Who am I?
I am a veterinary student at the University of Liverpool. From a young age I have always had a keen interest in science - and animals of course! I want to share my passion for science and maths with others, and show that it's not a bore!
What experience do I have?
Before starting university, I spent six months working as a teaching assistant at a secondary school. I also taught GCSE subjects to a student who had missed several months of school. When I moved to Liverpool, I started volunteering with Action Tutoring - a charity providing extra support for disadvantaged students.
How do the sessions work?
I tailor the sessions around you - we will go through what you find difficult, building your confidence along the way. I like to use a variety of resources (diagrams, quizzes, crosswords, etc) to make sure you grasp the concept and can share your knowledge with others. Once you are happy with the basics and comfortable with what you previously found difficult, we will build on that knowledge and push you forward in the subject.
What else can I help with?
Vet school can be extremely challenging to get into - I can offer advice and support with finding work experience, your personal statement and any other queries you may have.
I look forward to meeting you!
|Biology||A Level||£20 /hr|
|Maths||13 Plus||£18 /hr|
|Science||13 Plus||£18 /hr|
|Maths||11 Plus||£18 /hr|
|-Personal Statements-||Mentoring||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Mel (Parent) January 12 2017
Lori (Parent) January 10 2017
Lori (Parent) January 4 2017
Shumiao (Parent) December 29 2016
To solve these simulataneous equations we need to use substitution:
If 2x + y = 13 then y = 13 - 2x
Therefore 3x - y = 12 can be rewritten as 3x - (13 - 2x) = 12
We can expand these brackets and solve for x:
3x - 13 + 2x = 12
-> 5x = 25
--> x = 5
Now we have the value of x, we can subsitute this into either of the initial equations to find the value of y:
2(5) + y = 13
--> 10 + y = 13
--> y = 3
3(5) - y = 12
--> 15 - y = 12
--> y = 3
You can then check your values are correct by subsituting them into either of the equations:
2(5) + (3) = 13
10 + 3 = 13 --> it works!see more
This is the lowest/simplest ratio of the molecule.
For example propene has the formula C3H6 - if we look a the subscript numbers (the ones down here!) we can see that smaller numbers are possible. It is important to know the relationship between these numbers. In this case you can write this simply as CnH2n. Therefore the empirical formula for propene is CH2.
Another example is propane which is C3H8. We can work out that the relationship is as follows: CnH2n+2 and therefore the empirical formula is CH4.see more
A scalar quantity has magnitude only - for example distance.
A vector has magnitude and direction - for example gravity (acceleration towards the centre of Earth).