Currently unavailable: for new students
Degree: MSci Physics (Masters) - University College London University
|Further Mathematics||A Level||£24 /hr|
|Maths||A Level||£24 /hr|
|Physics||A Level||£24 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Viktoria (Parent) November 15 2016
Viktoria (Parent) October 11 2016
Viktoria (Parent) March 14 2017
Viktoria (Parent) February 28 2017
To find power we are going to need the equation:
P = F v
Where P is power, F is force and v is velocity
Since the car is travelling at a constant speed up the slope, we know that velocity, v is positive 20 meters per second.
The next step is to determine the force.
In mechanics it is important not to overlook any forces (or components of forces) that might be acting.
We must consider the force due to gravity and the resistive force due to friction as counterpoints to the driving force of the engine.
First, considering the force due to gravity:
We must resolve parallel to the plane of the slope, in order to determine the force against which the engine works. This is done by taking the product of mass and the acceleration due to gravity, mg, to find the weight: 1000*9.81 = 9810 Newtons and then resolving parallel with sin(5), giving 1000*9.81*sin(5) = 855 (rounded).
Knowing the force due to friction as 500 Newtons, we sum to get F = 855 + 500 = 1355
With our original equation P = F v we have:
P = 1355 * 20 = 27.1 kWsee more