Currently unavailable: for new students
Degree: Mathematics (Bachelors) - Exeter University
I am a maths student at the University of Exeter and have a genuine love for my subject, which I hope my tutorials will instill in you too.
I tutored Cores 3 and 4 of A level during my own exams, and helped my tutee to attain his grade required to make his university offer. I am patient and approachable, having volunteered at my local hospital during my A levels, and am willing to put in the hours required to get the best for my tutees.
The sessions will cover what you feel they need to, and we will work from the basics upwards. A strong foundation understanding is crucial in mathematics, and the vast majority of seemingly tricky questions can be broken down with practice into steps of basic calculations.
I will work through concepts with you until you understand it well enough to talk me through questions on your own. We will also go through different aproaches one can take when faced with different types of questions and practice determining the most appropriate approach for each.
Hopefully you will have fun during the sessions and come out of them feeling more confident in your abilities.
If you have any questions, feel free to send me a message, or book a 'Meet the Tutor' session, both available through this website.
Be sure to tell me your exam board and what you're struggling with, so we have a good point to start from!
I look forward to meeting you!
|Maths||A Level||£22 /hr|
|Maths||13 Plus||£20 /hr|
|Maths||11 Plus||£20 /hr|
|Science in Society||A-Level||A|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Oscar (Student) September 25 2016
Emily (Student) September 5 2016
Emily (Student) May 31 2016
Emily (Student) May 11 2016
First we need to multiply out the bracket
Then we must make sure our variable is only on one side so we need to deduct 3k from both sides
Now we should isolate our variable so add 21 to both sides of our equation
Finally dividing by 4 gives us k alone
First think how you would solve this if it was simply an '=' sign instead of a >
Deduct 5 from both sides
This would give us 6y>3
Divide both sides by 6
Think: because this is an inequality, is the value you are dividing by >0, in this cae it is so the inequality sign remains the same way around.
SInce the question requires simplified surd form, it makes sense to use the quadratic formula immediately for this question.
This would give us
x = 6 [+-] squareroot(36-(4x1x-2)) / 2
which simplifies to
x= 6 [+-] squrt(44) / 2
look at the square root: is 44 divisible by a square number? Yes: 44=4x11
This means that we can make
squrt(44)=squrt(4x11)=squrt(4)xsqurt(11) = 2xsqurt(11)
Which turns our equation for x into:
x = 6 [+-] 2xsqurt(11) / 2
The numerator and denominator share a factor of 2 so
x = 3 [+-] squrt(11) which is in simplified surd formsee more