Aaquib N. A Level Maths tutor, GCSE Maths tutor

Currently unavailable: for regular students

Degree: Computer Science (Bachelors) - Birmingham University

MyTutor guarantee

About me

Hi, my name is Aaquib and I'm studying Computer Science at the University of Birmingham. Throughout my life, I have been extremley passionate about Maths, to the extent that I did Maths and Further Maths at both GCSE and A-Level! My love for Maths combined with my interest in programming led me to pursea a career in Computer Science (which is a very Mathematical degree).

My passion for Maths led me to take part in the University of Birmingahm Tuition Scheme where I was a tutor for GCSE Maths students at Shenley Academy.

My ethos for teaching is to get students to learn by actively applying their knowledge on actual problems rather than regurgitating the theory. This is especially true for Maths. My sessions will be guided by you, the student. You will decide at what pace the sessions will run at so that each session is suited to your needs. I will try and make my sessions as engaging and fun as possible, and most importantly, as beneficial as possible.

If you have any questions, please feel free to get in touch. I am also available to answer any questions before each session if there is anything you are unsure about or would like me to focus on specifically.

I look forward to meeting you!

Subjects offered

Subject	Level	My prices
Maths	A Level	£20 /hr
Maths	GCSE	£18 /hr

Qualifications

Qualification	Level	Grade
Mathematics	A-Level	A*
Further Mathematics	A-Level	A*
Physics	A-Level	A
History	A-Level	A
Extended Project Qualification	A-Level	A

CRB/DBS Standard	✓	11/01/2016
CRB/DBS Enhanced		No

General Availability

Currently unavailable: for regular students

Weeks availability

	Mon	Tue	Wed	Thu	Fri	Sat	Sun

Weeks availability

	Before 12pm	12pm - 5pm	After 5pm
MONDAY
TUESDAY
WEDNESDAY
THURSDAY
FRIDAY
SATURDAY
SUNDAY

Please get in touch for more detailed availability

Questions Aaquib has answered

Line AB has the equation 3x + 5y = 7. Find the gradient of Line AB.

Rearrange equation into the form: y = mx + c m = gradient 3x + 5y = 7 5y = -3x + 7 y = (-3/5)x + (7/5) gradient = (-3/5)

Rearrange equation into the form: y = mx + c

m = gradient

3x + 5y = 7

5y = -3x + 7

y = (-3/5)x + (7/5)

gradient = (-3/5)

1 year ago

1267 views

Solve the simultaneous equation: 2x + 3y = 6, 3x + 2y = 5.

1) 2x + 3y = 6 2) 3x + 2y = 5 We can either use substitution or elimination. Using elimination: Multiply equation 1) by 3 and multiply equation 2) by 2. 1) 6x + 9y = 18 2) 6x + 4y = 10 Equation 1) - Equation 2) 5y = 8 y = 8/5 Substitue y back into either 1) or 2). 6x + (32/5) = 10 6x...

1) 2x + 3y = 6

2) 3x + 2y = 5

We can either use substitution or elimination.

Using elimination:

Multiply equation 1) by 3 and multiply equation 2) by 2.

1) 6x + 9y = 18

2) 6x + 4y = 10

Equation 1) - Equation 2)

5y = 8

y = 8/5

Substitue y back into either 1) or 2).

6x + (32/5) = 10