Currently unavailable: for new students
Degree: MSci Physics (Masters) - Birmingham University
I am a second year physics student at the University of Birmingham. I've always had a passion for understanding the way that the world works, and love to pass that understanding and excitement on to others. I am friendly, approachable and patient, so there's no need to worry about asking "silly questions". I have A*s in maths and physics at A-level, and was in the top 10% of my year group in my first year at uni, so I can help with any of your issues in these fascinating subjects.
You will direct the tutorials so I can spend the most time helping you with the problems you need the most help with. I will aim to make the tutorials fun and engaging - why should learning be boring?
I will go over topics in a variety of ways (explanations, diagrams, analogies, etc.) until you fully understand them. In maths and science, the key step is understanding the material, then answering the exam questions is just a matter of technique.
If you have any questions for me, just send me a webmail or book a "meet the tutor session", so we can discuss the details of your needs (both of these are accessable through the website).
I look forward to meeting you!
|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Ricky (Parent) December 3 2016
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The product rule is a rule for differentiating products of expressions, i.e. 2 expressions multiplied together.
The rule is: if y=A*B, then dy/dx=A*dB/dx +B*dA/dx. This can be remembered as "Write down the first, differentiate the second then write down the second, differentiate the first".
Differentiate y= e2x sin(x) with respect to x.
This is a product rule question because there are 2 expressions multiplied together.
To answer this question, we write down the 2 expressions that have been multiplied together:
A=e2x and B=sin(x)
Then, we differentiate each of them
dA/dx =2e2x (Remember that if you have to differentiate eax, it equals a*eax)
dB/dx=cos(x) (remember that differentiating sin(x) gives cos(x)).
Next, we combine these expressions using the rule at the top
so dy/dx=e2x cos(x) + sin(x) *2e2x
As a final step, we can simplify this by taking out a factor of e2x, so
dy/dx=e2x (cos(x) + 2sin(x)).see more