Sarah W.

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Robotics (Masters) - Bristol University

5.0

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#### Ratings & Reviews

5from 27 customer reviews

November 6 2016

Great help, stays focused and is very helpful

Robert (Student)

October 23 2016

Really great tution, explains things really well.

Krishnendu (Parent from Slough)

July 26 2017

Krishnendu (Parent from Slough)

April 30 2017

#### Qualifications

Biomedical EngineeringDegree (Bachelors)A
Electrical EngineeringDegree (Bachelors)A
MathematicsA-level (A2)A*
ChemistryA-level (A2)A*
BiologyA-level (A2)A
English LiteratureA-level (A2)B

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#### Subjects offered

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### How could I write a program to convert Km/h to m/s in python

First we need to know that the conversion factor for km/h to m/s is 3.6km/h=1m/s

Next we need to read in a value from the user. This can be done with 'input' function as follows:

KMHvalue= input("Enter a value in km/h: ")

we will then need to use our conversion to convert the value into m/s

MSvalue=KHMvalue/3.6

Then we can output the answer using the 'print' function:

print("your value in m/s is: "+MSvalue)

hence the whole program is:

KMHvalue= input("Enter a value in km/h: ")
MSvalue=KHMvalue/3.6
print("your value in m/s is: "+MSvalue)

We could make this program more sophisticated by allowing the user to select if they want to convert from km/h to m/s or the other way around. A sample script to do this would be:

choice=input("Please enter 1 to convert km/h to m/s or 2 to convert m/s to km/h")
​if choice==1
KMHvalue= input("Enter a value in km/h: ")
MSvalue=KHMvalue/3.6
print("your value in m/s is: "+MSvalue)

else if choice==2
MSvalue= input("Enter a value in m/s: ")
KMHvalue=MSvalue*3.6
print("your value in km/h is: "+KMHvalue)

else
​    print("Invalid Choice")

First we need to know that the conversion factor for km/h to m/s is 3.6km/h=1m/s

Next we need to read in a value from the user. This can be done with 'input' function as follows:

KMHvalue= input("Enter a value in km/h: ")

we will then need to use our conversion to convert the value into m/s

MSvalue=KHMvalue/3.6

Then we can output the answer using the 'print' function:

print("your value in m/s is: "+MSvalue)

hence the whole program is:

KMHvalue= input("Enter a value in km/h: ")
MSvalue=KHMvalue/3.6
print("your value in m/s is: "+MSvalue)

We could make this program more sophisticated by allowing the user to select if they want to convert from km/h to m/s or the other way around. A sample script to do this would be:

choice=input("Please enter 1 to convert km/h to m/s or 2 to convert m/s to km/h")
​if choice==1
KMHvalue= input("Enter a value in km/h: ")
MSvalue=KHMvalue/3.6
print("your value in m/s is: "+MSvalue)

else if choice==2
MSvalue= input("Enter a value in m/s: ")
KMHvalue=MSvalue*3.6
print("your value in km/h is: "+KMHvalue)

else
​    print("Invalid Choice")

2 years ago

1092 views

### How do you solve 3sin2AtanA=2 for 0<A<180?

The first step in solving any trigonometric equation is to convert everything into sine and cosine functions. So in this case we need to start by converting the tanA. We can use the identity: tanA=sinA/cosA

Hence the equation becomes:

3sin2A x sinA/cosA=2

Next we need to deal with the double angle that we have in sin2A. This time we can use the double angle rule for sine which says: sin2A=2sinAcosA. We substitute this into our equation to get:

3 x 2sinAcosA x sinA/cosA=2

We can now simplify the equation by cancelling out cosA and combining sinA:

6sin​2A=2

which we simplify further to:

sin​2​A=1/3

square rooting both sides we get:

sinA=0.5774

hence by taking the inverse of sine we get:

A=35.27 degrees

However this is only one possible solution. We need to use the general solution of sine to find all possible answers within the given angle range.

The general solution for sine is:

sin-1​=A +360k or 180-A +360k where k is an integer

A= (35.27 or  144.73) +360k

but since only 35.27 and 144.73 lie in the given range of 0

A=35.27 or 144.73

The first step in solving any trigonometric equation is to convert everything into sine and cosine functions. So in this case we need to start by converting the tanA. We can use the identity: tanA=sinA/cosA

Hence the equation becomes:

3sin2A x sinA/cosA=2

Next we need to deal with the double angle that we have in sin2A. This time we can use the double angle rule for sine which says: sin2A=2sinAcosA. We substitute this into our equation to get:

3 x 2sinAcosA x sinA/cosA=2

We can now simplify the equation by cancelling out cosA and combining sinA:

6sin​2A=2

which we simplify further to:

sin​2​A=1/3

square rooting both sides we get:

sinA=0.5774

hence by taking the inverse of sine we get:

A=35.27 degrees

However this is only one possible solution. We need to use the general solution of sine to find all possible answers within the given angle range.

The general solution for sine is:

sin-1​=A +360k or 180-A +360k where k is an integer

A= (35.27 or  144.73) +360k

but since only 35.27 and 144.73 lie in the given range of 0

A=35.27 or 144.73

2 years ago

607 views

### In the presence of ultraviolet light, ethane and chlorine react to give a mixture of products. What are the products of this reaction?

The reaction that is occuring is a substitution reaction as ethan is already a saturated molecule. The ultraviolet light provides the energy needed to break the bonds between hydrogen and carbon in ethane so that the chlorine atoms can replace the hydrogen ones.

Ethane's chemical formula is CH3CH​3 ​and since chlorine is a diatomic gas, its formula is Cl2

The equation representing this reaction is therefore:

CH​3CH​3 +Cl​2 ->CH2​ClCH2Cl+H​2

So the products of the reation are 1,2-dichloro ethane and hydrogen gas

The reaction that is occuring is a substitution reaction as ethan is already a saturated molecule. The ultraviolet light provides the energy needed to break the bonds between hydrogen and carbon in ethane so that the chlorine atoms can replace the hydrogen ones.

Ethane's chemical formula is CH3CH​3 ​and since chlorine is a diatomic gas, its formula is Cl2

The equation representing this reaction is therefore:

CH​3CH​3 +Cl​2 ->CH2​ClCH2Cl+H​2

So the products of the reation are 1,2-dichloro ethane and hydrogen gas

2 years ago

10143 views

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