Currently unavailable: until 19/12/2016
Degree: Physics and Computer Science (Natural Sciences) (Masters) - Durham University
I'm a Physics and Computer Science student at Durham University, which sounds boring but it's actually really fun. I've got a great knack for making boring things more exciting, which is a good job given my degree title!
I've been tutoring GCSE and A-level for 4 years now, so I know a thing or two about communicating in a way that gets the most out of you or your child! I'm very patient, honest and friendly, and I genuinely enjoy helping others get on the road to success.
What Can I Teach?:
I've got great experience in almost all GCSE subjects, but I specialise in Mathematics and Science, both of which I frequently tutor at A-level as well.
On top of this, I'm a bit of a wizz in several programming languages, feel free to ask a little more if you're into that kind of thing!
I'm very familiar with what it's like going through various application processess and I'd be more than happy to help with a science-based Personal Statement as well as strive to help with any other application-based concerns you might have.
How Do I Teach?
Everybody's different and likes to learn at their own rate. I plan lessons around you, so whether it's understanding or exam technique that you struggle with, I'll pick up on it and we'll focus on that.
I often find that in exams, confidence is key. Getting the right knowledge combined with a good exam technique really helps to settle those all too familiar pre-exam nerves, giving you the best possible chance to achieve what you want.
Any questions? Drop me a message on the site or book a meeting and I'd only be too happy to help.
I look forward to seeing you soon!
|Maths||A Level||£22 /hr|
|Physics||A Level||£22 /hr|
|Maths||13 Plus||£20 /hr|
|Science||13 Plus||£20 /hr|
|Maths||11 Plus||£20 /hr|
|-Personal Statements-||Mentoring||£22 /hr|
|Physics and Computer Science||Masters Degree||2.1|
|Extended Project Qualification||A-Level||A*|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Algebra is the enemy of many a student, but I'm here to show you that this (and many more concepts in maths!) really aren't that bad.
For this problem, we need to group all of the like terms together, that is terms in the equation that take the same form, or look like each other.
In this example, we have 4x on one side, and -5x on the other side. These can be simplified by, say, adding 5x to both sides. You can do this in maths, so long as you do the same thing to both sides.
We see that if we add 5x to both sides, we get 9x on the left hand side (lhs) of the equals, and 0x on the right hand side (rhs) of the equals. Anything times 0 is 0, so 0x disappears from the rhs of the equation.
We're left with 9x + 2 = 20. Now we simplify further, by getting all the 'x' terms on one side, and all the numbers on the other. We can do this in the same way as before by subtracting 2 from both sides, to get 9x = 18.
Now, we know that '9 times x' equals '18', but we want to know what 1 x is. To do this, we can divide both sides by 9. Doing this gives '9/9 times x' on the lhs and '18/9' on the rhs. Knowing that 9/9 = 1 and 18/9 is 2, we can see here that the solution simplifies to:
x = 2
Which is the answer. Learn the answer to this and more with me!see more