Sam G. A Level Maths tutor, GCSE Maths tutor, 13 plus  Maths tutor, A...

Sam G.

Unavailable

Morse (Masters) - Warwick University

MyTutor guarantee

New to the site and yet to acquire customer reviews. We personally interview all our tutors so if you’re not satisfied, lets us know within 48 hours and we’ll refund you.

This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

About me

Hi, I'm Sam.

I am a second year student at University of Warwick doing Morse which stands for Maths, Operational Research, Statics and Economics.

Availability:

I am available to Tutor every day. My schedule is always changing due to University work and with me being an exec for Floorball and Mind Aware, but simply get in touch and I’m sure we can find a suitable time.

Learning:

I Have now gone through years of education now I know that “one size fits all” does not always work: it didn’t work for me. I have always found that you learn more if you find it enjoyable, so I will always endeavour to make our tutorials fun. Even if that sounds impossible with a subjects like mathematics and physics! I can always show many different methods of how to approach questions making solving them much easier.

Sessions:

Within my tutorials we can cover everything and anything you're finding hard, difficult or just confusing. I feel the best way to do this is to communicate beforehand which topics you struggle with so that I can prepare some questions and we can tackle them together understanding how to complete a question correctly.

Hi, I'm Sam.

I am a second year student at University of Warwick doing Morse which stands for Maths, Operational Research, Statics and Economics.

Availability:

I am available to Tutor every day. My schedule is always changing due to University work and with me being an exec for Floorball and Mind Aware, but simply get in touch and I’m sure we can find a suitable time.

Learning:

I Have now gone through years of education now I know that “one size fits all” does not always work: it didn’t work for me. I have always found that you learn more if you find it enjoyable, so I will always endeavour to make our tutorials fun. Even if that sounds impossible with a subjects like mathematics and physics! I can always show many different methods of how to approach questions making solving them much easier.

Sessions:

Within my tutorials we can cover everything and anything you're finding hard, difficult or just confusing. I feel the best way to do this is to communicate beforehand which topics you struggle with so that I can prepare some questions and we can tackle them together understanding how to complete a question correctly.

Show more

Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

DBS Icon

Standard DBS Check

31/03/2014

Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
Further MathsA-level (A2)A*
PhysicsA-level (A2)A*
AEAUni admission testMerit

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£20 /hr
MathsA Level£20 /hr
Further MathematicsGCSE£18 /hr
MathsGCSE£18 /hr
PhysicsGCSE£18 /hr
Maths13 Plus£18 /hr

Questions Sam has answered

given y=(1+x)^2, find dy/dx

There are two ways in which this we can do this,

The first is explanding the brackets to get 1+2x+x2 and differentiating to get 2+2x.

The second way is using the chain rule, let u=1+x such that y=u2 and differentiate both equations to get du/dx=1 and dy/du=2u. (du/dx)(dy/du)  = dy/dx. plug theses together and we get dy/dx = 2u. To finish off we will need to have the answer in its original form of in terms of x's so plug in u=1+x to gain 2+2x

As you may see both ways generated the same answer. It doesn't matter which way you do alsong as you remember the rules, I will personally do both to double check my answer.

There are two ways in which this we can do this,

The first is explanding the brackets to get 1+2x+x2 and differentiating to get 2+2x.

The second way is using the chain rule, let u=1+x such that y=u2 and differentiate both equations to get du/dx=1 and dy/du=2u. (du/dx)(dy/du)  = dy/dx. plug theses together and we get dy/dx = 2u. To finish off we will need to have the answer in its original form of in terms of x's so plug in u=1+x to gain 2+2x

As you may see both ways generated the same answer. It doesn't matter which way you do alsong as you remember the rules, I will personally do both to double check my answer.

Show more

2 years ago

729 views

Send Sam a message

A Free Video Meeting is a great next step. Just ask Sam below!


Send message

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do Online Lessons work?

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok