Ewan H. GCSE Maths tutor, A Level Maths tutor, GCSE Physics tutor, Me...
£18 - £20 /hr

Ewan H.

Degree: Aerospace Engineering (Masters) - Bristol University

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About me

About me:

I am currently a first year at Bristol University studying Aerospace Engineering. Given my degree, my interests have always been interested in the sciences and maths.

I have always been involved in various tutoring groups, mostly covering GCSE and A Level Maths but my brother is two years below me so I have always been available to help him in a variety of GCSE subjects and now his A levels too.

The Sessions:

I think one of the easiest ways to understand something is to first isolate exactly what confuses you. From there we can structure sessions to cover exactly what you're having difficulties with. 

From my perspective, I have always found it easier to understand something if it can be explained in a number of different ways. That means I'll try and do the same for you so if I can't get the idea across immediately, there might be an easier way available.

What next?

If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session'! (both accessible through this website). Remember to tell me your exam board and what you're struggling with.

I look forward to meeting you!

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Physics A Level £20 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
-Personal Statements- Mentoring £20 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA
PhysicsA-LevelA
Design TechnologyA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

4from 1 customer review

Simon (Parent) September 13 2016

Oliver enjoyed the tutorial

Questions Ewan has answered

How do I differentiate f(x) = cos(x)/x?

To answer this question you need to use the quotient rule. dy/dx = (vu' - uv')/v2. U = cos(x) which differentiates to -sin(x) so u'= -sin(x) v = x so v' = 1 Therefore, dy/dx = ( -xsin(x) - cos(x) ) / x2

To answer this question you need to use the quotient rule. dy/dx = (vu' - uv')/v2.

U = cos(x) which differentiates to -sin(x) so u'= -sin(x)

v = x so v' = 1

Therefore, dy/dx = ( -xsin(x) - cos(x) ) / x2

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8 months ago

224 views

How would you start a personal statement?

The start of a personal statement is often the hardest bit. I think it's best to try and convey why you want to study your course without using clichés that entrance examiners will have heard thousands of times before.

The start of a personal statement is often the hardest bit. I think it's best to try and convey why you want to study your course without using clichés that entrance examiners will have heard thousands of times before.

8 months ago

205 views

What is the difference between a series circuit and a parallel circuit?

In a series circuit, the electrons passes through each component in order before returning to the cell. In a parallel circuit, there are different paths for the electrons to take so the current splits depending on the resistance of each path. The voltage across each path remains the same.

In a series circuit, the electrons passes through each component in order before returning to the cell. In a parallel circuit, there are different paths for the electrons to take so the current splits depending on the resistance of each path. The voltage across each path remains the same.

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8 months ago

288 views
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