Daniel  M. GCSE Maths tutor, GCSE Physics tutor, GCSE Biology tutor, ...

Daniel M.

Currently unavailable: for new students

Degree: Physics (Bachelors) - Bath University

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About me

Hi! I'm Daniel! As a patient, understanding, and industrious tutor, I aim to nourish your child's academic curiosity in a caring, understandable and encouraging manner so that they may be the best that they can be. I'm currently reading Physics at the University of Bath and am entering my second year. I live and breathe science and am very passionate and enthusiastic about them (particularly Physics and Maths) and am keen to instil these attributes in your child. Comprehension is critical to the success of your child in the sciences and I aim to nurture this through a variety of 'tried and tested' methods (such as exam questions, flashcards, diagrams, examples, analogies, and memorisation techniques.)  I also aim to make the tutorials enjoyable so that he/she really excels in these fields. My teaching experience ranges from workshops for developing reading, numeracy and communication skills for students in key stages 3 and 4 as well as my peer mentor experience, which provides a balanced background in a 1-to-1 setting for developing key skills. It is essential that you explain to me which concepts that you are struggling with and under which exam board you are studying so that I can perform at my best and prepare beforehand to best prepare your child. I am also happy to mentor in preparing a personal statement as I have much experience and have access to a lot of resources for compressing, polishing and refining the personal statement. I am very much looking forward to meeting you and helping your child in this next brave step towards success!

Subjects offered

Maths A Level £30 /hr
Biology GCSE £30 /hr
Chemistry GCSE £30 /hr
Maths GCSE £30 /hr
Physics GCSE £30 /hr
Science GCSE £30 /hr
-Personal Statements- Mentoring £30 /hr


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CRB/DBS Standard


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General Availability

Currently unavailable: for new students

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Ratings and reviews

5from 73 customer reviews

Ralph (Student) June 15 2017

My son has requested that tutorials resume on Daniel's return

Caroline (Parent) June 15 2017

Dan has been a fantastic tutor. He has made a massive difference to my son's confidence with Physics and exams in general. He is officially a 'legend' in our house!

Dave (Parent) June 8 2017

Jake felt like he really learnt a lot from his latest lesson across a broad range of science topics. It was a real confidence boost for him which has reflected in his recent revision.

Konstantina (Student) June 7 2017

Very professional and knowledgeable tutor. Has helped me a lot throughout my GCSEs!
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Questions Daniel has answered

Can you explain the formula method for solving quadratic equations?

We can use the formula method (for solving quadratic equations) to find 'roots' or values of x that satisfy or 'work out' for a given quadratic equation of an unknown variable (say x.) The formula is: x=-b(+or- sqrt[b2-4ac])/2a Note that the 'plus or minus' can give us 2 possible values or 'r...

We can use the formula method (for solving quadratic equations) to find 'roots' or values of x that satisfy or 'work out' for a given quadratic equation of an unknown variable (say x.) The formula is:

x=-b(+or- sqrt[b2-4ac])/2a

Note that the 'plus or minus' can give us 2 possible values or 'roots' for the unknown 'x'. These may be 2 positive roots, 2 negative roots, or a negative and a positive root. These roots are the coordinates where a curve/line intersects with the x axis (we know that y=0 on the x-axis already.)

We may compare our quadratic equation to the general format (ax2+bx+c) to obtain the values for a, b, and c, which are coefficients of x (c is the coefficient of x0 which equals 1.)

Our 2 values may then be substituted back into our original equation to show that the 2 sides 'match' and thus the equation is valid. We let the quadratic equation equal zero to display that the 2 sides are balanced or 'homogeneous'.


Solve the quadratic equation 3x2+9x+3 via the formula method.

Firstly, we must compare the above quadratic equation with the general format (ax2+bx+c) to obtain values for the coefficients of x. We can see that a=3, b=9, and c=3. Our general formula:

x=-b(+or- sqrt[b2-4ac])/2a

is thus

x=-9(+or- sqrt[(9)2-4(3)(3)])/2(3)

So that by solving for x, x=-0.381 (3 d.p.) and x=-2.618 (3 d.p.). We obtained these answers by adding and subtracting the square root terms (respectively) and performing the arithmetic.

We can check that these are correct by equating the quadratic to zero and substituting in our x values:



Thus our roots are correct! The equations do not equal zero exactly as we have rounded our roots to 3 decimal places.

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11 months ago

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