Who am I?
Hello everyone, I'm Youssef and I'm a dental student at the University of Birmingham. Since a young age I've had a passion for science, one which I hope I can pass on to you too. A passion which I continue through studying dentistry.
How will the sessions be run?
Having had tutoring before I understand the importance of student guidance - after all the student know's what they're struggling with more than I do. For this reason sessions will largely be focused on explaining concepts in ways that make it easy to grasp - followed by solving questions successfully.
There is nothing like the feeling of getting the right answer after having difficulty.
How I work
If you contact me with what you're struggling with I will gather resources and ideas to successfully overcome the hurdles. This ensures that the whole session is spent teaching and learning, making efficient use of time.
I hope to teach you soon!
Balancing chemical equations can seem tricky at first, especially when starting out. But by following an order it becomes a quick and easy task.
For the sake of this question we'll balance this equation:
C5H12 + O2 → CO2 + H2O
It's easiest to start from left to right and work your way along until the equation is balanced, then any cancellation can be done.
1. C5H12 + O2 → CO2 + H2O
We can see there are 5 carbons on the left and only 1 on the right, so balance the carbons first
C5H12 + O2 → 5CO2 + H2O
2. C5H12 + O2 → 5CO2 + H2O
There are 12 hydrogens on the left but only 2 on the right, so multiply by 6 to balance.
C5H12 + O2 → 5CO2 + 6H2O
3. C5H12 + O2 → 5CO2 + 6H2O
Now the right hand side has much more oxygens than the left, 10 from the 5CO2 and 6 from the 6H2O for a total of 16. So multiply the O2 on the left by 8 to get 16.
C5H12 + 8O2 → 5CO2 + H2O.
And there you go, the equation is balanced. Working systematically works for even complicated equations.see more