I am a passionate, energetic and motivating mathematics tutor. I have a strong belief that mathematics can and should be made fun, engaging and accessible for everyone! Thus, I tailor my approach to suit the student`s individual needs.
I am currently studying Mathematics at the University of Bristol.
I have also had experience with tutoring Russian Language. I have completed a native Russian GIA qualification as well as achieving an A* at Russian A Level. Russian is my native tongue.
I have experience in working with children as young as 11 all the way up to sixth form level.
I have tutored Year 11 students in their Maths and Physics GCSE, who have then gone on to achieve fantastic grades in GCSE and A Level Maths.
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A Level Maths Modules I can help you with: C1-C4, FP1, FP2, S1, S2, M1. M2, D1, DE.
|Further Mathematics||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Russian||A Level||£20 /hr|
|Further Mathematics||GCSE||£18 /hr|
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Assem (Student) October 13 2016
To differentiate this kind of expression you would need to use implicit differentiation.
Although it may sound new, you already have all the skills you need to be able to do it. We will differentiate both sides of the expression.
We will treat the x's as normal. When we encounter terms with y's in them, we will differentiate these terms and multiply each of them by 'dy/dx'.
So, it will look like this.
Differentiating both sides, we get:
No, to get the derivative, we will simply rearrange the terms, solving for dy/dx:
Hence, our soultion is dy/dx=1/(y-1).see more