PremiumCallum O. GCSE Maths tutor, A Level Maths tutor, 11 Plus Maths tutor,...

Callum O.

Currently unavailable: for regular students

Degree: Computer Science (Masters) - Warwick University

MyTutor guarantee

Contact Callum
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Callum

About me

With a strong passion for Mathematics and the Sciences, I never turn down oppurtunities to share these passions with keen individuals. Having had extensive tuition experience working in one-to-one tuition centres, I have been able to develop numerous tuition styles to suit you/your child's needs. 

I have a wealth of resources from numerous exam boards to facilitate in all aspects of learning. In addition, our tuition sessions would result in you not only being able to understand given topics, but more cruicially be able to define and tackle these topics in your exams.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Chemistry GCSE £18 /hr
Further Mathematics GCSE £18 /hr
Maths GCSE £18 /hr
Physics GCSE £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr

Qualifications

QualificationLevelGrade
Mathematics A-LevelA*
Further Mathematics A-LevelA
PhysicsA-LevelA
ChemistryA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

09/08/2016

Currently unavailable: for regular students

General Availability

Weeks availability
MonTueWedThuFriSatSun
Weeks availability
Before 12pm12pm - 5pmAfter 5pm
MONDAYMONDAY
TUESDAYTUESDAY
WEDNESDAYWEDNESDAY
THURSDAYTHURSDAY
FRIDAYFRIDAY
SATURDAYSATURDAY
SUNDAYSUNDAY

Please get in touch for more detailed availability

Questions Callum has answered

Differentiate with respect to X: x^2 + 2y^2+ 2xy = 2

Assuming the correct tools of differentiation have been taught, we can tackle each term seperately and then rearrange to have dy/dx as the subject. Taking a look at the first term, x^2,  differentiating this term would become 2x (diffentiating x^n = nx^n-1) Taking a look at the second term, 2...

Assuming the correct tools of differentiation have been taught, we can tackle each term seperately and then rearrange to have dy/dx as the subject.

Taking a look at the first term, x^2,  differentiating this term would become 2x (diffentiating x^n = nx^n-1)

Taking a look at the second term, 2y^2, it would appear we could differentiate it just like we did the first term. However this variable involves y and not x, meaning we must differentiate it implicitly.Therefore differentiating 2y^2 would become 4y(dy/dx)

Taking a look at the third term, 2xy, we immediately notice that it has both x terms and y terms involved; this should immediately hint to us that the product rule should be used. Therefore differentiating 2xy would become 2y + 2x(dy/dx) (Differentiating any term involving any other variable other than x with respect to x would require implicit differentiation).

Differentiating any constant (2) would = 0

Putting all these terms together would give:

2x + 4y(dy/dx) + 2y + 2x(dy/dx) = 0

With our basic GCSE knowledge of subject formula we can get:

2x + (dy/dx)(4y+2x) = 0

dy/dx = (-2x) / (4y+2x)

see more

3 months ago

117 views
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Callum

Still comparing tutors?

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

Cookies:

We use cookies to improve our service. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok