Gadah A. GCSE Maths tutor, 11 Plus Maths tutor, 13 plus  Maths tutor,...

Gadah A.

Currently unavailable: for regular students

Degree: Dentistry (Bachelors) - Birmingham University

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About me

Hi! I'm Gadah and am currently a Dental Student at the University of Birmingham. I have always been interested in why things happen and always want to understand the reasoning behind explanaitions. I believe that it's best to understand why things happen rather than simply trying to memorise concepts. Maths and Biology are great because they are both quite logical subjects meaning once you understand them, it's easier to apply your knowledge to answer questions!

During these sessions, we'll find out what topics you need the most support in and how you learn best. We'll run through questions and identify whether it's certain types of questions you need help in or whether it's certain subject topics. We'll then practise lots of exam-style and past paper questions to ensure that you've not only developed your understanding in the subject, but you know the techniques in order to answer questions in the exam.

I hope you'll find the sessions fun, sometimes all it takes is a bit of support and guidance in order to achieve your full potential! If you have any questions please message me with the subject and exam board you need help in, I look forward to hearing from you :)

Subjects offered

SubjectLevelMy prices
Maths GCSE £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr

Qualifications

QualificationLevelGrade
BiologyA-LevelA
MathsA-LevelA
ChemistryA-LevelB
General StudiesA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

12/07/2016

CRB/DBS Enhanced

No

Currently unavailable: for regular students

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Questions Gadah has answered

Factorise 2b^2 + 6b

1 - We first need to find a common factor, something that is the same in both parts of the expression. 2 - Then we need to take this out of the expression by dividing both parts of the expression by the common factor. 3 - We then need to rewrite the expression with the common factor outside t...

1 - We first need to find a common factor, something that is the same in both parts of the expression.

2 - Then we need to take this out of the expression by dividing both parts of the expression by the common factor.

3 - We then need to rewrite the expression with the common factor outside the brackets and the rest of the expression that has been divided inside the brackets. 

2b+ 6b

1 - Here both parts of the expression are divisible by 2b. Therefore the common factor is 2b.

2 - 2b2 divided by 2b is b.

6b divided by 2b is 3.

3 - We now rewrite our expression with the common factor on the outside of the brackets:

2b(    )

We now need to put in the expression after it has been divided by the common factor:

2b(b+3) 

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3 months ago

99 views

Solve 5x - 2= 3x + 7

1 - First we need to get all the x values on one side and all the numbers on the otherside of the equals sign. 2 - We then need simplify the equation to get 1 x. Solve 5x - 2= 3x + 7 1 - Remember, whatever you do to one side of the equation, you must do to the otherside of the equation. We w...

1 - First we need to get all the x values on one side and all the numbers on the otherside of the equals sign.

2 - We then need simplify the equation to get 1 x.

Solve 5x - 2= 3x + 7

1 - Remember, whatever you do to one side of the equation, you must do to the otherside of the equation. We want to get rid of the -2. In order to do this we can add 2. This is because -2 + 2 = 0. 

5x - 2= 3x + 7

ADD 2                  (5x - 2 + 2 = 3x + 7 +2)

5x = 3x +9

Now we need to get the x's on the same side, let's say the left hand side. In order to do this, we subtract 3x.

5x = 3x +9

SUBTRACT 3x            (5x - 3x = 3x - 3x + 9)

2x = 9

2 - We now have the x's on one side and the numbers on the other. We next need to simplify so we can get x on its own. To do this we can divide by 2 because 2x/2 = x

2x = 9

DIVIDE BY 2             (2x/2 = 9/2)

x = 4.5

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3 months ago

103 views

Solve this inequality 4y - 3 ≥ 5

1 - We treat an inequality sign like an equals sign (unless we divide by a negative number). 2 - Rearrange the inequality to get all the ys on one side and all the numbers on the other side. 3 - Simplify to get 1 y. 4y - 3 ≥ 5 ADD 3                 (4y - 3 + 3 ≥ 5 + 3) 4y ≥ 8 DIVIDE BY 4 ...

1 - We treat an inequality sign like an equals sign (unless we divide by a negative number).

2 - Rearrange the inequality to get all the ys on one side and all the numbers on the other side.

3 - Simplify to get 1 y.

4y - 3 ≥ 5

ADD 3                 (4y - 3 + 3 ≥ 5 + 3)

4y ≥ 8

DIVIDE BY 4        (4y/4 ≥ 8/4)

y ≥ 2

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3 months ago

121 views
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