Currently unavailable: for new students

Degree: Mathematics (Bachelors) - Warwick University

MyTutor guarantee

Me:

I am a second year maths student at Warwick University. I have always loved maths and very much enjoy finding solutions for problems and also alternative ways to approach them.

I am a calm individual who has helped a number of students both peers and those younger than me with maths at varying levels. The joy from helping people understand and learn is something I have found I enjoy immensely.

What I will do:

My aim is to help you understand the subject and therefore improve your confidence and skill with it, ultimately this will help with exams and also whatever comes after. My hope is that after each session you will come out with a greater enjoyment and understanding and if you have any suggestions on things that work better for you I will glady listen.

What should you do:

If you have any questions just send me a message via 'Webmail' or book a 'Meet the Tutor session' and I will do my best to answer them fully.

Hopefully hear from you soon.

#### Subjects offered

SubjectQualificationPrices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Maths GCSE £18 /hr

#### Qualifications

MathematicsA-levelA2A*
Further MathematicsA-levelA2A*
PhysicsA-levelA2A
ChemistryA-levelA2A
 CRB/DBS Standard No CRB/DBS Enhanced No

#### General Availability

Currently unavailable: for new students

Weeks availability
MonTueWedThuFriSatSun
Weeks availability
Before 12pm12pm - 5pmAfter 5pm
MONDAY
TUESDAY
WEDNESDAY
THURSDAY
FRIDAY
SATURDAY
SUNDAY

Please get in touch for more detailed availability

### Find the set of values for which: 3/(x+3) >(x-4)/x

First we must consider for which values of x the equation: 3/(x+3) = (x-4)/x is undefined. In this case, x=-3, and x=0.  Now we must consider each of the cases, x<-3, -3 Case 1 (x<-3): if we assume 3/(x+3) > (x-4)/x then it follows, as x<-3, 3x > x2 -x-12. Which implies (x-6)(x+2) < 0. For th...

First we must consider for which values of x the equation: 3/(x+3) = (x-4)/x is undefined. In this case, x=-3, and x=0.

Now we must consider each of the cases, x<-3, -3

Case 1 (x<-3): if we assume 3/(x+3) > (x-4)/x then it follows, as x<-3, 3x > x2-x-12. Which implies (x-6)(x+2) < 0. For this to hold exactly one of (x-6) and (x+2) must be less than 0 and the other greater than 0. which implies -2

Case 2 (-32-4x-12 > 0, which implies (x-6)(x+2) >0. Therefore for x2-4x-12 > 0, either both (x-6) and (x+2) must be less than 0 or greater than 0. therefore x<-2 or x>6. Therefore as we know -3

Case 3 (x>0): Therefore x2-4x-12 < 0, which implies (x-6)(x+2) < 0. For this to hold exactly one of (x-6) and (x+2) must be less than 0 and the other greater than 0. which implies -2

Finally as we have considered all cases the final answer is -3

see more

12 months ago

417 views
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Still comparing tutors?

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this.