Aaquib N. A Level Maths tutor, GCSE Maths tutor

Aaquib N.

Currently unavailable: for regular students

Degree: Computer Science (Bachelors) - Birmingham University

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About me

Hi, my name is Aaquib and I'm studying Computer Science at the University of Birmingham. Throughout my life, I have been extremley passionate about Maths, to the extent that I did Maths and Further Maths at both GCSE and A-Level! My love for Maths combined with my interest in programming led me to pursea a career in Computer Science (which is a very Mathematical degree).

My passion for Maths led me to take part in the University of Birmingahm Tuition Scheme where I was a tutor for GCSE Maths students at Shenley Academy.

My ethos for teaching is to get students to learn by actively applying their knowledge on actual problems rather than regurgitating the theory. This is especially true for Maths. My sessions will be guided by you, the student. You will decide at what pace the sessions will run at so that each session is suited to your needs. I will try and make my sessions as engaging and fun as possible, and most importantly, as beneficial as possible.

If you have any questions, please feel free to get in touch. I am also available to answer any questions before each session if there is anything you are unsure about or would like me to focus on specifically.

I look forward to meeting you!

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA*
PhysicsA-LevelA
HistoryA-LevelA
Extended Project QualificationA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

11/01/2016

CRB/DBS Enhanced

No

Currently unavailable: for regular students

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Questions Aaquib has answered

Line AB has the equation 3x + 5y = 7. Find the gradient of Line AB.

Rearrange equation into the form: y = mx + c m = gradient 3x + 5y = 7 5y = -3x + 7 y = (-3/5)x + (7/5) gradient = (-3/5)

Rearrange equation into the form: y = mx + c

m = gradient

3x + 5y = 7

5y = -3x + 7

y = (-3/5)x + (7/5)

gradient = (-3/5)

7 months ago

472 views

Solve the simultaneous equation: 2x + 3y = 6, 3x + 2y = 5.

1) 2x + 3y = 6 2) 3x + 2y = 5 We can either use substitution or elimination. Using elimination: Multiply equation 1) by 3 and multiply equation 2) by 2. 1) 6x + 9y = 18 2) 6x + 4y  = 10 Equation 1) - Equation 2) 5y = 8 y = 8/5 Substitue y back into either 1) or 2). 6x + (32/5) = 10 6x...

1) 2x + 3y = 6

2) 3x + 2y = 5

We can either use substitution or elimination.

Using elimination:

Multiply equation 1) by 3 and multiply equation 2) by 2.

1) 6x + 9y = 18

2) 6x + 4y  = 10

Equation 1) - Equation 2)

5y = 8

y = 8/5

Substitue y back into either 1) or 2).

6x + (32/5) = 10

6x = 10 - (32/5)

x = 3/5

see more

7 months ago

224 views
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