Aaquib N. A Level Maths tutor, GCSE Maths tutor

Aaquib N.

Unavailable

Computer Science (Bachelors) - Birmingham University

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About me

Hi, my name is Aaquib and I'm studying Computer Science at the University of Birmingham. Throughout my life, I have been extremley passionate about Maths, to the extent that I did Maths and Further Maths at both GCSE and A-Level! My love for Maths combined with my interest in programming led me to pursea a career in Computer Science (which is a very Mathematical degree).

My passion for Maths led me to take part in the University of Birmingahm Tuition Scheme where I was a tutor for GCSE Maths students at Shenley Academy.

My ethos for teaching is to get students to learn by actively applying their knowledge on actual problems rather than regurgitating the theory. This is especially true for Maths. My sessions will be guided by you, the student. You will decide at what pace the sessions will run at so that each session is suited to your needs. I will try and make my sessions as engaging and fun as possible, and most importantly, as beneficial as possible.

If you have any questions, please feel free to get in touch. I am also available to answer any questions before each session if there is anything you are unsure about or would like me to focus on specifically.

I look forward to meeting you!

Hi, my name is Aaquib and I'm studying Computer Science at the University of Birmingham. Throughout my life, I have been extremley passionate about Maths, to the extent that I did Maths and Further Maths at both GCSE and A-Level! My love for Maths combined with my interest in programming led me to pursea a career in Computer Science (which is a very Mathematical degree).

My passion for Maths led me to take part in the University of Birmingahm Tuition Scheme where I was a tutor for GCSE Maths students at Shenley Academy.

My ethos for teaching is to get students to learn by actively applying their knowledge on actual problems rather than regurgitating the theory. This is especially true for Maths. My sessions will be guided by you, the student. You will decide at what pace the sessions will run at so that each session is suited to your needs. I will try and make my sessions as engaging and fun as possible, and most importantly, as beneficial as possible.

If you have any questions, please feel free to get in touch. I am also available to answer any questions before each session if there is anything you are unsure about or would like me to focus on specifically.

I look forward to meeting you!

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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11/01/2016

Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A*
PhysicsA-level (A2)A
HistoryA-level (A2)A
Extended Project QualificationA-level (A2)A

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr

Questions Aaquib has answered

Line AB has the equation 3x + 5y = 7. Find the gradient of Line AB.

Rearrange equation into the form: y = mx + c

m = gradient

3x + 5y = 7

5y = -3x + 7

y = (-3/5)x + (7/5)

gradient = (-3/5)

Rearrange equation into the form: y = mx + c

m = gradient

3x + 5y = 7

5y = -3x + 7

y = (-3/5)x + (7/5)

gradient = (-3/5)

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2 years ago

2222 views

Solve the simultaneous equation: 2x + 3y = 6, 3x + 2y = 5.

1) 2x + 3y = 6

2) 3x + 2y = 5

We can either use substitution or elimination.

Using elimination:

Multiply equation 1) by 3 and multiply equation 2) by 2.

1) 6x + 9y = 18

2) 6x + 4y  = 10

Equation 1) - Equation 2)

5y = 8

y = 8/5

Substitue y back into either 1) or 2).

6x + (32/5) = 10

6x = 10 - (32/5)

x = 3/5

1) 2x + 3y = 6

2) 3x + 2y = 5

We can either use substitution or elimination.

Using elimination:

Multiply equation 1) by 3 and multiply equation 2) by 2.

1) 6x + 9y = 18

2) 6x + 4y  = 10

Equation 1) - Equation 2)

5y = 8

y = 8/5

Substitue y back into either 1) or 2).

6x + (32/5) = 10

6x = 10 - (32/5)

x = 3/5

Show more

2 years ago

1085 views

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