to you.
I look forward to meeting you!
|Further Mathematics||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|Further Mathematics||GCSE||£18 /hr|
|-Personal Statements-||Mentoring||£20 /hr|
|Maths and Physics||Bachelors Degree||2:1|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Say you are given the equations of both a line and a curve, for example y=x2+8x-1 and y=3x-7, and asked to find where these two intersect. This just means where the two lines would cross or touch if drawn on the same graph.
To find these points you simply have to equate the equations of the two lines, where they equal eachother must be the points of intersection.
For this example this would mean x2+8x-1=3x-7
Collecting like terms leads to x2+5x+6=0
And from then this is a simple case of solving the quadratic. This expression factorises to (x+2)(x+3)=0 which implies either x=-2 or x=-3. To find the corresponding y coordinates for each point simply input these x values one at a time into either one of the original equations.
For x=-2, we get y=3(-2)-7=-13 so the point is (-2,-13)
For x=-3, we get y=3(-3)-7=-16 so the point is (-3,-16)
Both of these are valid intersection points for the line and curve given.see more