I am currently a first year at Bristol University studying Aerospace Engineering. Given my degree, my interests have always been interested in the sciences and maths.
I have always been involved in various tutoring groups, mostly covering GCSE and A Level Maths but my brother is two years below me so I have always been available to help him in a variety of GCSE subjects and now his A levels too.
I think one of the easiest ways to understand something is to first isolate exactly what confuses you. From there we can structure sessions to cover exactly what you're having difficulties with.
From my perspective, I have always found it easier to understand something if it can be explained in a number of different ways. That means I'll try and do the same for you so if I can't get the idea across immediately, there might be an easier way available.
If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session'! (both accessible through this website). Remember to tell me your exam board and what you're struggling with.
I look forward to meeting you!
|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|-Personal Statements-||Mentoring||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Simon (Parent) September 13 2016
To answer this question you need to use the quotient rule. dy/dx = (vu' - uv')/v2.
U = cos(x) which differentiates to -sin(x) so u'= -sin(x)
v = x so v' = 1
Therefore, dy/dx = ( -xsin(x) - cos(x) ) / x2see more
The start of a personal statement is often the hardest bit. I think it's best to try and convey why you want to study your course without using clichés that entrance examiners will have heard thousands of times before.
In a series circuit, the electrons passes through each component in order before returning to the cell. In a parallel circuit, there are different paths for the electrons to take so the current splits depending on the resistance of each path. The voltage across each path remains the same.see more