Malachi R. GCSE Maths tutor, A Level Maths tutor, GCSE Further Mathem...
£18 - £25 /hr

Malachi R.

Degree: Engineering Science (Masters) - Oxford, Balliol College University

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About me

About Me
I am a second year engineering student at Oxford university. I really enjoy my degree, which employs a wide range of complex physics and maths skills.
I can offer a professional and friendly service, having had experience as a guitar teacher, and helping to tutor younger years in my strongest subjects while still at secondary school. With the online tutoring platform I can provide this during flexible hours at your convenience.
The Sessions
Each session you will be able to see a real improvement in ability. I like to approach topics by focusing on basic understanding, and building up to tackling routine questions and how to gain maximum marks. I will use diagrams and work through standard exam question examples to achieve this.

I can also offer detailed personal statement and interview sessions, and if required can put an experienced emphisis on applying to oxbridge, having been through the daunting process myself.


If you have any questions, feel free to send me a "web mail", or book a session! Don't forget to specify what topics in particular you would like to review with me.

Subjects offered

SubjectLevelMy prices
Electronics A Level £20 /hr
Maths A Level £20 /hr
Physics A Level £20 /hr
Electronics GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
-Personal Statements- Mentoring £20 /hr
.PAT. Uni Admissions Test £25 /hr

Qualifications

QualificationLevelGrade
AQABaccalaureatePass
MathsA-LevelA*
PhysicsA-LevelA*
BiologyA-LevelA
HistoryA-LevelA
PATUni Admissions TestPass
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

5from 11 customer reviews

Brian (Parent) September 29 2016

Brian (Parent) September 29 2016

Brian (Parent) September 27 2016

Brian (Parent) September 20 2016

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Questions Malachi has answered

Represent in partial fraction form the expression x/x^2-3x+2

Partial fractions are just another technique to simplify expressions to make them easier to manipulate in more complex questions. This is a low mark questions, testing your skills at using partial fractions - but dont worry! - once you master the technique all the questions are very similar. T...

Partial fractions are just another technique to simplify expressions to make them easier to manipulate in more complex questions. This is a low mark questions, testing your skills at using partial fractions - but dont worry! - once you master the technique all the questions are very similar.
To begin, all expressions to be simplified will either have an already factorised denominator, or factorisable, like the question we have above. If you find the denominator cant be factorised, then either there has been a mistake earlier in the question or you arn't intended to answer the question using partial fractions. Factorise the denominator
x/(x-1)(x-2)        (if the student struggles to factorise we would look at this for the rest of the session and move on to partial fractions once confident)
The next step is to write the equation in a generalised partial fraction form, the same form your answer is to be in, replacing the unknown numerators with constants to be found, like below
x/(x-1)(x-2) = A/(x-1) + B/(x-2)
From this point there are a few techniques to find the constants A and B. Are there any you have come across before in lessons which we could work from? (if yes, use their familiar method, if not use suggested method). The easiest way to find the constants is to equate the numerators of the two sides of the equation, as so, by multiplying through by both the denominators, giving
x = A(x-2) + B(x-1) 
From here we can substitute in values of x which will eliminate either the first A term or second B term in the expression, allowing us to find the constants A and B
substitute in x = 2
2 = (2-1)*B
B = 2
substitute in x = 1
1 = A*(1-2)
A = -1
We now have everything we need for the solution! Take the new found constants and go back to the generalised solution and substitute them in. The solution is
-1/(x-1) + 2/(x-2)
Previously research students exam board and see whether it is relevant to probe different twists on more complicated partial fractions once the simple process is mastered, eg 3 terms and constants, or numerators of the form Cx + D with higher powers in denominators.

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6 months ago

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