I am a Medical Student currently in my 5th Year at Imperial College London. I also hold a BSc in Biomedical Sciences with Management (2:1) from Imperial. I studied my A-levels and GCSEs at The Haberdasher's Aske's Boys' School achieving As in Maths, Biology, Chemistry and Physics at A/ AS level, as well as A*s in these subjects at GCSE.
What I Teach...
I am an enthusiastic and successful tutor specialising in GCSE/iGCSE Maths, Biology, Chemistry and Physics, as well as A/AS Level Maths, Biology and Chemistry. I also tutor in the Medical School entrance examinations: BMAT and UKCAT.
The purpose of the inital lesson is to firstly identify whether myself and the tutee can successfully work together. It is important that the student not only feels comfortable with me, but that I can identify the teaching style that would provide optimal benefit for them. Secondly, I will determine their academic level and learning pace. This will be used to create performance goals, allowing us to track development and pinpoint weaker areas. Lastly, I will establish the relevant syllabus boards, which in addition to the identified gaps will allow me to create a bespoke plan around the student's needs for the upcoming lessons.
I have previously provided tuition to younger year students at school as a prefect and mentor. I have also tutored my sisters through their GCSEs and A-levels and taught pre-clinical medicine to first and second year medical students. Furthermore, I have attended courses in teaching skills.
Where and When...
As a busy medical student, I am only available to provide tuition on weekends and some weekday evenings.
Please feel free to ask any questions not already answered here!
|-Medical School Preparation-||Mentoring||£22 /hr|
|.BMAT (BioMedical Admissions)||Uni Admissions Test||£25 /hr|
|BMAT||Uni Admissions Test||5.5; 6.7; 3.5A|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
whenever we solve an equation we want to get the unknown (x) alone on one side of the equals sign, but remember whatever we do to one sign of the equation, we have to do to the other. So lets start by subtracting 11 from both sides:
x/2 + 11 = 15
x/2 = 15 - 11
this then works out to
x/2 = 4
from here we can multiply both sides of the equation by 2:
x = 4 x 2
therefore x = 8see more