I am a student at the London School of Economics (LSE) studying Management, and I'm offering tutorials in IB Mathematics and IB Economics, both of which I took at the higher level (HL).
Who Am I: My name is Sanveer, but you can call me Sunny. I have Indian origins, but I grew up in Switzerland, where I lived for 14 years before moving to the UK. My passions include basketball and music. I am a student studying Management at the London School of Economics (LSE), and I'm offering tutorials in IB Mathematics and IB Economics, both of which I took at the higher level.
Patience, a necessary trait for a teacher to have, is certainly something I feel I offer as a tutor. I tutored other students in my last two years of high school, so I have some experience in teaching. One of the reasons I enjoy tutoring is that it allows me to stay refreshed on subjects that I am passionate about.
The Sessions: My goal as a tutor is to guide you to solve problems rather than to tell you the answer. In addition, I feel it's important that you are confident in your understanding of basic concepts before jumping directly into exam-style questions. If you are a student that learns better under more structure, we can set goals that we aim to reach by the end of each session (e.g., I want to understand how to factorise quadratic functions). As a student myself, I hope I can also pass on some of the tips and tricks that I have used in order to more easily grasp tricky concepts.
Feel free to contact me with any questions you may have! I look forward to meeting you!
|International Baccalaureate||Baccalaureate||41 points|
|IB Mathematics HL||Advanced Higher||6|
|IB Economics HL||Advanced Higher||7|
|IB German B HL||Advanced Higher||7|
|IB Chemistry SL||Higher||7|
|IB Physics SL||Higher||7|
|IB English Language & Literature SL||Higher||6|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Saleem (Parent) November 9 2016
Saleem (Parent) December 1 2016
Saleem (Parent) November 23 2016
Haadiya (Student) November 6 2016
The key to solving this equation is realizing that sin(2x) can be written in terms of sin(x) and cos(x) using a double-angle formula. (With trigonometric problems similar to this one, you should always check if any trigonometric identites like the double-angle formulae can be used, as these can often help you.)
Using your IB formula booklet, you will see that the double-angle formula for sine is:
sin(2x) = 2sin(x)cos(x)
Therefore, we can rewrite the given equation from:
2cos(x) = sin(2x)
2cos(x) = 2sin(x)cos(x)
Next, we notice that both sides of the equation are multiplied by 2, so we can divide both sides by 2. This yields the equation:
cos(x) = sin(x)cos(x)
We can now divide both sides of the equation by cos(x), which leaves us with:
sin(x) = 1
Finally, we must think about the angles at which sin(x) is equal to 1. You should realize, perhaps by imagining the unit circle, that sine is equal to 1 whenever x = π/2 + n2π, where n is any integer.
However, this is not the final answer, as the problem gave us a restricted domain for x. x must be in between 0 and 3π. Therefore, the only possible values for x are π/2 and 5π/2.
So, the answer is:
x = π/2 and 5π/2see more