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Piyush S.

Currently unavailable: for new students

Degree: Electronics Engineering (Doctorate) - Imperial College London University

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About me

About Me:

I am a PhD student in the Department of Electrical/ Electronic Engineering at Imperial College London (one of the top 10 universities in the world). In Sept. 2015, I was awarded a Distinction for my master's degree in the same department. I am quite passionate about Maths and started teaching this subject to my younger brother and my cousins at a small age of 15.  

My Approach: 

Math provides a tool to model and simplify the complicated concepts of the world but its fundamental understanding is difficult to a lot of students. Since this subject relates to problem solving skills, my approach of teaching this subject is quite simple. I teach theory by focussing on solving problems i.e. using practical approach for establishing the understanding of the concepts.

Experience and Feedback:

I have been teaching this subject from an age of 15 and continued to do so during my undergraduate, master's and now the PhD degree. My patience, politeness, confidence and focus on the basic skills have always allowed me to develop an interactive relationship with my students. They have always provided me an excellent feedback for my teaching methods. 

Do I need to be scared if I lack the understanding of the basic concepts?

No, not at all. The regular fear which I have seen in the eyes of a student is when they lack the understanding of the basic skills/ topics which make it quite tough for them to grasp the new advanced concepts. My initial sessions always focus on the preliminary understanding of a topic to make a student more comfortable and confident with the upcoming sessions.

Resources:

Teaching the concepts alone doesn't help much. From my experience, I have learnt that Maths is all about practicising. Thus, I try to make some worksheets for my students which cover questions from a basic level to a moderate level and then to an advanced level. This route guarantees the understanding of the topic immensely.

Contact:

I am always accessible via email. My average replying time is less than half an hour so please contact me if you are interested in tutoring with me. I will try to get in touch as soon as possible.

Subjects offered

SubjectLevelMy prices
Maths A Level £30 /hr
Maths GCSE £30 /hr
Maths IB £30 /hr
Maths 13 Plus £30 /hr
Maths 11 Plus £30 /hr

Qualifications

QualificationLevelGrade
Analogue and Digital Integrated Circuit DesignMasters DegreeDistinction
Electrical EngineeringBachelors Degree9.43/ 10
Science, Maths, EnglishA-Level90/ 100
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for new students

General Availability

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Ratings and reviews

4.9from 13 customer reviews

Jack (Student) August 7 2016

Thank you for all your help i have really enjoyed being with you and hope you have a good time teaching. Once again goodbye and good look

Jack (Student) July 31 2016

Thanks again i didn't really find it that boring but i understand why it had to be done. i will go through them at least 3 times this week. once again thanks and see you next week :-)

Mike (Parent) July 24 2016

Thank you it was fun that lesson and i like scratch and looking forward to seeing you again next week Bye.

Jamila (Parent) July 17 2016

Good teaching methods which helped me grasp key concepts
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Questions Piyush has answered

Find the zeroes of the quadratic polynomial x^2 + 8x + 15.

x2+8x+15 = (x+3)(x+5) So, the value of x2+8x+15 is zero when x2+8x+15 = 0 i.e. x = -3 or x = -5.

x2+8x+15 = (x+3)(x+5)

So, the value of x2+8x+15 is zero when x2+8x+15 = 0 i.e. x = -3 or x = -5.

7 months ago

225 views

Form the differential equation representing the family of curves x = my , where, m is arbitrary constant.

Differentiating the above equation with respet to y: dx/dy = m; Substituting the value of m in the given form: x = (dx/dy) y i.e. the solution is (dx/dy) y - x = 0

Differentiating the above equation with respet to y:

dx/dy = m;

Substituting the value of m in the given form:

x = (dx/dy) y i.e. the solution is

(dx/dy) y - x = 0

7 months ago

216 views

How much work is done in moving a charge of 2 C across two points having a potential difference 12 V?

The amount of charge Q, that flows between two points at potential difference V (= 12 V) is 2 C. Thus, the amount of work W, done in moving the charge is W = QV = 2 * 12 = 24 J

The amount of charge Q, that flows between two points at potential difference V (= 12 V) is 2 C. Thus, the amount of work W, done in moving the charge is

W = QV = 2 * 12 = 24 J

7 months ago

225 views
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