Joshua D. GCSE Maths tutor, 11 Plus Maths tutor, IB Maths tutor, 13 p...

Joshua D.

Currently unavailable: for regular students

Degree: Materials Science (Masters) - Oxford, Corpus Christi College University

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About me

About Me

Hi! I'm an Undergraduate studying Materials Science at the University of Oxford, about to begin my second year of study. I have a passion for the Physical Sciences - in particular Maths, Physics and Chemistry, and am keen to encourage such a passion in others while helping them with anything they find particularly tough.

I have previous experience with both tutoring and classroom teaching at Fiwilia school in Zambia, as well as working as a classroom assistant at my local school on Friday afternoons.
 I really enjoy tutoring and hope that any students would enjoy my tutoring too!

What I can teach:

My degree in Materials Science focuses predominantly on the three subjects I took at Higher Level for the IB: Physics, Maths and Chemistry. I am happy to tutor these up to IB Higher Level Standard.

I am also more than happy to tutor anyone interested in Materials Science and who would potentially like to apply for the subject - including help with Interviews and PAT tests for Oxford, or with Personal Statements/Interviews for other Universities (I also applied succesfully to Imperial College, Manchester and Exeter).

Finally I spent three years at a French International School, and studied French up to IB Standard Level, so would be keen to help any students with their French.

How I Teach:

I find tutoring works best when the student leads the sessions with the questions that they have. If possible I encourage students to send me their questions in advance so that I can provide the most comprehensive answers possible when we work through problems together, however I am also very happy to take any spotaneous questions as we go along. Succesful sessions for me tend to include plenty of active discussion on the topic, and working through plenty of past paper questions together.

Availability

I'm available for as much tutoring as possible, excluding 21-25 July and 8-13 September, and  can work flexible hours throughout the summer. I would also be keen to continue tutoring through the following academic year(s), whether it is for regular or one-off help sessions. Please get in touch and book a free meeting if you're interested!

Subjects offered

SubjectLevelMy prices
Chemistry GCSE £18 /hr
French GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
Chemistry IB £20 /hr
Maths IB £20 /hr
Physics IB £20 /hr
French 13 Plus £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr
-Personal Statements- Mentoring £20 /hr
.PAT. Uni Admissions Test £25 /hr

Qualifications

QualificationLevelGrade
Preliminary Examinations in Material ScienceHigherFirst with Distinction
HL MathsBaccalaureate7
HL PhysicsBaccalaureate7
HL ChemistryBaccalaureate7
SL EconomicsBaccalaureate7
SL FrenchBaccalaureate7
SL EnglishBaccalaureate6
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

5from 2 customer reviews

Tessa (Student) November 23 2016

Tessa (Student) August 18 2016

Questions Joshua has answered

How can I impress the examiner in the writing paper of my GCSE exam?

So the best way that I have found of impressing an examiner, is through the use ofinteresting phrases and tenses. Knowing some unique vocab is also good but is more of a sign of having memorised words and can also be hard to work into your passage. For example, you can use 'si clauses' to wor...

So the best way that I have found of impressing an examiner, is through the use of interesting phrases and tenses. Knowing some unique vocab is also good but is more of a sign of having memorised words and can also be hard to work into your passage.

For example, you can use 'si clauses' to work two tenses into one phrase:

The most common use of the Si clause is to use:

Si + Verb in Imperfect Tense + Verb in Conditional Tense

eg: Si j'étais riche, j'achèterais une voiture!

Translation: If I were rich, I would buy a car!

You could also use some idiomatic phrases that really show an understanding of french:

eg:

"tomber dans les pommes" translates literally to "To fall in the apples", but is a french idiom that actually means "to faint"

"faire l'andouille" translates literally to "To make the sausage" but actually means "to do something ridiculous"

"Avoir un poil dans la main" translates literally to "to have a hair in the hand" but means "To be lazy"

These sorts of phrases show you really know your french inside-out and are likely to impress the examiner and encourage them to give you a higher mark!

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5 months ago

189 views

Solve the equation log(1-x) - log(x) = 1 where log() is the logarithmic function, base 10.

From the rules of logarithms, we know that: log(A) - log(B) = log(A/B) and thus: log(1-x) - log(x) = log[(1-x)/x] Therefore from the question, we know: log[(1-x)/x] = 1 If we then take both sides of the equation as a power of 10: (1-x)/x = 10^1 and then multiply both sides through by x: ...

From the rules of logarithms, we know that:

log(A) - log(B) = log(A/B)

and thus:

log(1-x) - log(x) = log[(1-x)/x]

Therefore from the question, we know:

log[(1-x)/x] = 1

If we then take both sides of the equation as a power of 10:

(1-x)/x = 10^1

and then multiply both sides through by x:

1-x=10x

Solving for x:

1=11x

x=1/11

We can check our answer by inserting it into the original equation:

log(1-x) - log(x) = log[1-(1/11)] - log[1/11]

and using the rule log(A) - log(B) = log(A/B):

log[1-(1/11)] - log[1/11] = log(10/11)-log(1/11)

= log[(10/11)/(1/11)]

= log(10)

= 1

Thus we know x=1/11

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5 months ago

183 views

Trolley A weighs 5kg and is moving at 15m/s to the right. It collides with a stationary Trolley B, weighing 10kg more than Trolley A. After the collision they move off together. Calulate the velocity that they move off with.

To start with, we should work out all of the quantities we need:  Mass of Trolley A:  MA= 5kg  Mass of Trolley B: B weighs 10kg more than A  --> Therefore MB= 10 + 5 = 15kg  Mass of Both Trolleys together: MAB = 15 + 5 = 20kg Initial Velocity of A: VA= 15 m/s  Initial Velocity of B: VB=...

To start with, we should work out all of the quantities we need: 

Mass of Trolley A:  MA= 5kg 

Mass of Trolley B: B weighs 10kg more than A 

--> Therefore MB= 10 + 5 = 15kg 

Mass of Both Trolleys together: MAB = 15 + 5 = 20kg

Initial Velocity of A: VA= 15 m/s 

Initial Velocity of B: VB= 0 m/s

By the conservation of momentum, we know that the total momentum of a closed system is unchanged for any process. Thus the initial and final momenta of the two trollies combined are the same, ie:

PA + PB = PAB where P is momentum

We know that momentum P = mv

Therefore:

MAVA + MBVB = MABVAB

From above, we know all of these quantities except for VAB which is the quantity we need to find for the answer. Thus we can substitute in all of the values and find VAB:

(5x15) + (15x0) = (20xVAB)

75 = 20VAB

VAB = 75/20 = 3.75 m/s

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5 months ago

149 views
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