Who Am I: My name is Sanveer, but you can call me Sunny. I have Indian origins, but I grew up in Switzerland, where I lived for 14 years before moving to the UK. My passions include basketball and music. I am a student studying Management at the London School of Economics (LSE), and I'm offering tutorials in IB Mathematics and IB Economics, both of which I took at the higher level.
Patience, a necessary trait for a teacher to have, is certainly something I feel I offer as a tutor. I tutored other students in my last two years of high school, so I have some experience in teaching. One of the reasons I enjoy tutoring is that it allows me to stay refreshed on subjects that I am passionate about.
The Sessions: My goal as a tutor is to guide you to solve problems rather than to tell you the answer. In addition, I feel it's important that you are confident in your understanding of basic concepts before jumping directly into exam-style questions. If you are a student that learns better under more structure, we can set goals that we aim to reach by the end of each session (e.g., I want to understand how to factorise quadratic functions). As a student myself, I hope I can also pass on some of the tips and tricks that I have used in order to more easily grasp tricky concepts.
Feel free to contact me with any questions you may have! I look forward to meeting you!
|International Baccalaureate||Baccalaureate||41 points|
|IB Mathematics HL||Advanced Higher||6|
|IB Economics HL||Advanced Higher||7|
|IB German B HL||Advanced Higher||7|
|IB Chemistry SL||Higher||7|
|IB Physics SL||Higher||7|
|IB English Language & Literature SL||Higher||6|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Saleem (Parent) October 19 2016
Haadiya (Student) October 19 2016
The key to solving this equation is realizing that sin(2x) can be written in terms of sin(x) and cos(x) using a double-angle formula. (With trigonometric problems similar to this one, you should always check if any trigonometric identites like the double-angle formulae can be used, as these can often help you.)
Using your IB formula booklet, you will see that the double-angle formula for sine is:
sin(2x) = 2sin(x)cos(x)
Therefore, we can rewrite the given equation from:
2cos(x) = sin(2x)
2cos(x) = 2sin(x)cos(x)
Next, we notice that both sides of the equation are multiplied by 2, so we can divide both sides by 2. This yields the equation:
cos(x) = sin(x)cos(x)
We can now divide both sides of the equation by cos(x), which leaves us with:
sin(x) = 1
Finally, we must think about the angles at which sin(x) is equal to 1. You should realize, perhaps by imagining the unit circle, that sine is equal to 1 whenever x = π/2 + n2π, where n is any integer.
However, this is not the final answer, as the problem gave us a restricted domain for x. x must be in between 0 and 3π. Therefore, the only possible values for x are π/2 and 5π/2.
So, the answer is:
x = π/2 and 5π/2see more