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Degree: Medicinal and Biological Chemistry (MChem) (Masters) - Edinburgh University
Hey there!! My name is Andreas and I study Medicinal and Biological Chemistry (MChem) at University of Edinburgh (UoE). I consider myself passionate in the field of Science and Maths and at the same time I try to learn more and become better like you do!! I’m patient, friendly and very approachable which are features that a good tutor MUST have!! My genuine enthusiasm about Science and the fact that I enjoy helping people drove me to become an online tutor and who knows maybe yours as well!! J
Even though my degree is focusing on Chemistry, my knowledge on other sciences and maths is not limited. On the contrary, I was awarded for the Highest International Subject Mark for International GCSE Mathematics for scoring full marks in the exams.
The sessions will be based on your needs and focus on understanding the key concepts, explaining anything in a clear and simple way and mainly solving examples and exercises.
|Biology||A Level||£20 /hr|
|Chemistry||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
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First thing we have to do is to eliminate one of the variables, either x or y (it doesn’t matter which one). In order to achieve that, we aim to have the same co-efficient (number in front of x or y) of a variable in both equations.
In this example, we can observe that no co-efficient is the same so we have to do some manipulation first before eliminating a variable!
Multiplying 2x+5y=17 by 2, give us 4x+10y=34 (Remember to multiply by 2 all the numbers)
Now that we have the same x co-efficient in both equations we can eliminate the x variable by subtracting one equation from the other:
4x + 10y = 34
– 4x + 7y = 25
Hence, we can substitute y in one of the initial equations e.g. 2x+5y=17
2x+5(3) = 17
Therefore, the variables are x=1 and y=3see more
This is a neutralisation reaction between an acid (sulfuric acid) and a base (copper carbonate). When a carbonate reacts with an acid, the products are a salt, carbon dioxide and water.
carbonate + acid --> salt + carbon dioxide + water
ATTENTION: If you are NOT familiarised with these reactions, I advise first to revise and then try to solve the question.
First thing to do when we tackle problem like this one is to write down the balanced equation (if it is not given)
CuCO3 + H2SO4 --> CuSO4 + CO2 + H2O
RFM (CuCO3) = 124 g mol-1
Number of moles of CuCO3 = 6.2 g / 124 g mol-1 = 0.05 mol
For every 1 mole of CuCO3, 1 mole of CO2 is produced (Using the stoichiometry of the equation)
Number of moles of CO2 = 0.05 mol
Volume of CO2 gas released = 0.05 mol * 24 dm3 = 1.2 dm3 = 12000 cm3see more