Tilly P. GCSE Maths tutor, GCSE Computing tutor

Tilly P.

Currently unavailable: for regular students

Degree: Computer Science and Mathematics (Bachelors) - Exeter University

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About me

I'm happy to take on extra people over christmas, whether for a one off class or multiple throughout the holidays! Though I'm not taking on any new long term students right now.

About Me:

I'm a Maths and Computer Science student at the university of Exeter. I've always enjoyed maths and I really want to help others enjoy it too!

I have a lot of experience in helping out with younger students as I've taken part in Buddy programmes and maths help schemes as well as other things during my GCSEs and Alevels.

Our time together

I believe that it's super important that you develop a full understanding on the things that you struggle with at school. So I'm here to help explain things to you! Whether through analogies, diagrams or songs (though please not I'm not a singing teacher!), I'll patiently help you reach your targets.

There is a lot we can do in a small amount of time, and so if you have topics you're struggling with then I can help you out! If you're not sure what your weak points are then I can help you figure those out too. It's totally up to you how we spend our time as I just want you to become confident and happy in your subject of choice.

If you have any questions please send me a message! I hope to see you soon!

Subjects offered

SubjectLevelMy prices
Computing GCSE £18 /hr
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA
Further MathsA-LevelB
Computer ScienceA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for regular students

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

5from 1 customer review

Nicola (Parent) December 1 2016

Questions Tilly has answered

if x^2 + 9x + 20 = 0, what are the possible values of x?

So x2 + 9x + 20 = 0 My preffered way of solving this equation is to factorise the equation. (Though I understand that different students may find other ways easier)  Factorisation is where the above equation is (x+a)(x+b) = 0 So if we times out (x+a)(x+b) we get x2 + ax + bx + ab = 0 therefo...

So x2 + 9x + 20 = 0

My preffered way of solving this equation is to factorise the equation. (Though I understand that different students may find other ways easier) 

Factorisation is where the above equation is (x+a)(x+b) = 0

So if we times out (x+a)(x+b) we get

x2 + ax + bx + ab = 0
therefore
x2 + (a+b)x + ab = 0

Therefore we can equate this to the original question, so
x2 + 9x + 20 = x2 + (a+b)x + ab

so now we can see that
9 = a + b and
20 = ab

I would reccomend using trial and error (although I understand that different students may prefer other techniques).

So by trying for multiple values of a and b, we can see that they must equal 5 and 4.

Therefore
x2 + 9x + 20 = (x+5)(x+4) = 0

We know that the only way of producing a 0 through multiplication is through multiplying one number by another. Therefore we know that

x+5= 0 or x+4=0

Through rearranging these equations we can conclude that x must equal -4 or -5.
 

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2 months ago

63 views
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