Currently unavailable: for regular students
Degree: Computer Science (Bachelors) - Birmingham University
Hi, my name is Aaquib and I'm studying Computer Science at the University of Birmingham. Throughout my life, I have been extremley passionate about Maths, to the extent that I did Maths and Further Maths at both GCSE and A-Level! My love for Maths combined with my interest in programming led me to pursea a career in Computer Science (which is a very Mathematical degree).
My passion for Maths led me to take part in the University of Birmingahm Tuition Scheme where I was a tutor for GCSE Maths students at Shenley Academy.
My ethos for teaching is to get students to learn by actively applying their knowledge on actual problems rather than regurgitating the theory. This is especially true for Maths. My sessions will be guided by you, the student. You will decide at what pace the sessions will run at so that each session is suited to your needs. I will try and make my sessions as engaging and fun as possible, and most importantly, as beneficial as possible.
If you have any questions, please feel free to get in touch. I am also available to answer any questions before each session if there is anything you are unsure about or would like me to focus on specifically.
I look forward to meeting you!
|Maths||A Level||£20 /hr|
|Extended Project Qualification||A-Level||A|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Rearrange equation into the form: y = mx + c
m = gradient
3x + 5y = 7
5y = -3x + 7
y = (-3/5)x + (7/5)
gradient = (-3/5)
1) 2x + 3y = 6
2) 3x + 2y = 5
We can either use substitution or elimination.
Multiply equation 1) by 3 and multiply equation 2) by 2.
1) 6x + 9y = 18
2) 6x + 4y = 10
Equation 1) - Equation 2)
5y = 8
y = 8/5
Substitue y back into either 1) or 2).
6x + (32/5) = 10
6x = 10 - (32/5)
x = 3/5see more