Hi! I'm Kyle, and I've just completed my degree in Maths & Economics at the University of York. I have always loved learning about and teaching maths, and have a broad understanding of the topics covered at GCSE and A Level.
I have a lot of tutoring experience from my time at college and university. I have volunteered at a professional maths tutor, as well ashelping fellow college students with A Level maths exams to get the grades they need. At university, I was Head Student Mentor for my college, piloting a new mentoring scheme to aid new students with the transition to university and organising group seminars for course related questions.
The key to a productive and enjoyable tutoring session is that you decide what we cover. The sessions are designed to be fun and interesting, whilst making sure that you get the help you need to answer any question on a topic that you may not feel confident on. I always think a good target to aim for is that once we have gone through a topic in a session or two, you feel confident enough to explain to me how to do the question. Everyone is different, so I will always take your suggestions on board and tailor our sessions for you as an individual.
If you have any questions, just send me a WebMail or request a free Meet the Tutor Session. Just let me know your exam board and what you want to cover in the sessions. I look forward to meeting you!
|Maths||A Level||£20 /hr|
|Economics & Mathematics||Bachelors Degree||3rd|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
The key point to remember when dealing with an algebra equation is that whatever operation you carry out on one side of the equation, you MUST do to the other side as well.
To solve this equation, we first want to collect like terms onto one side of the equation, in this case the 'x' terms. To do this, we will subtract the '3x' term from BOTH sides of the equation:
To complete the process of collecting like terms, we now need to add '6' to both sides of the equation, so that we are left with only 'x' terms on the left hand side :
Now that we have collected all like terms, we can simplify the equation, which becomes:
Finally, to solve the equation, we want to find the value of 'x' on its own. We have the value for 2x, so we can divide BOTH sides of the equation by 2 to solve for x:
x=13/2 or x=6.5see more