Ellie B. GCSE Maths tutor, 11 Plus Maths tutor, A Level Maths tutor, ...
£18 - £20 /hr

Ellie B.

Degree: Mathematics (Masters) - York University

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About me

I study Mathematics at the University of York, and I am incredibly passionate about my subject: there's nothing I like more than doing Mathematics and helping others with it. I really like teaching people, I volunteer at my local Brownie Unit and I love teaching the girls new crafts and games. So I could really think of nothing better than to teach students Maths.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Further Mathematics GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
Maths 11 Plus £18 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA
Further MathematicsA-LevelA
PhysicsA-LevelB
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

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Questions Ellie has answered

Solve Inx + In3 = In6

To solve Inx + In3 = In6 we must follow some basic log rules,  logb(mn) = logb(m) + logb(n) if we compare this with the left side of our equation, Inx + In3, we will set m = x and n = 3,  mn is therefore 3x this means that Inx + In3 is equivalent to In3x So replacing that into our original ...

To solve Inx + In3 = In6 we must follow some basic log rules, 

logb(mn) = logb(m) + logb(n)

if we compare this with the left side of our equation, Inx + In3, we will set m = x and n = 3, 

mn is therefore 3x

this means that Inx + In3 is equivalent to In3x

So replacing that into our original equation:

In3x = In6

Take In of both sides

3x = 6

therefore x = 2

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7 months ago

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