Henry H. GCSE Maths tutor, A Level Maths tutor, GCSE Further Mathemat...

Henry H.

Currently unavailable: for regular students

Degree: Materials Science (Bachelors) - Oxford, The Queen's College University

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Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Further Mathematics GCSE £18 /hr
Maths GCSE £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
Further MathsA-LevelA*
PhysicsA-LevelA*
ChemistryA-LevelA*
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CRB/DBS Standard

02/12/2015

CRB/DBS Enhanced

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Currently unavailable: for regular students

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Questions Henry has answered

The radius of a circular disc is increasing at a constant rate of 0.003cm/s. Find the rate at which the area is increasing when the radius is 20cm.

The rate at which the area is increasing, dA/dt, can be written with terms we know or can find out easily: dA/dt=dA/dr x dr/dt. Area of a disc, A = (pi)r^2 dA/dr=2(pi)r Rate of change of radius, dr/dt=0.003cm/s Therefore, dA/dt=2(pi)r x 0.003 = 2(pi) x 20 x 0.003 =0.12(pi) = 0.377cm^2/s

The rate at which the area is increasing, dA/dt, can be written with terms we know or can find out easily: dA/dt=dA/dr x dr/dt.

Area of a disc, A = (pi)r^2

dA/dr=2(pi)r

Rate of change of radius, dr/dt=0.003cm/s

Therefore, dA/dt=2(pi)r x 0.003

= 2(pi) x 20 x 0.003

=0.12(pi)

= 0.377cm^2/s

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5 months ago

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