Sam W. A Level Maths tutor, GCSE Maths tutor, A Level Further Mathema...

Sam W.

£22 - £24 /hr

Currently unavailable: for new students

Studying: MSci Physics (Masters) - University College London University

5.0
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32 reviews| 33 completed tutorials

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About me

I am a final year Physics MSci student studying at University College London, where I have achieved a first class in my first three years. Seeing my tutees learn and achieve their academic goals has been an incredibly emotionally rewarding experience for me and I hope you will find your tuition sessions equally beneficial. As a tutee, you'll benefit from a patient approach that can help all students flourish in Mathematics and Physics. Tutorials are centered around first fostering a broad understanding for the topics, and then focusing in on question technique. Tutorial content will be driven by your needs, specifically tailored to consolidate your understanding and improve exam technique.  I have extensive experience tutoring Maths and Physics at GCSE and A-Level to students in Oxfordshire where I`ve tutored both applied and pure A-level mathematics and further mathematics modules. My availability is flexible, if you've got any questions don't hesitate to get in touch!I am a final year Physics MSci student studying at University College London, where I have achieved a first class in my first three years. Seeing my tutees learn and achieve their academic goals has been an incredibly emotionally rewarding experience for me and I hope you will find your tuition sessions equally beneficial. As a tutee, you'll benefit from a patient approach that can help all students flourish in Mathematics and Physics. Tutorials are centered around first fostering a broad understanding for the topics, and then focusing in on question technique. Tutorial content will be driven by your needs, specifically tailored to consolidate your understanding and improve exam technique.  I have extensive experience tutoring Maths and Physics at GCSE and A-Level to students in Oxfordshire where I`ve tutored both applied and pure A-level mathematics and further mathematics modules. My availability is flexible, if you've got any questions don't hesitate to get in touch!

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Ratings & Reviews

5from 32 customer reviews
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Viktoria (Parent)

November 15 2016

explains well and goes through everything step by step

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Viktoria (Parent)

October 11 2016

went through everyhting well and went into great detail with everything

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Viktoria (Parent)

June 13 2017

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Viktoria (Parent)

May 30 2017

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A
PhysicsA-level (A2)A

General Availability

Before 12pm12pm - 5pmAfter 5pm
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tuesdays
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fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
Further Mathematics A Level£24 /hr
MathsA Level£24 /hr
PhysicsA Level£24 /hr
MathsGCSE£22 /hr
PhysicsGCSE£22 /hr

Questions Sam has answered

If a car of mass 1000kg travels up a slope inclined at 5 degrees at a speed of 20 meters per second calculate the power output of the car's engine (assuming a resistive force due to friction of 500N)

To find power we are going to need the equation:

P = F v 

Where P is power, F is force and v is velocity

Since the car is travelling at a constant speed up the slope, we know that velocity, v is positive 20 meters per second.

The next step is to determine the force.

In mechanics it is important not to overlook any forces (or components of forces) that might be acting. 

We must consider the force due to gravity and the resistive force due to friction as counterpoints to the driving force of the engine.

First, considering the force due to gravity:

 We must resolve parallel to the plane of the slope, in order to determine the force against which the engine works. This is done by taking the product of mass and the acceleration due to gravity, mg, to find the weight: 1000*9.81 = 9810 Newtons and then resolving parallel with sin(5), giving 1000*9.81*sin(5) = 855 (rounded).

Knowing the force due to friction as 500 Newtons, we sum to get F = 855 + 500 = 1355

With our original equation P = F v we have:

P = 1355 * 20 = 27.1 kW

To find power we are going to need the equation:

P = F v 

Where P is power, F is force and v is velocity

Since the car is travelling at a constant speed up the slope, we know that velocity, v is positive 20 meters per second.

The next step is to determine the force.

In mechanics it is important not to overlook any forces (or components of forces) that might be acting. 

We must consider the force due to gravity and the resistive force due to friction as counterpoints to the driving force of the engine.

First, considering the force due to gravity:

 We must resolve parallel to the plane of the slope, in order to determine the force against which the engine works. This is done by taking the product of mass and the acceleration due to gravity, mg, to find the weight: 1000*9.81 = 9810 Newtons and then resolving parallel with sin(5), giving 1000*9.81*sin(5) = 855 (rounded).

Knowing the force due to friction as 500 Newtons, we sum to get F = 855 + 500 = 1355

With our original equation P = F v we have:

P = 1355 * 20 = 27.1 kW

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1 year ago

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