James K. IB Business Studies tutor, A Level Business Studies tutor, G...
£18 - £20 /hr

James K.

Degree: Law with Accounting and Finance (Bachelors) - Liverpool University

MyTutor guarantee

Contact James
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact James

About me

About Me:

I am currently studying Law with Accounting and Finance (LLB Hons) at the University of Liverpool. I have always had a real passion and love for Maths, Economics, Business and reccently discovered Law and hope that my tutorials will instill that love in you, too.

I am very patient and friendly. I have been teaching sport since I was 15, so have a lot of experience teaching, with people as young as 5 years old. Throghout sixth form and university I have mentored and tutor a variety of students in Maths, Economics and Business.

The Sessions:

During the sessions, you will guide what we cover. In all my subjects basic understanding is key, so before we do exam questions, we will focus on this.

I will use as many different ways (diagrams, words, analogies) as possible to explain a concept, until you are confident enough that you can explain it to me (or anyone else... the cat... the goldfish...)

I hope the sessions will be fun! A lot can be achieved in 55mins especially if it is made enjoyable - science is amazing and hopefully, if you didn’t think that before, you will by the end of the session!

What next?

If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session'! (both accessible through this website). Remember to tell me your exam board and what you're struggling with.

I look forward to meeting you!

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Business Studies GCSE £18 /hr
Law GCSE £18 /hr
Maths GCSE £18 /hr
Maths 13 Plus £18 /hr
Maths 11 Plus £18 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA
General StudiesA-LevelB
Economics and BusinessA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

General Availability

Weeks availability
MonTueWedThuFriSatSun
Weeks availability
Before 12pm12pm - 5pmAfter 5pm
MONDAYMONDAY
TUESDAYTUESDAY
WEDNESDAYWEDNESDAY
THURSDAYTHURSDAY
FRIDAYFRIDAY
SATURDAYSATURDAY
SUNDAYSUNDAY

Please get in touch for more detailed availability

Questions James has answered

A group of 120 Year 4s and Year 5s are going on a school trip. 60% of the children going on the trip are Year 4s, and of the Years 4s, 1/4 are boys. How many Year 4 girls are going on the trip?

There are quite a few stages to this problem, so let's work through each piece of information one by one. We know that the total number of children is 120, and 60% are Year 4s. Finding 60% straight away can be tricky so we should find 10% first. To find 10%, we just divide 120 by 10, which gi...

There are quite a few stages to this problem, so let's work through each piece of information one by one.

We know that the total number of children is 120, and 60% are Year 4s. Finding 60% straight away can be tricky so we should find 10% first.

To find 10%, we just divide 120 by 10, which gives us 12. Now we know 12 = 10%, we need to multiply both numbers by 6 in order to find 60%. 

10% x 6 = 60%

12 x 6 = 72

So 72 students are in Year 4. 

We are told 1/4 are boys. So we need to find one quarter of the total number of students in Year 4. We do this by dividing 72 by 4. 

72 / 4 = 18

So we have 72 Year 4s, 18 of which are boys. However we want to find the girls. Therefore we take the total and subtract the number of boys:

72-18 = 54

There are 54 Year 4 girls on the trip

see more

1 month ago

36 views

Find the equation of the line passing through the point ( 2, −3) which is parallel to the line with equation y + 4x = 7

First we rearrange the equation y + 4x = 7     to      y = −4x + 7 So we can see that the gradient of this equation is −4. Since the line we are looking for is parallel, it must have the same gradient, −4. So now we know we have a line for equation: y = −4x + m which passes through the poi...

First we rearrange the equation

y + 4x = 7     to      y = −4x + 7

So we can see that the gradient of this equation is −4.

Since the line we are looking for is parallel, it must have the same gradient, −4.

So now we know we have a line for equation:

= −4x + m

which passes through the point ( 2, −3).

We can set the values into the equation to find m:

−3 = −4 x 2 + m

−3 = −8 + m               

Now we add 8 to both sides

5 = m

So we see that the value of m is 5 and the equation we are looking for is:

= −4x + 5

see more

1 month ago

46 views

What are the advantages of doing business as a sole trader?

In answering this question, a few things must be taken into consideration. FIrstly, the question clearly asks for the advantages of being a sole trader. This means that any time wasted in explaining a disadvantage of this will gain no marks. The marks allocated to the question give an idea of ...

In answering this question, a few things must be taken into consideration. FIrstly, the question clearly asks for the advantages of being a sole trader. This means that any time wasted in explaining a disadvantage of this will gain no marks. The marks allocated to the question give an idea of how many advantages you may need to put across. If this question was for 8 marks, you would probably need to explain in detail about 4 advantages. An evaluation point may help at the end of your response.

see more

1 month ago

49 views
See all answers
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact James

Still comparing tutors?

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

Cookies:

We use cookies to improve our service. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok