Chloe H. A Level Maths tutor, GCSE Maths tutor
£18 - £20 /hr

Chloe H.

Degree: Mathematics (Bachelors) - Warwick University

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About me

Hi there! My name is Chloe, I'm doing maths at the University of Warwick. 

I love maths and I have a passion for helping other people understand it. I have previously tutored GCSE students as well as students in lower years. I am friendly and easy going and our sessions will be dictated by you! 

Subjects offered

SubjectLevelMy prices
Maths A Level £20 /hr
Maths GCSE £18 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
Further MathematicsA-LevelA*
ChemistryA-LevelA*
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

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Questions Chloe has answered

Differentiate y^3 + 3y^2 + 5

When you differentiate, you multiply by the old power and decrease the power by 1. If the expression has a constant in it, this differentiates to 0.  So the answer is 3y^(3-1) + (3x2)y^(2-1) + 0 = 3y^2 +6y

When you differentiate, you multiply by the old power and decrease the power by 1. If the expression has a constant in it, this differentiates to 0. 

So the answer is 3y^(3-1) + (3x2)y^(2-1) + 0 = 3y^2 +6y

2 months ago

72 views

Factorise x^2 + 3x +2

You want two numbers that multiply to give 2 and add to give 3. Looking at factors is always easiest, so start by listing pairs of numbers that multiply together to give 2. There are only two such pairs, 1x2 and (-1)x(-2). The only pair that add together to make 3 is +1+2=3. So the answer is ...

You want two numbers that multiply to give 2 and add to give 3. Looking at factors is always easiest, so start by listing pairs of numbers that multiply together to give 2. There are only two such pairs, 1x2 and (-1)x(-2). The only pair that add together to make 3 is +1+2=3.

So the answer is (x+1)(x+2) 

see more

2 months ago

68 views
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