PremiumRebecca V. A Level Maths tutor, 13 plus  Maths tutor, GCSE Maths tuto...

Rebecca V.

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PGCE Mathematics (Other) - Bristol University

5.0
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16 reviews

This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

21 completed lessons

About me

Hi, I'm Rebecca, I'm 24 and I'm currently part way through my PGCE Mathematics course. As a trainee teacher, I have real insight into the current curriculum and understanding of how best to teach a topic.  My approach is simple, take nothing for granted,  I believe unless you truly understand where something comes from, you will struggle to apply the basic formula to other problems.  I think the job of a tutor is to answer all those why questions, so it's not a case of the answer is this 'because it just is' but actually the foundations of where this came from. And that's what I hope to achieve. :) I am a firm believer of practice makes perfect so I will begin with a few intro questions recapping the previous lesson, then teach a method and its background, before setting some examples and expansion work. 

Hi, I'm Rebecca, I'm 24 and I'm currently part way through my PGCE Mathematics course. As a trainee teacher, I have real insight into the current curriculum and understanding of how best to teach a topic.  My approach is simple, take nothing for granted,  I believe unless you truly understand where something comes from, you will struggle to apply the basic formula to other problems.  I think the job of a tutor is to answer all those why questions, so it's not a case of the answer is this 'because it just is' but actually the foundations of where this came from. And that's what I hope to achieve. :) I am a firm believer of practice makes perfect so I will begin with a few intro questions recapping the previous lesson, then teach a method and its background, before setting some examples and expansion work. 

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About my sessions

Mathematics is learnt by doing, so my lessons will be heavily question based, going through examples and then providing questions to be completed. 

Mathematics is learnt by doing, so my lessons will be heavily question based, going through examples and then providing questions to be completed. 

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Ratings & Reviews

5from 16 customer reviews
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Sophie (Student)

May 11 2017

Thanks for all your help!

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Angela (Parent from Manchester)

April 28 2017

Thank you for helping me! My daughter seemed to enjoy the tutorial... I would like to book you further if you are interested?

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Sophie (Student)

April 7 2017

Amazing

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Sophie (Student)

February 21 2017

Brilliant, thanks for all your help!

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Qualifications

SubjectQualificationGrade
MathematicsDegree (Bachelors)2:1
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A
PhysicsA-level (A2)B

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£24 /hr
MathsGCSE£22 /hr
Maths13 Plus£22 /hr
Maths11 Plus£22 /hr

Questions Rebecca has answered

How do you calculate the hypotenuse of a right angle triangle if the two shorter sides are 6 and 8?

As this is a right angle triangle, we need to use Pythagoras's Theorem. 

This says that the length of the longest side of a right angle triangle (the hypotenuse) is equal to the sqaure root of the sum of the squares of two other sides.

So in this case:

h = sqrt(6^2 + 8^2)

h= sqrt(36 + 64)

h = sqrt (100)

h = 10 :)

Fun fact - this is a special triangle known as a Pythagorean triple as all three sides are integers (whole numbers) 

As this is a right angle triangle, we need to use Pythagoras's Theorem. 

This says that the length of the longest side of a right angle triangle (the hypotenuse) is equal to the sqaure root of the sum of the squares of two other sides.

So in this case:

h = sqrt(6^2 + 8^2)

h= sqrt(36 + 64)

h = sqrt (100)

h = 10 :)

Fun fact - this is a special triangle known as a Pythagorean triple as all three sides are integers (whole numbers) 

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2 years ago

729 views

why does log a + log b = log (ab)

Let log a be some number A and log b be some number B

now the natural log of something is the equivalent of saying a=e^A and b = e^B

So a*b = e^A * e^B which by rules of indices

 = e^(A+B)

Therefore log(ab) = log(e^(A+B))

= A + B = log a + log b 

Let log a be some number A and log b be some number B

now the natural log of something is the equivalent of saying a=e^A and b = e^B

So a*b = e^A * e^B which by rules of indices

 = e^(A+B)

Therefore log(ab) = log(e^(A+B))

= A + B = log a + log b 

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2 years ago

739 views

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