Simon T. GCSE Further Mathematics  tutor, A Level Further Mathematics...

Simon T.

Currently unavailable: for regular students

Degree: Natural Sciences Tripos (Masters) - Cambridge University

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About me

About me:

Hey, I'm a first year undergraduate at Cambridge studying Natural Science, and hope to specialise in theoretical physics. This year I study physics, chemistry, geology and mathematics, and I would be happy to tutor in any of these subjects.

I enjoy running, hillwallking and basking in my lack of musical talent!

The sessions

I hope my tutoring sessions will be useful and fun! Having enjoyed science so much at school i hope I can pass off my enthusiasm and understanding :)

The 55 minute supervisions will be catered  entirely for for the students needs: whether that carefully establishing a firm grasp of the key concepts, or working thorugh the rigours of problems that might be set in exams.

Experience:

I enjoy teaching and have been involved in outreach events for my university, mainly demonstrating physics to lower secondary age pupils. During 6th form I volunteered in GCSE maths classes, and gained experienceThis summer I am working as an activity leader at a language school in Edinburgh.

I am applying to Oxbridge... can you help?:

I am not an expert in the field, despite passing through the system myself, I am fairly certain there is no secret to preperation. However as a passion for your chosen subject and ability to learm well in an academic environemnt, I would be happy to suggest books that you might find enjoyable, and try to provide a flavour of what the interview might be like. 

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Physics A Level £20 /hr
Further Mathematics GCSE £18 /hr
Chemistry IB £20 /hr
Further Mathematics IB £20 /hr
Maths IB £20 /hr
Physics IB £20 /hr
Science IB £20 /hr
-Personal Statements- Mentoring £20 /hr

Qualifications

QualificationLevelGrade
Physics Higher LevelBaccalaureate7
Chemistry Higher LevelBaccalaureate7
Mathematics Higher LevelBaccalaureate6
English Standard LevelBaccalaureate6
German Standard LevelBaccalaureate6
Geography Standard LevelBaccalaureate7
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

5from 3 customer reviews

Holly (Student) August 12 2016

Thanks that was a really good lesson, you have explained things very clearly and it makes it easy to understand and Chemistry is starting to make sense.

Holly (Student) August 16 2016

Thanks so much for your help, I really think I am beginning to understand a bit better :).

Betina (Student) June 26 2016

The tutorial was great! I'm looking forward to the next one!

Questions Simon has answered

Based on Newton's 3 laws of motion why is linear momentum always conserved?

This is a common IB question- fairly tricky the first time you com across it!

This is a common IB question- fairly tricky the first time you com across it!

8 months ago

203 views

Take the square root of 2i

As with much of complex number the trick here is to change forms to polar representation. If you think of an argand diagram the number i will be represented as a point straight up on the imaginary axis a distance 2 from the origin. It can therefore be represented as 2i = 2*e^(iπ/2) From here...

As with much of complex number the trick here is to change forms to polar representation.

If you think of an argand diagram the number i will be represented as a point straight up on the imaginary axis a distance 2 from the origin.

It can therefore be represented as 2i = 2*e^(iπ/2)

From here it's easy! Just  apply the same indices rules that you have grown so familiar with. 

2 goes to the square root of 2, e^(iπ/2) goes to e^(iπ/4).

so we have the expression (2i)^(1/2) = (2)^(1/2)*(iπ/4)

And now convert back to standard form!

We know the magnitude is square root 2, and the arguement is π/4. Imagined on the argand diagram this is a line slanting at 45 degrees to the horizontal.

We can use the identity e^(iθ) =cos(θ) + i*sin(θ)

cos(π/4)=sin(π/4)= 2^(-1/2)

Thankfully the square roots of 2 cancel (Careful! they will not allways do this!) Therefore we reach the answer:

(2i)^(1/2) = 1 + i

which is satisfyingly elegant

see more

8 months ago

201 views
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