Youssef M. GCSE Biology tutor, GCSE Chemistry tutor, GCSE Maths tutor

Youssef M.

Unavailable

Dentisty (Bachelors) - Birmingham University

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About me

Who am I?

Hello everyone, I'm Youssef and I'm a dental student at the University of Birmingham. Since a young age I've had a passion for science, one which I hope I can pass on to you too. A passion which I continue through studying dentistry.

How will the sessions be run?

Having had tutoring before I understand the importance of student guidance - after all the student know's what they're struggling with more than I do. For this reason sessions will largely be focused on explaining concepts in ways that make it easy to grasp - followed by solving questions successfully. 

There is nothing like the feeling of getting the right answer after having difficulty.

How I work

If you contact me with what you're struggling with I will gather resources and ideas to successfully overcome the hurdles. This ensures that the whole session is spent teaching and learning, making efficient use of time.

I hope to teach you soon!

Who am I?

Hello everyone, I'm Youssef and I'm a dental student at the University of Birmingham. Since a young age I've had a passion for science, one which I hope I can pass on to you too. A passion which I continue through studying dentistry.

How will the sessions be run?

Having had tutoring before I understand the importance of student guidance - after all the student know's what they're struggling with more than I do. For this reason sessions will largely be focused on explaining concepts in ways that make it easy to grasp - followed by solving questions successfully. 

There is nothing like the feeling of getting the right answer after having difficulty.

How I work

If you contact me with what you're struggling with I will gather resources and ideas to successfully overcome the hurdles. This ensures that the whole session is spent teaching and learning, making efficient use of time.

I hope to teach you soon!

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Enhanced DBS Check

30/07/2014

Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
BiologyA-level (A2)A
ChemistryA-level (A2)A

Subjects offered

SubjectQualificationPrices
BiologyA Level£20 /hr
ChemistryA Level£20 /hr
MathsA Level£20 /hr
BiologyGCSE£18 /hr
ChemistryGCSE£18 /hr
MathsGCSE£18 /hr

Questions Youssef has answered

How to balance a chemical equation.

Balancing chemical equations can seem tricky at first, especially when starting out. But by following an order it becomes a quick and easy task.

For the sake of this question we'll balance this equation:
C5H12 + O2 → CO2 + H2O

It's easiest to start from left to right and work your way along until the equation is balanced, then any cancellation can be done.

1. C5H12 + O2 → CO2 + H2O

We can see there are 5 carbons on the left and only 1 on the right, so balance the carbons first

C5H12 + O2 → 5CO2 + H2O

2. C5H12 + O2 → 5CO2 + H2O

There are 12 hydrogens on the left but only 2 on the right, so multiply by 6 to balance.

C5H12 + O2 → 5CO2 + 6H2O

3. C5H12 + O2 → 5CO2 + 6H2O

Now the right hand side has much more oxygens than the left, 10 from the 5COand 6 from the 6H2O for a total of 16. So multiply the O2 on the left by 8 to get 16.

C5H12 + 8O2 → 5CO2 + H2O.

And there you go, the equation is balanced. Working systematically works for even complicated equations.

Balancing chemical equations can seem tricky at first, especially when starting out. But by following an order it becomes a quick and easy task.

For the sake of this question we'll balance this equation:
C5H12 + O2 → CO2 + H2O

It's easiest to start from left to right and work your way along until the equation is balanced, then any cancellation can be done.

1. C5H12 + O2 → CO2 + H2O

We can see there are 5 carbons on the left and only 1 on the right, so balance the carbons first

C5H12 + O2 → 5CO2 + H2O

2. C5H12 + O2 → 5CO2 + H2O

There are 12 hydrogens on the left but only 2 on the right, so multiply by 6 to balance.

C5H12 + O2 → 5CO2 + 6H2O

3. C5H12 + O2 → 5CO2 + 6H2O

Now the right hand side has much more oxygens than the left, 10 from the 5COand 6 from the 6H2O for a total of 16. So multiply the O2 on the left by 8 to get 16.

C5H12 + 8O2 → 5CO2 + H2O.

And there you go, the equation is balanced. Working systematically works for even complicated equations.

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2 years ago

679 views

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