PremiumDaniel  M. GCSE Maths tutor, GCSE Physics tutor, GCSE Biology tutor, ...
£24 - £26 /hr

Daniel M.

Degree: Physics (Bachelors) - Bath University

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About me

Hi! I'm Daniel! A patient, understanding, and industrious tutor. I shall nourish your child's academic curiosity in a caring, comprehensible, and encouraging manner so that they become the best. I'm a third year reading Physics at the University of Bath. I live and breathe science and am passionate and enthusiastic about instilling these attributes in your child. Comprehension is critical to the success of your child in the sciences and I aim to nurture this through a variety of 'tried and tested' methods (such as exam questions, flashcards, diagrams, examples, analogies, and memorisation techniques.) I also aim to make the tutorials enjoyable so that he/she really excels in these fields, particularly in Maths and Physics. My teaching experience ranges from workshops for developing reading, numeracy and communication skills for students in key stages 3-4 as well as my peer mentor experience, which provides a balanced background in a 1-to-1 setting for developing key skills. Please explain to me which concepts that you are struggling with and under which exam board you are studying so that I can perform at my best and prepare beforehand to best prepare your child. I also mentor in preparing personal statements as I have much experience and have access to a lot of resources for compressing, polishing and refining the personal statement. I look forward to meeting you and helping your child in this next brave step towards success!

About my sessions

I follow nationally approved lesson plans used throughout the country and by my father (an R.S. teacher.) For the first 5-10 minutes, I ask your son/daughter what subject he/she wants to improve, while assessing their current understanding. This is done by asking them to define and use key terms, explain important concepts, and apply these fundamental ideas to 'real-life' scenarios that tend to be given in exam questions. After this brief introduction, I spend approximately 20 minutes with your son/daughter revising these key terms and concepts while improving vocabulary and scientific terminology. This is followed by reinforcing their explanations and understandings with all the necessary key terms, calculations, and concepts. For a further 20 minutes, we shall initially attempt some past-paper question examples together. After your son/daughter has the necessary knowledge, clarity, and confidence, I ask them to answer by themselves, under my supervision and to explain them in simple terms while maintaining correct terminology. For the final 5-10 minutes, we recap the key points, concepts, and terminology. We shall also discuss any unscheduled changes to future sessions if applicable (i.e. to accommodate school sports days and the like.) I also informally set some problems or reading as necessary. I tend to overrun at no extra cost so to finish my points, as well as educating your child being more important than a few minutes of time.

Subjects offered

Maths A Level £26 /hr
Biology GCSE £24 /hr
Chemistry GCSE £24 /hr
Maths GCSE £24 /hr
Physics GCSE £24 /hr
Science GCSE £24 /hr
-Personal Statements- Mentoring £26 /hr


Disclosure and Barring Service

CRB/DBS Standard


CRB/DBS Enhanced


General Availability

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Before 12pm12pm - 5pmAfter 5pm

Please get in touch for more detailed availability

Ratings and reviews

5from 73 customer reviews

Ralph (Student) June 15 2017

My son has requested that tutorials resume on Daniel's return

Caroline (Parent) June 15 2017

Dan has been a fantastic tutor. He has made a massive difference to my son's confidence with Physics and exams in general. He is officially a 'legend' in our house!

Dave (Parent) June 8 2017

Jake felt like he really learnt a lot from his latest lesson across a broad range of science topics. It was a real confidence boost for him which has reflected in his recent revision.

Konstantina (Student) June 7 2017

Very professional and knowledgeable tutor. Has helped me a lot throughout my GCSEs!
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Questions Daniel has answered

Can you explain the formula method for solving quadratic equations?

We can use the formula method (for solving quadratic equations) to find 'roots' or values of x that satisfy or 'work out' for a given quadratic equation of an unknown variable (say x.) The formula is: x=-b(+or- sqrt[b2-4ac])/2a Note that the 'plus or minus' can give us 2 possible values or 'r...

We can use the formula method (for solving quadratic equations) to find 'roots' or values of x that satisfy or 'work out' for a given quadratic equation of an unknown variable (say x.) The formula is:

x=-b(+or- sqrt[b2-4ac])/2a

Note that the 'plus or minus' can give us 2 possible values or 'roots' for the unknown 'x'. These may be 2 positive roots, 2 negative roots, or a negative and a positive root. These roots are the coordinates where a curve/line intersects with the x axis (we know that y=0 on the x-axis already.)

We may compare our quadratic equation to the general format (ax2+bx+c) to obtain the values for a, b, and c, which are coefficients of x (c is the coefficient of x0 which equals 1.)

Our 2 values may then be substituted back into our original equation to show that the 2 sides 'match' and thus the equation is valid. We let the quadratic equation equal zero to display that the 2 sides are balanced or 'homogeneous'.


Solve the quadratic equation 3x2+9x+3 via the formula method.

Firstly, we must compare the above quadratic equation with the general format (ax2+bx+c) to obtain values for the coefficients of x. We can see that a=3, b=9, and c=3. Our general formula:

x=-b(+or- sqrt[b2-4ac])/2a

is thus

x=-9(+or- sqrt[(9)2-4(3)(3)])/2(3)

So that by solving for x, x=-0.381 (3 d.p.) and x=-2.618 (3 d.p.). We obtained these answers by adding and subtracting the square root terms (respectively) and performing the arithmetic.

We can check that these are correct by equating the quadratic to zero and substituting in our x values:



Thus our roots are correct! The equations do not equal zero exactly as we have rounded our roots to 3 decimal places.

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1 year ago

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