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Degree: Mathematics (Bachelors) - Warwick University
|Maths||A Level||£22 /hr|
|Maths||13 Plus||£20 /hr|
|Maths||11 Plus||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
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Jamie (Student) January 27 2017
Jamie (Student) December 9 2016
Ay (Parent) November 7 2016
Ay (Parent) November 18 2016
Method 1 (algebraically):
Since we have "y=" at the start of both equations, we can substitue one into the other to get
Then we want all the x terms on one side of the equation, and all the number terms on the other side. So we can subtract 2x from both sides to get
then add 10 to both sides to get
Now we can substitute this x value back into our first equation to find a value for y!
Then we check that our x and y values (x=15 and y=35) satisfy our second equation.
They do, so we have our answer!
Method 2 (graphically):
If you have graph paper, and can draw accurately enough, you can draw the two equations as graphs (on the same piece of paper) and find the co-ordinates of the point where they cross.
Ideally, we want you to able to solve equations like this using algebra, however being able to draw the graph allows you to visualise what is happening.see more