George I. 13 Plus  Maths tutor, A Level Maths tutor, GCSE Maths tutor...

George I.

£18 - £20 /hr

Currently unavailable: for regular students

Studying: Electrical and Electronic Engineering (Masters) - Bristol University

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About me

About Me: I am currently a third year Electrical and Electronic engineering undergraduate at the University of Bristol. I have always enjoyed taking mathematics and further mathematics as I look forward to tackling problems with numerical reasoning and logical explanations. I am very cordial and patient. I believe in understanding fundamentals first then applying it to harder examples and pragmatic situations. My Grades A Level Mathematics  - A* Further Mathematics - A Physics - BAbout Me: I am currently a third year Electrical and Electronic engineering undergraduate at the University of Bristol. I have always enjoyed taking mathematics and further mathematics as I look forward to tackling problems with numerical reasoning and logical explanations. I am very cordial and patient. I believe in understanding fundamentals first then applying it to harder examples and pragmatic situations. My Grades A Level Mathematics  - A* Further Mathematics - A Physics - B

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Qualifications

SubjectQualificationGrade
MathematicsA-level (A2)A*
Further MathematicsA-level (A2)A
PhysicsA-level (A2)B

General Availability

Before 12pm12pm - 5pmAfter 5pm
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sundays

Subjects offered

SubjectQualificationPrices
Further MathematicsA Level£20 /hr
MathsA Level£20 /hr
Further MathematicsGCSE£18 /hr
MathsGCSE£18 /hr
Maths13 Plus£18 /hr
Maths11 Plus£18 /hr

Questions George has answered

if y = (e^x)^7 find dy/dx

To solve the the problem we need to recognize what type of differentiation technique we shall be employing

y = (ex)7

the x unction which we are diferentiating is a power of an exponential function therefore we must employ a substituion method to solve this

if u = ex

therefore y = (u)7

dy/du = 7(u)6

we can say du/dx = ex

therefore dy/dx = dy/du  * du/dx

dy/dx = 7(ex)6 * ex

dy/dx = 7(ex)6​ * ex

dy/dx = 7(ex)7​

To solve the the problem we need to recognize what type of differentiation technique we shall be employing

y = (ex)7

the x unction which we are diferentiating is a power of an exponential function therefore we must employ a substituion method to solve this

if u = ex

therefore y = (u)7

dy/du = 7(u)6

we can say du/dx = ex

therefore dy/dx = dy/du  * du/dx

dy/dx = 7(ex)6 * ex

dy/dx = 7(ex)6​ * ex

dy/dx = 7(ex)7​

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1 year ago

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