Joseff S. A Level Maths tutor, GCSE Maths tutor, A Level Physics tuto...

Joseff S.

Unavailable

Civil Engineering (Bachelors) - Bristol University

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About me

Hi my name's Joe, I'm from Cardiff originally and I study Civil Engineering at the University of Bristol, I've just completed my 3rd year and I'm hoping to make a change and study Computer Science. 

I went to a welsh speaking school so if you're keen to go through anything in Welsh I can help with that. 

If you have any questions please feel free to send me an email and let me know what you're struggling with.

Hi my name's Joe, I'm from Cardiff originally and I study Civil Engineering at the University of Bristol, I've just completed my 3rd year and I'm hoping to make a change and study Computer Science. 

I went to a welsh speaking school so if you're keen to go through anything in Welsh I can help with that. 

If you have any questions please feel free to send me an email and let me know what you're struggling with.

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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11/09/2015

Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
Further MathsA-level (A2)A*
PhysicsA-level (A2)A
Civil EngineeringDegree (Bachelors)2:1

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
PhysicsA Level£20 /hr
MathsGCSE£18 /hr
PhysicsGCSE£18 /hr

Questions Joseff has answered

Calculate the largest share when £400 is shared in the ratio 1 : 2 : 5.

To calculate the largest share, first we need to find out how much each part that makes up a share is worth.

To find out how much the smallest part is (i.e 1 part), we divide the value £400 by the sum of the shares (1+2+5) = 8,

400/8 = 50, therefore each part is £50.

to find the largest share (5) we multiply £50 by 5;

£50*5 = £250

to double check we can calculate the value of the remaining shares (2 &1) and then add them together to check it equals £400.

£50*2 = £100 and £50*1 = £50,

the sum of £250,£100 and £50 is £400 therefore we know that we have calcuated correctly

To calculate the largest share, first we need to find out how much each part that makes up a share is worth.

To find out how much the smallest part is (i.e 1 part), we divide the value £400 by the sum of the shares (1+2+5) = 8,

400/8 = 50, therefore each part is £50.

to find the largest share (5) we multiply £50 by 5;

£50*5 = £250

to double check we can calculate the value of the remaining shares (2 &1) and then add them together to check it equals £400.

£50*2 = £100 and £50*1 = £50,

the sum of £250,£100 and £50 is £400 therefore we know that we have calcuated correctly

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2 years ago

4383 views

Calculate the value of 2^(–3) as a fraction in its simplest form.

To calculate the value of 2-3 first we know that a negative exponent is equivalent to the inverse of the same number with a positive exponent. 

Therefore 2-3= 1/23, the next step is to calculate 23, 2*2*2 = 8, so the answer in it's simplest form is 1/8

 

To calculate the value of 2-3 first we know that a negative exponent is equivalent to the inverse of the same number with a positive exponent. 

Therefore 2-3= 1/23, the next step is to calculate 23, 2*2*2 = 8, so the answer in it's simplest form is 1/8

 

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2 years ago

2582 views

Find dy/dx when y = x^2(cos(x)).

y = x2(cos(x)) therefore we will need to use the product rule, 

dy/dx = u dv/dx + v du/dx

where u = x2 and v = cos(x)

du/dx = 2x and dv/dx = - sin(x), (don't forget the negative symbol when differentiating cosine)

dy/dx = x2(- sin(x)) + cos(x)(2x)

dy/dx = 2x(cos(x)) - x2(sin(x))

y = x2(cos(x)) therefore we will need to use the product rule, 

dy/dx = u dv/dx + v du/dx

where u = x2 and v = cos(x)

du/dx = 2x and dv/dx = - sin(x), (don't forget the negative symbol when differentiating cosine)

dy/dx = x2(- sin(x)) + cos(x)(2x)

dy/dx = 2x(cos(x)) - x2(sin(x))

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2 years ago

967 views

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