PremiumElizabeth H. A Level Chemistry tutor, GCSE Chemistry tutor, A Level P...

Elizabeth H.

Currently unavailable: for new students

Degree: Natural Science (Masters) - Durham University

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About me

Hi! I'm a Natural Sciences student at Durham University studying Physics and Chemistry. I love learning science and applying it to the real world as well as exam and homework questions, and would love to help you do the same! I tutored Chemistry and Physics while I was at college, and have been tutoring on MyTutor for over a year, so have lots of experience in finding exactly what will help you. I'm friendly and approachable, and having taken time to understand new concepts myself I know that no question is a stupid one! In our sessions you will get the chance to ask me lots of questions and gain understanding of everything you've learnt. We will cover whichever topics you want - just tell me which and your exam board if applicable.  To get in touch, please send me a message. I look forward to seeing you!

About my sessions

Each session is tailored to you! I am happy to talk you through an entire topic in the style of a lesson or even a lecture, or answer your questions, or work through questions set for you by your teachers or myself. Everyone learns differently, so I think it's important to make sure we work together so you learn best. I normally ask that students let me know in advance of a tutorial which topics they would like to cover, so that I can make sure I'm familiar with the syllabus and prepare any questions. 

Subjects offered

SubjectQualificationPrices
Chemistry A Level £24 /hr
Further Mathematics A Level £24 /hr
Maths A Level £24 /hr
Physics A Level £24 /hr
Chemistry GCSE £22 /hr
Further Mathematics GCSE £22 /hr
Maths GCSE £22 /hr
Physics GCSE £22 /hr

Qualifications

SubjectQualificationLevelGrade
MathematicsA-levelA2A*
Further MathematicsA-levelA2A*
Chemistry A-levelA2A*
PhysicsA-levelA2A*
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

Currently unavailable: for new students

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Ratings and reviews

4.9from 12 customer reviews

Benny (Student) March 21 2017

Offered in-depth explanations and reffered to my exam board's specification to ensure I knew everything I needed to. Very helpful!

B (Parent) September 17 2017

Benny (Student) March 7 2017

Mya (Student) December 16 2016

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Questions Elizabeth has answered

A curve has the equation y = x^4 - 8x^2 + 60x + 7. What is the gradient of the curve when x = 6?

To find the gradient of any curve, we take the derivative. So in this case, we need to take dy/dx. We do this by multiplying the term by the power on x, and then lowering the power by one. For example, for the first term, x4, the power is four, so we multiply x4 by four, and the power becomes ...

To find the gradient of any curve, we take the derivative. So in this case, we need to take dy/dx. We do this by multiplying the term by the power on x, and then lowering the power by one. For example, for the first term, x4, the power is four, so we multiply x4 by four, and the power becomes three, so we have 4x3. We repeat this for all of the terms individually to get dy/dx = 4x-16x +60. 

That gives us the gradient at any point. To get the gradient at x = 6 we need to substitute the value in to the new equation, so we get dy/dx = 4 * 63 - 16 * 6 + 60 = 828

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1 year ago

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