Chloe H. A Level Maths tutor, GCSE Maths tutor

Chloe H.

Unavailable

Mathematics (Bachelors) - Warwick University

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About me

Hi there! My name is Chloe, I'm doing maths at the University of Warwick. 

I love maths and I have a passion for helping other people understand it. I have previously tutored GCSE students as well as students in lower years. I am friendly and easy going and our sessions will be dictated by you! 

Hi there! My name is Chloe, I'm doing maths at the University of Warwick. 

I love maths and I have a passion for helping other people understand it. I have previously tutored GCSE students as well as students in lower years. I am friendly and easy going and our sessions will be dictated by you! 

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A*
ChemistryA-level (A2)A*

General Availability

Pre 12pm12-5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
MathsA Level£20 /hr
MathsGCSE£18 /hr

Questions Chloe has answered

Differentiate y^3 + 3y^2 + 5

When you differentiate, you multiply by the old power and decrease the power by 1. If the expression has a constant in it, this differentiates to 0. 

So the answer is 3y^(3-1) + (3x2)y^(2-1) + 0 = 3y^2 +6y

When you differentiate, you multiply by the old power and decrease the power by 1. If the expression has a constant in it, this differentiates to 0. 

So the answer is 3y^(3-1) + (3x2)y^(2-1) + 0 = 3y^2 +6y

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2 years ago

552 views

Factorise x^2 + 3x +2

You want two numbers that multiply to give 2 and add to give 3. Looking at factors is always easiest, so start by listing pairs of numbers that multiply together to give 2. There are only two such pairs, 1x2 and (-1)x(-2). The only pair that add together to make 3 is +1+2=3.

So the answer is (x+1)(x+2) 

You want two numbers that multiply to give 2 and add to give 3. Looking at factors is always easiest, so start by listing pairs of numbers that multiply together to give 2. There are only two such pairs, 1x2 and (-1)x(-2). The only pair that add together to make 3 is +1+2=3.

So the answer is (x+1)(x+2) 

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2 years ago

549 views

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