Simon T. GCSE Further Mathematics  tutor, A Level Further Mathematics...

Simon T.

£18 - £22 /hr

Currently unavailable: for new students

Studying: Natural Sciences Tripos (Masters) - Cambridge University

5.0
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

3 reviews| 5 completed tutorials

Contact Simon

About me

Hey, I'm a second year undergraduate at Cambridge studying Natural Science, specialising in Astrophysics. 

I hope my tutoring sessions will be useful and fun. Having enjoyed science so much at school i hope I can pass off my enthusiasm and understanding.

I enjoy teaching and have been involved in outreach events for my university, mainly demonstrating physics to lower secondary age pupils. During 6th form I volunteered in GCSE maths classes, and gained experience. Last summer I worked as an activity leader at a language school in Edinburgh.

Hey, I'm a second year undergraduate at Cambridge studying Natural Science, specialising in Astrophysics. 

I hope my tutoring sessions will be useful and fun. Having enjoyed science so much at school i hope I can pass off my enthusiasm and understanding.

I enjoy teaching and have been involved in outreach events for my university, mainly demonstrating physics to lower secondary age pupils. During 6th form I volunteered in GCSE maths classes, and gained experience. Last summer I worked as an activity leader at a language school in Edinburgh.

Show more

About my sessions

The 55 minute supervisions will be catered  entirely for for the students needs: whether that carefully establishing a firm grasp of the key concepts, or working thorugh the rigours of problems that might be set in exams.

The 55 minute supervisions will be catered  entirely for for the students needs: whether that carefully establishing a firm grasp of the key concepts, or working thorugh the rigours of problems that might be set in exams.

Show more

No DBS Icon

No DBS Check

Ratings & Reviews

5from 3 customer reviews
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Holly (Student)

August 12 2016

Thanks that was a really good lesson, you have explained things very clearly and it makes it easy to understand and Chemistry is starting to make sense.

Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Holly (Student)

August 16 2016

Thanks so much for your help, I really think I am beginning to understand a bit better :).

Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Betina (Student)

June 26 2016

The tutorial was great! I'm looking forward to the next one!

Show more reviews

Qualifications

SubjectQualificationGrade
Physics Higher LevelInternational Baccalaureate (IB)7
Chemistry Higher LevelInternational Baccalaureate (IB)7
Mathematics Higher LevelInternational Baccalaureate (IB)6
English Standard LevelInternational Baccalaureate (IB)6
German Standard LevelInternational Baccalaureate (IB)6
Geography Standard LevelInternational Baccalaureate (IB)7

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
Further Mathematics A Level£20 /hr
PhysicsA Level£20 /hr
Further Mathematics GCSE£18 /hr
ChemistryIB£20 /hr
Further Mathematics IB£20 /hr
MathsIB£20 /hr
PhysicsIB£20 /hr
ScienceIB£20 /hr
-Personal Statements-Mentoring£22 /hr

Questions Simon has answered

Based on Newton's 3 laws of motion why is linear momentum always conserved?

This is a common IB question- fairly tricky the first time you com across it!

This is a common IB question- fairly tricky the first time you com across it!

Show more

1 year ago

664 views

Take the square root of 2i

As with much of complex number the trick here is to change forms to polar representation.

If you think of an argand diagram the number i will be represented as a point straight up on the imaginary axis a distance 2 from the origin.

It can therefore be represented as 2i = 2*e^(iπ/2)

From here it's easy! Just  apply the same indices rules that you have grown so familiar with. 

2 goes to the square root of 2, e^(iπ/2) goes to e^(iπ/4).

so we have the expression (2i)^(1/2) = (2)^(1/2)*(iπ/4)

And now convert back to standard form!

We know the magnitude is square root 2, and the arguement is π/4. Imagined on the argand diagram this is a line slanting at 45 degrees to the horizontal.

We can use the identity e^(iθ) =cos(θ) + i*sin(θ)

cos(π/4)=sin(π/4)= 2^(-1/2)

Thankfully the square roots of 2 cancel (Careful! they will not allways do this!) Therefore we reach the answer:

(2i)^(1/2) = 1 + i

which is satisfyingly elegant

As with much of complex number the trick here is to change forms to polar representation.

If you think of an argand diagram the number i will be represented as a point straight up on the imaginary axis a distance 2 from the origin.

It can therefore be represented as 2i = 2*e^(iπ/2)

From here it's easy! Just  apply the same indices rules that you have grown so familiar with. 

2 goes to the square root of 2, e^(iπ/2) goes to e^(iπ/4).

so we have the expression (2i)^(1/2) = (2)^(1/2)*(iπ/4)

And now convert back to standard form!

We know the magnitude is square root 2, and the arguement is π/4. Imagined on the argand diagram this is a line slanting at 45 degrees to the horizontal.

We can use the identity e^(iθ) =cos(θ) + i*sin(θ)

cos(π/4)=sin(π/4)= 2^(-1/2)

Thankfully the square roots of 2 cancel (Careful! they will not allways do this!) Therefore we reach the answer:

(2i)^(1/2) = 1 + i

which is satisfyingly elegant

Show more

1 year ago

979 views

Arrange a free online meeting


To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Simon

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok