Henry H. GCSE Maths tutor, A Level Maths tutor, GCSE Further Mathemat...

Henry H.

Currently unavailable: for regular students

Degree: Materials Science (Masters) - Oxford, The Queen's College University

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About me

Hi, I'm Henry, a 20 year old Materials Science student at Oxford University, going into my third year. My degree is essentially uses a lot of physics and some chemistry to observe how materials (mainly metals) behave and why. Besides that, I play quite a bit of football, and cricket when it's hot and sunny.

About my sessions

For my sessions, I would set the student questions in advance, before going through them in the tutorial. I can explain concepts well, and from multiple angles. Understanding concepts is the most important part to learning maths and will be strived for. Practice  is key for exams, as it builds experience used to recognise patterns and similarities between questions, and eventually leads to these entering long-term memory.

Subjects offered

SubjectQualificationPrices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Further Mathematics GCSE £18 /hr
Maths GCSE £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr

Qualifications

SubjectQualificationLevelGrade
MathsA-levelA2A*
Further MathsA-levelA2A*
PhysicsA-levelA2A*
ChemistryA-levelA2A*
Disclosure and Barring Service

CRB/DBS Standard

02/12/2015

CRB/DBS Enhanced

No

General Availability

Currently unavailable: for regular students

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Questions Henry has answered

The radius of a circular disc is increasing at a constant rate of 0.003cm/s. Find the rate at which the area is increasing when the radius is 20cm.

The rate at which the area is increasing, dA/dt, can be written with terms we know or can find out easily: dA/dt=dA/dr x dr/dt. Area of a disc, A = (pi)r^2 dA/dr=2(pi)r Rate of change of radius, dr/dt=0.003cm/s Therefore, dA/dt=2(pi)r x 0.003 = 2(pi) x 20 x 0.003 =0.12(pi) = 0.377cm^2/s

The rate at which the area is increasing, dA/dt, can be written with terms we know or can find out easily: dA/dt=dA/dr x dr/dt.

Area of a disc, A = (pi)r^2

dA/dr=2(pi)r

Rate of change of radius, dr/dt=0.003cm/s

Therefore, dA/dt=2(pi)r x 0.003

= 2(pi) x 20 x 0.003

=0.12(pi)

= 0.377cm^2/s

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1 year ago

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