Rosemary T. A Level Maths tutor, GCSE Maths tutor, A Level Physics tu...
£20 - £22 /hr

Rosemary T.

Degree: Physics (Masters) - Durham University

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About me

Hello,  I'm Rosemary, a third-year Physics student with five years' experience in tutoring, first through a school mentoring scheme and then through my University's one-to-one tutoring project, and of course mytutor! I like to use analogies to help students understand concepts, as well as encouraging students to be able to think for themselves about how to tackle problems after a bit of guidance. I aim to produce those lightbulb moments when something that was tricky clicks :)  I like to think I am patient and will tailor the teaching to each indiviual, so the more you can tell me about what you're struggling with, the better! For me, seeing someone make progress because of my contribution is very rewarding so I really hope I can help you better understand, and also enjoy, science and maths!

About my sessions

I like to be flexible with the structure of my lessons, as different styles work for different people - but I've found it can be helpful to agree a certain topic to focus on beforehand so I can prepare and teach for the first half or so of the session, and follow that with relevant questions to gain confidence in applying the concepts we've talked about. Of course nearer to exams, going through any past paper questions you've found difficult is also a useful way to target areas you need more confidence with.

Subjects offered

SubjectQualificationPrices
Maths A Level £22 /hr
Physics A Level £22 /hr
Maths GCSE £20 /hr
Physics GCSE £20 /hr

Qualifications

SubjectQualificationLevelGrade
MathsA-levelA*
PhysicsA-levelA*
Further MathsA-levelA
ChemistryA-levelA*
Disclosure and Barring Service

CRB/DBS Standard

14/11/2014

CRB/DBS Enhanced

No

General Availability

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Ratings and reviews

5from 6 customer reviews

Abdul (Parent) November 30 2016

Rosemary is engaging, highly adept and distills complicated subject matters into simple bite size components.

Elaine (Parent) July 18 2017

Emma (Student) January 27 2017

Emma (Parent) October 27 2016

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Questions Rosemary has answered

Can you define current, potential difference and resistance in a circuit, and give their units?

Current is the flow of charge in the circuit, a bit like the flow of water in a river, and is measured inAmps (A). Potential difference is defined as the 'work done per unit charge', which is related to the voltage across (and so the energy supplied to) a component in the circuit. It's measur...

Current is the flow of charge in the circuit, a bit like the flow of water in a river, and is measured in Amps (A).

Potential difference is defined as the 'work done per unit charge', which is related to the voltage across (and so the energy supplied to) a component in the circuit. It's measured in Volts, (V).

Resistance is the quantity that describes how difficult it is for a current to flow in a circuit (think of traffic trying to get through a narrow tunnel vs a motorway), and is measured in Ohms, (Ω).

Bonus: do you know the relation between these three quantities? 

A: it's called Ohm's law, and it states that R=V/I, or resistance is potential difference divided by current.

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10 months ago

461 views

Use the chain rule to differentiate y=(x-3)^(-3)

Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dx So we just need to find dy/du and du/dx! In this case u(x)=x-3, so du/dx = 1. from y=u^(-3), dy/du = -3u^(-4). This means we know dy/dx = -3u^(-4) * 1 Converting from u to x, we get dy/dx = -3 (x-3)...

Hint: the chain rule states that for y=u(x) ^a, the derivative will be dy/dx = dy/du * du/dx

So we just need to find dy/du and du/dx!

In this case u(x)=x-3, so du/dx = 1.

from y=u^(-3), dy/du = -3u^(-4).

This means we know dy/dx = -3u^(-4) * 1

Converting from u to x, we get dy/dx = -3 (x-3)^(-4)  .... done! 

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10 months ago

442 views
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