Andrew P. A Level Maths tutor, GCSE Maths tutor

Andrew P.

Unavailable

Mathematics (Bachelors) - Birmingham University

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About me

I am a Mathematics student at Birmingham University. I think Maths is a great subject with countless real life applications, and I love helping other people understand and explore it!

Passing on my knowledge and skills to others is an area I'm very comfortable with, as I have a year's Maths and English tutoring experience with Kumon. Additionally I was a youth basketball coach for 4 years before I moved to university.

I regard myself as a friendly and approachable person, so you can expect our sessions to have lots of discussion. I believe that the most effective and interesting sessions are led by the student, with the tutor acting as a guide. In the end, it's all about you and developing your knowledge!

Please feel free to contact me if you have any questions! I hope to speak to you soon.

I am a Mathematics student at Birmingham University. I think Maths is a great subject with countless real life applications, and I love helping other people understand and explore it!

Passing on my knowledge and skills to others is an area I'm very comfortable with, as I have a year's Maths and English tutoring experience with Kumon. Additionally I was a youth basketball coach for 4 years before I moved to university.

I regard myself as a friendly and approachable person, so you can expect our sessions to have lots of discussion. I believe that the most effective and interesting sessions are led by the student, with the tutor acting as a guide. In the end, it's all about you and developing your knowledge!

Please feel free to contact me if you have any questions! I hope to speak to you soon.

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Physical EducationA-level (A2)A*
BiologyA-level (A2)A

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr

Questions Andrew has answered

Solve the quadratic equation x^2 + 4x +1 = 0 by completing the square.

Completing the square means to put our equation into a slightly different form which looks like this, where a and b are real numbers:

(x+a)2 + b = 0

From here, we can rearrange the equation and directly solve for x. Let's have a look at our specific example:

x2 +4x +1 = 0

The first step is to divide the coefficient of x by 2, and add this to x (this is our value of 'a' to go inside our bracket). We then square this value of a and subtract it outside the bracket.

In our example it will look like this:

(x+2)2 - 4 + 1 = 0

(x+2)2 - 3 = 0

We have our equation in completed square form.

[There is a quick way to check we've got this right by expanding out this equation quickly:

(x+2)(x+2) - 3 = 0

x2 + 4x + 4 - 3 = 0

x2 + 4x +1 = 0

We're back to our original equation, so we know we've got it right. Let's go and solve our equation in completed square form.]

We simply rearrange for x:

(x+2)2 - 3 = 0

Add 3 to both sides.

(x+2)2 = 3

Take the square root of both sides. This splits into two possible cases:

Case 1: Positive square root of 3

x+2 = + sqrt(3)

x = - 2 + sqrt(3)

Case 2: Negative square root of 3

x+2 = - sqrt(3)

x = - 2 - sqrt(3)

So our final answer is...

x = - 2 + sqrt(3)

x = - 2 - sqrt(3)

Completing the square means to put our equation into a slightly different form which looks like this, where a and b are real numbers:

(x+a)2 + b = 0

From here, we can rearrange the equation and directly solve for x. Let's have a look at our specific example:

x2 +4x +1 = 0

The first step is to divide the coefficient of x by 2, and add this to x (this is our value of 'a' to go inside our bracket). We then square this value of a and subtract it outside the bracket.

In our example it will look like this:

(x+2)2 - 4 + 1 = 0

(x+2)2 - 3 = 0

We have our equation in completed square form.

[There is a quick way to check we've got this right by expanding out this equation quickly:

(x+2)(x+2) - 3 = 0

x2 + 4x + 4 - 3 = 0

x2 + 4x +1 = 0

We're back to our original equation, so we know we've got it right. Let's go and solve our equation in completed square form.]

We simply rearrange for x:

(x+2)2 - 3 = 0

Add 3 to both sides.

(x+2)2 = 3

Take the square root of both sides. This splits into two possible cases:

Case 1: Positive square root of 3

x+2 = + sqrt(3)

x = - 2 + sqrt(3)

Case 2: Negative square root of 3

x+2 = - sqrt(3)

x = - 2 - sqrt(3)

So our final answer is...

x = - 2 + sqrt(3)

x = - 2 - sqrt(3)

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2 years ago

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