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Degree: MSci Physics (Masters) - University College London University
I am a final year Physics MSci student studying at University College London, where I have achieved a first class in my first three years. Seeing my tutees learn and achieve their academic goals has been an incredibly emotionally rewarding experience for me and I hope you will find your tuition sessions equally beneficial.
As a tutee, you'll benefit from a patient approach that can help all students flourish in Mathematics and Physics. Tutorials are centered around first fostering a broad understanding for the topics, and then focusing in on question technique. Tutorial content will be driven by your needs, specifically tailored to consolidate your understanding and improve exam technique.
I have extensive experience tutoring Maths and Physics at GCSE and A-Level to students in Oxfordshire where I`ve tutored both applied and pure A-level mathematics and further mathematics modules.
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|Further Mathematics||A Level||£24 /hr|
|Maths||A Level||£24 /hr|
|Physics||A Level||£24 /hr|
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To find power we are going to need the equation:
P = F v
Where P is power, F is force and v is velocity
Since the car is travelling at a constant speed up the slope, we know that velocity, v is positive 20 meters per second.
The next step is to determine the force.
In mechanics it is important not to overlook any forces (or components of forces) that might be acting.
We must consider the force due to gravity and the resistive force due to friction as counterpoints to the driving force of the engine.
First, considering the force due to gravity:
We must resolve parallel to the plane of the slope, in order to determine the force against which the engine works. This is done by taking the product of mass and the acceleration due to gravity, mg, to find the weight: 1000*9.81 = 9810 Newtons and then resolving parallel with sin(5), giving 1000*9.81*sin(5) = 855 (rounded).
Knowing the force due to friction as 500 Newtons, we sum to get F = 855 + 500 = 1355
With our original equation P = F v we have:
P = 1355 * 20 = 27.1 kWsee more