Currently unavailable: for new students
Degree: Mechanical Engineering (Masters) - Imperial College London University
Hi I'm Will and I am currently studying Mechanical Engineering at Imperial College London. In recent years I have been a tutee of Maths and Physics and with the help of some excellent teaching I saw my grades improve massively so I'm in a good position now to pass on what I've learned. Most of my tutoring experience is in teaching maths and I have loved helping students get to grips with some challenging problems
I am a well-organised, patient teacher and will try to ask you the best questions in order to help you understand the topic. Sessions will be structured around any weaker areas you might have so be sure to let me know what you struggle with. My main focus is very much on going carefully over the theory and helping you gain as deep as possible an understanding of the basic principles involved. Following this, sessions can be moved more towards practice questions in order to develop good exam technique.
I'm easy-going, have a real interest in the subjects I teach, and believe that a relaxed environment is the best one in which to learn.
If there are any questions you have, feel free to send me a message from this page and I'll be happy to help.
|Maths||A Level||£20 /hr|
|Physics||A Level||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Dylan (Student) September 12 2016
Dylan (Student) September 19 2016
Daniel (Student) November 24 2016
Daniel (Student) October 21 2016
The first step of solving this equation to find out what x is, is to factorise it.
This means grouping it into a set of double brackets which will take the form (x+a)(x+b)=0.
The a and the b must give the coefficient of x (7 in this case) when added, and the units (10 in this case) when multiplied.
Thinking of the pairs of factors for 10 (10 & 1, 5 & 2) we can see that the only pair that adds to 7 is 5 and 2.
Therefore our factorised equation looks like this:
If you want to check that this is right, try multiplying out the terms to see if you get back to the equation we started with.
From here we can get our solutions.
For the equation to be right, one of the sets of brackets must be zero, meaning:
x+5 = 0; and x+2 = 0; are both correct.
The last step is simply to rearrange these two equations to make x the subject.
The first gives us x = -5 and the second x = -2see more