Hi, I'm Sam.
I am a second year student at University of Warwick doing Morse which stands for Maths, Operational Research, Statics and Economics.
I am available to Tutor every day. My schedule is always changing due to University work and with me being an exec for Floorball and Mind Aware, but simply get in touch and I’m sure we can find a suitable time.
I Have now gone through years of education now I know that “one size fits all” does not always work: it didn’t work for me. I have always found that you learn more if you find it enjoyable, so I will always endeavour to make our tutorials fun. Even if that sounds impossible with a subjects like mathematics and physics! I can always show many different methods of how to approach questions making solving them much easier.
Within my tutorials we can cover everything and anything you're finding hard, difficult or just confusing. I feel the best way to do this is to communicate beforehand which topics you struggle with so that I can prepare some questions and we can tackle them together understanding how to complete a question correctly.
|Further Mathematics||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Further Mathematics||GCSE||£18 /hr|
|Maths||13 Plus||£18 /hr|
|AEA||Uni Admissions Test||Merit|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
There are two ways in which this we can do this,
The first is explanding the brackets to get 1+2x+x2 and differentiating to get 2+2x.
The second way is using the chain rule, let u=1+x such that y=u2 and differentiate both equations to get du/dx=1 and dy/du=2u. (du/dx)(dy/du) = dy/dx. plug theses together and we get dy/dx = 2u. To finish off we will need to have the answer in its original form of in terms of x's so plug in u=1+x to gain 2+2x
As you may see both ways generated the same answer. It doesn't matter which way you do alsong as you remember the rules, I will personally do both to double check my answer.see more