Sophie S. GCSE Biology tutor, GCSE Chemistry tutor, GCSE Physics tuto...

Sophie S.

£22 /hr

Studying: Biochemistry (MBiochem) (Masters) - St Andrews University

4.9
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11 reviews| 45 completed tutorials

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About me

Hello, I’m Sophie and I’m in my third year at the University of St Andrews, studying biochemistry. I have previous experience at tutoring as I tutored a family friend in all three sciences for her GCSEs. I have also done maths tutoring for children from 8 to 17 years old at Kumon. I am friendly, patient and dedicated person who loves the sciences amd maths and is very happy to help others.

Hello, I’m Sophie and I’m in my third year at the University of St Andrews, studying biochemistry. I have previous experience at tutoring as I tutored a family friend in all three sciences for her GCSEs. I have also done maths tutoring for children from 8 to 17 years old at Kumon. I am friendly, patient and dedicated person who loves the sciences amd maths and is very happy to help others.

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About my sessions

The sessions will be tailored to what you wish to learn. I aim to improve confidence in the subject and help develop a better understanding. In the session we will work at your own pace, ensuring nothing is missed out and a complete understanding is achieved. I look forward to hearing from you, please don’t hesitate to ask any questions.  

The sessions will be tailored to what you wish to learn. I aim to improve confidence in the subject and help develop a better understanding. In the session we will work at your own pace, ensuring nothing is missed out and a complete understanding is achieved. I look forward to hearing from you, please don’t hesitate to ask any questions.  

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Ratings & Reviews

4.9from 11 customer reviews
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Erika (Parent)

January 17 2017

Very good first session, so far. Very helpful!

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Chineze & Isioma (Student)

October 16 2016

Very good explanations of topic, easy to comprehend even for a student who with no knowledge of the said topic.

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Lesley (Parent)

May 8 2016

Very knowledgable/ Helpful

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Ross (Parent)

April 28 2016

Very helpful and clear

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A
BiologyA-level (A2)A
ChemistryA-level (A2)A
PhysicsA-level (A2)A

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
BiologyGCSE£22 /hr
ChemistryGCSE£22 /hr
MathsGCSE£22 /hr
PhysicsGCSE£22 /hr
ScienceGCSE£22 /hr

Questions Sophie has answered

Describe the reflex arc.

A stimulus (for example a pin) stimulates the receptor which causes a nerve impulse in the sensory neuron. The impulse travels to a synapse in the spinal cord, where chemicals diffuse across the gap in the synapse and stimulate an impulse in the relay neurone. This travels to another synapse and an impulse in the motor neurone, which travels to the effector, causing a response (for example moving hand)

A stimulus (for example a pin) stimulates the receptor which causes a nerve impulse in the sensory neuron. The impulse travels to a synapse in the spinal cord, where chemicals diffuse across the gap in the synapse and stimulate an impulse in the relay neurone. This travels to another synapse and an impulse in the motor neurone, which travels to the effector, causing a response (for example moving hand)

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2 years ago

1248 views

Solve the quadratic equation x^2 + 3x + 2 = 0, by factorisation.

We need two numbers, a and b, such that a*b = 2 and a+b=3

Looking at the equation it can be seen that 2 and 1 fulfill these conditions.

Therefore x2 +3x +2=0
              = (x+2)(x+1)=0

This means we need either x+2 or x+1 to equal 0
x+2=0 so x= -2
or x+1=0 so x= -1

Therefore x= (-1 , -2)

We need two numbers, a and b, such that a*b = 2 and a+b=3

Looking at the equation it can be seen that 2 and 1 fulfill these conditions.

Therefore x2 +3x +2=0
              = (x+2)(x+1)=0

This means we need either x+2 or x+1 to equal 0
x+2=0 so x= -2
or x+1=0 so x= -1

Therefore x= (-1 , -2)

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2 years ago

832 views

Solve the simultaneous equations 2x + 3y = 4, 3x + 6y = 3

Label the equations
(1): 2x + 3y = 4
(2): 3x + 6y = 3

We need the same number of x's or y's in the equations, so multiply (1) by 3 and (2) by 2
giving (3): 6x + 9y = 12
(4): 6x + 12y = 6

Subtract (3) from (4)
6x + 12y - 6x - 9y = 6 - 12
so 3y= -6
so y= -2

Substitute the y value into (1) to find x
2x + (3*-2) = 4
        2x - 6 = 4
             2x = 10
               x = 5

Check by substituting into (2)
(3*5) + (6*-2) = 15 - 12 = 3 the solutions work

So x = 5 and y = -2

Label the equations
(1): 2x + 3y = 4
(2): 3x + 6y = 3

We need the same number of x's or y's in the equations, so multiply (1) by 3 and (2) by 2
giving (3): 6x + 9y = 12
(4): 6x + 12y = 6

Subtract (3) from (4)
6x + 12y - 6x - 9y = 6 - 12
so 3y= -6
so y= -2

Substitute the y value into (1) to find x
2x + (3*-2) = 4
        2x - 6 = 4
             2x = 10
               x = 5

Check by substituting into (2)
(3*5) + (6*-2) = 15 - 12 = 3 the solutions work

So x = 5 and y = -2

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2 years ago

751 views

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