Kezia  M. GCSE Maths tutor, 13 plus  Maths tutor, 11 Plus Maths tutor...

Kezia M.

Currently unavailable: for regular students

Degree: Medicine (Bachelors) - Southampton University

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About me

Who am I?

I am a second year medical student at the University of Southampton. I absolutely love the course and am very excited to share my love for the subject with other students!

I am very organised and patient as well as being approachable and friendly. I have good experience in teaching - tutored some students in GCSE maths and chemistry.

My strengths

Mathematics, biology and chemistry are my 3 favourite subjects to learn and teach! I will try my very best to explain concepts to students in the easiest way possible - I understant everyone learns differently!

I was unsuccessful in gaining a place in medical school first time round and so I took a gap year and tried again - this means I understand the application process very well and I know exactly what mistakes people (myself) make and how to avoid them! I can offer help with interview preparation as well as writing a strong personal statement.

How my sessions will run

I understand timing is key! My sessions will be paced at a level suitable for YOU - no point rushing to the end of the module only to go over it again another 50 times. Once a topic has been covered, you will know it as well as you know the aphabet! 

Practice makes perfect! I will find many practive questions for you to do to exercise what you have learnt so you can tackle any question the exam throws at you. 

Some students are naturally very clever and don't require as much work - others who are not necessarily the best in class (like myself) can make up for this and achieve just as much through discipline and practice and that is what I will encourage you to do!

I look forward to working with you if you are interested!

Subjects offered

SubjectLevelMy prices
Biology GCSE £18 /hr
Chemistry GCSE £18 /hr
Maths GCSE £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr
-Medical School Preparation- Mentoring £20 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
BiologyA-LevelA
ChemistryA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

General Availability

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Please get in touch for more detailed availability

Questions Kezia has answered

a) You area told that y is proportional to x2 and that when y = 75, x = 5. Find a formula for y in terms of x. y = x b) Find the value of y when x = 3. c) Find the value of x when y = 1200.

a) y is proportional to x^2, when x is 5, y is 75 Therefore: 75 = (something multiplied by) 5^2 75 = 3 x 25 Hence y = 3x^2 b) y = 3 multiplied by 3^2  = 27 c) 1200 = 3x^2 1200/3 = x^2 400 = x^2 Undo the square of x (on both sides!) x = 20

a) y is proportional to x^2, when x is 5, y is 75

Therefore: 75 = (something multiplied by) 5^2

75 = 3 x 25

Hence y = 3x^2

b) y = 3 multiplied by 3^2 

= 27

c) 1200 = 3x^2

1200/3 = x^2

400 = x^2

Undo the square of x (on both sides!)

x = 20

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8 months ago

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