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Sarah W.

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Degree: Robotics (Masters) - Bristol University

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About me

About Me:

I am currently a Masters student in Robotics at the University of Bristol. My choice of degree was based on my love for hands on science. I will try to pass on this love to you during my tutorials!

I have alot of experience with tutoring and have tutored in both classroom environments and individually for the past four years. I have taught students from primary school all the way through to first year university. I particularly specialise in the sciences (maths, physics, chamistry, biology, and electronics) as these are the subjects I have a real passion for. However duing my university years I was exposed to coding and have learnt to enjoy that too. So I offer mentoring in python and javascript as well.

The Sessions:

During the sessions we will cover what you feel you need to go over. My typical style is to start by trying to find out from you, and from doing a few questions, what it is that you have difficulty with. Once I have established this I will try to build up your understanding of the subject by using real world examples and various situations that you can relate to. For example if you love dancing then I will try and explain physics to you by relating it to certain dance moves that you do.

​My goal is to build up your confidence and inspire a love of science in you. I try to keep my tutorials fun and relevant so that you look forward to attending them.

Other Questions:

​If you have questions about applying to university, writing or preparing for entrance exams, or what courses to chose then feel free to ask me. I am on my third university degree now (for some reason I just keep coming back!) so I have tonnes of experience with the university system and should be able to give you some good advice. I am also happy to help you prepare for entrance exams.

What next?

If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session'! ). ​You can do both of these things via the mytutor website.

I look forward to meeting you!

Subjects offered

SubjectLevelMy prices
Electronics A Level £24 /hr
Maths A Level £24 /hr
Physics A Level £24 /hr
Biology GCSE £22 /hr
Chemistry GCSE £22 /hr
Electronics GCSE £22 /hr
Maths GCSE £22 /hr
Physics GCSE £22 /hr
Maths IB £24 /hr
Physics IB £24 /hr
Maths 13 Plus £22 /hr

Qualifications

QualificationLevelGrade
Biomedical EngineeringBachelors DegreeA
Electrical EngineeringBachelors DegreeA
MathematicsA-LevelA*
ChemistryA-LevelA*
BiologyA-LevelA
English LiteratureA-LevelB
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for new students

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Ratings and reviews

5from 11 customer reviews

Aadam (Student) November 6 2016

Great help, stays focused and is very helpful

Robert (Student) October 23 2016

Really great tution, explains things really well.

Carol (Parent) December 1 2016

Jamila (Parent) November 30 2016

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Questions Sarah has answered

How could I write a program to convert Km/h to m/s in python

First we need to know that the conversion factor for km/h to m/s is 3.6km/h=1m/s Next we need to read in a value from the user. This can be done with 'input' function as follows: KMHvalue= input("Enter a value in km/h: ") we will then need to use our conversion to convert the value into m/s ...

First we need to know that the conversion factor for km/h to m/s is 3.6km/h=1m/s

Next we need to read in a value from the user. This can be done with 'input' function as follows:

KMHvalue= input("Enter a value in km/h: ")

we will then need to use our conversion to convert the value into m/s

MSvalue=KHMvalue/3.6

Then we can output the answer using the 'print' function:

print("your value in m/s is: "+MSvalue)

hence the whole program is:

KMHvalue= input("Enter a value in km/h: ")
MSvalue=KHMvalue/3.6
print("your value in m/s is: "+MSvalue)

We could make this program more sophisticated by allowing the user to select if they want to convert from km/h to m/s or the other way around. A sample script to do this would be:

choice=input("Please enter 1 to convert km/h to m/s or 2 to convert m/s to km/h")
​if choice==1
    KMHvalue= input("Enter a value in km/h: ")
    MSvalue=KHMvalue/3.6
    print("your value in m/s is: "+MSvalue)

else if choice==2
    MSvalue= input("Enter a value in m/s: ")
    KMHvalue=MSvalue*3.6
    print("your value in km/h is: "+KMHvalue)

else
​    print("Invalid Choice")

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2 months ago

53 views

How do you solve 3sin2AtanA=2 for 0<A<180?

The first step in solving any trigonometric equation is to convert everything into sine and cosine functions. So in this case we need to start by converting the tanA. We can use the identity: tanA=sinA/cosA Hence the equation becomes: 3sin2A x sinA/cosA=2 Next we need to deal with the double...

The first step in solving any trigonometric equation is to convert everything into sine and cosine functions. So in this case we need to start by converting the tanA. We can use the identity: tanA=sinA/cosA

Hence the equation becomes:

3sin2A x sinA/cosA=2

Next we need to deal with the double angle that we have in sin2A. This time we can use the double angle rule for sine which says: sin2A=2sinAcosA. We substitute this into our equation to get:

3 x 2sinAcosA x sinA/cosA=2

We can now simplify the equation by cancelling out cosA and combining sinA:

6sin​2A=2

which we simplify further to:

sin​2​A=1/3

square rooting both sides we get:

sinA=0.5774

hence by taking the inverse of sine we get:

A=35.27 degrees

However this is only one possible solution. We need to use the general solution of sine to find all possible answers within the given angle range.

The general solution for sine is:

sin-1​=A +360k or 180-A +360k where k is an integer

Hence our answer becomes:

A= (35.27 or  144.73) +360k

but since only 35.27 and 144.73 lie in the given range of 0

A=35.27 or 144.73

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2 months ago

67 views

In the presence of ultraviolet light, ethane and chlorine react to give a mixture of products. What are the products of this reaction?

The reaction that is occuring is a substitution reaction as ethan is already a saturated molecule. The ultraviolet light provides the energy needed to break the bonds between hydrogen and carbon in ethane so that the chlorine atoms can replace the hydrogen ones. Ethane's chemical formula is C...

The reaction that is occuring is a substitution reaction as ethan is already a saturated molecule. The ultraviolet light provides the energy needed to break the bonds between hydrogen and carbon in ethane so that the chlorine atoms can replace the hydrogen ones.

Ethane's chemical formula is CH3CH​3 ​and since chlorine is a diatomic gas, its formula is Cl2

The equation representing this reaction is therefore:

CH​3CH​3 +Cl​2 ->CH2​ClCH2Cl+H​2

So the products of the reation are 1,2-dichloro ethane and hydrogen gas

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2 months ago

68 views
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