Emily-Louisa S. A Level Maths tutor, A Level Further Mathematics  tutor

Emily-Louisa S.

Currently unavailable: for new students

Degree: Mathematics (Masters) - Exeter University

MyTutor guarantee

Contact Emily-Louisa
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Emily-Louisa

About me

I am in my first year of my mathematics degree at the University of Exeter and one of my favourite things about maths is how it can appear in unexpected situations. For example, in cryptography (the writing and solving of codes of which the strongest use more maths than you may realise) are used in the decipherment of ancient languages, such as the ones present on the Rosetta stone (a rock found in Eqypt where the Greek inscriptions were used to decipher the hieroglyphs). Cryptography also played a major role in the World Wars; a famous example is the enigma machine.

One of my favourite books on this topic which is suitable for whatever your level of maths may be is Simon Singh's 'The Code Book'. I read this book in my first year of A-levels and it is the book which developed my interest further in the applications of maths. I also recommend any of Simon Singh's books.

These constant links that maths has with everything around us is one of the things I love so much about it. Maths makes me question things around me and sometimes an answer to one question just leads to so many more, but the more questions there are, the more beautiful maths becomes.

My strongest area of maths is algebra and I especially enjoy pure maths ( I studied FP1 & FP2 at A-level). My weakest areas are statistics and decision maths.

In my A-levels I got 100% in C2, C3 and C4. The exam board I was taught was OCR.

I would be happy to tutor you in C1, C2, C3, C4 and FP1.

Through my tutorials with you I hope to develop your understanding, interest and confidence in maths.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA*
ChemistryA-LevelB
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

Currently unavailable: for new students

General Availability

Weeks availability
MonTueWedThuFriSatSun
Weeks availability
Before 12pm12pm - 5pmAfter 5pm
MONDAYMONDAY
TUESDAYTUESDAY
WEDNESDAYWEDNESDAY
THURSDAYTHURSDAY
FRIDAYFRIDAY
SATURDAYSATURDAY
SUNDAYSUNDAY

Please get in touch for more detailed availability

Questions Emily-Louisa has answered

Given that f(x)=2sinhx+3coshx, solve the equation f(x)=5 giving your answers exactly.

Firstly set 2sinhx+3coshx=5 Now using the exponential definitions of sinhx and coshx rewrite the equation to give: 2(1/2(e^x-e^-x))+3(1/2(e^x+e^-x))=5 Simplify the equation by expanding out the brackets, multipling by 2 to eliminate fractions and collecting like terms together, as so: e^x-e...

Firstly set 2sinhx+3coshx=5

Now using the exponential definitions of sinhx and coshx rewrite the equation to give:

2(1/2(e^x-e^-x))+3(1/2(e^x+e^-x))=5

Simplify the equation by expanding out the brackets, multipling by 2 to eliminate fractions and collecting like terms together, as so:

e^x-e^-x+3/2e^x+3/2e^-x=5

2e^x-2e^-x+3e^x+3e^-x=10

5e^x+e^-x=10

5e^x+e^-x-10=0

e^-x is equivalent to 1/e^x therefore multiply through by e^x to get a quadratic equation in e^x

5e^2x-10e^x+1=0

Now using the quadratic equation (where a=5, b=-10 and c=1) solve for e^x

I will indicate 'plus or minus' by +/- (not to be confused with plus, divide, minus)

e^x=(-(-10)+/-√(-10)^2-4(5)(1))/2(5)

e^x=(10+/-√80)/10

e^x=1+/-(2√5)/5

To solve for x you must take the natural logarithm of both sides as (ln^e=1) so

x=ln(1+(2√5)/5

or

x=ln(1-(2√5)/5)

see more

2 months ago

64 views

Integrate 1/(5-2x) for 3≤x≤4

You must be careful with these sorts of questions as although 1/(5-2x) is equivalent to (5-2x)^-1, when you integrate you would add one to the power and divide by the new power. But if you were to add one to (5-2x)^-1 you would get zero. Therefore, when you are integrating a fraction with a li...

You must be careful with these sorts of questions as although 1/(5-2x) is equivalent to (5-2x)^-1, when you integrate you would add one to the power and divide by the new power. But if you were to add one to (5-2x)^-1 you would get zero. Therefore, when you are integrating a fraction with a linear expression as the denominator (meaning a denominator where the greatest power of x is 1), it integrates to the natural logarithm (ln) of the denominator, multiplied by the differential of the denominator.

So in this example, 1/(5-2x) would integrate to

[ln(5-2x)/(-2)] (as 5-2x differentiates to -2) for 3≤x≤4

Then you would sub in the limits of x and subtract as usual:

ln(5-2(4))/(-2) - ln(5-2(3))/(-2)

= -1/2ln(5-8) - -1/2ln(5-6) 

Remeber that you cannot take the ln of a negative number, so it is best to write it as: 

= -1/2ln|-3| - -1/2ln|-1|

= -1/2ln(3) - -1/2ln(1)

ln(1)=0 so our answer is

-1/2ln3

  

see more

2 months ago

50 views
Send a message

All contact details will be kept confidential.

To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Emily-Louisa

Still comparing tutors?

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

Cookies:

We use cookies to improve our service. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok