Currently unavailable: for regular students
Degree: Civil Engineering (Bachelors) - Bristol University
Hi my name's Joe, I'm from Cardiff originally and I study Civil Engineering at the University of Bristol, I've just completed my 3rd year and I'm hoping to make a change and study Computer Science.
I went to a welsh speaking school so if you're keen to go through anything in Welsh I can help with that.
If you have any questions please feel free to send me an email and let me know what you're struggling with.
|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|Civil Engineering||Bachelors Degree||2:1|
|Before 12pm||12pm - 5pm||After 5pm|
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To calculate the largest share, first we need to find out how much each part that makes up a share is worth.
To find out how much the smallest part is (i.e 1 part), we divide the value £400 by the sum of the shares (1+2+5) = 8,
400/8 = 50, therefore each part is £50.
to find the largest share (5) we multiply £50 by 5;
£50*5 = £250
to double check we can calculate the value of the remaining shares (2 &1) and then add them together to check it equals £400.
£50*2 = £100 and £50*1 = £50,
the sum of £250,£100 and £50 is £400 therefore we know that we have calcuated correctlysee more
To calculate the value of 2-3 first we know that a negative exponent is equivalent to the inverse of the same number with a positive exponent.
Therefore 2-3= 1/23, the next step is to calculate 23, 2*2*2 = 8, so the answer in it's simplest form is 1/8
y = x2(cos(x)) therefore we will need to use the product rule,
dy/dx = u dv/dx + v du/dx
where u = x2 and v = cos(x)
du/dx = 2x and dv/dx = - sin(x), (don't forget the negative symbol when differentiating cosine)
dy/dx = x2(- sin(x)) + cos(x)(2x)
dy/dx = 2x(cos(x)) - x2(sin(x))see more