Maisie J. A Level Maths tutor, GCSE Maths tutor, A Level Further Math...

Maisie J.

£18 - £20 /hr

Currently unavailable: for regular students

Studying: Mathematics (G100) (Bachelors) - Warwick University

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About me

Hi! My name is Maisie and I'm studying Mathematics at Warwick University. My aim is to share my passion of maths with my students and to boost my students' self-confidence and self-esteem.  I am friendly, patient and I will adapt the sessions to fit the individual students needs. The sessions will be a fun and interesting learning experience and questions and discussions are very much encouraged! If you have any questions feel free to send me a message or book a 'Meet the Tutor Session'. Remember to include your exam board and details of what bits you're struggling with the most. I look forward to meeting you!Hi! My name is Maisie and I'm studying Mathematics at Warwick University. My aim is to share my passion of maths with my students and to boost my students' self-confidence and self-esteem.  I am friendly, patient and I will adapt the sessions to fit the individual students needs. The sessions will be a fun and interesting learning experience and questions and discussions are very much encouraged! If you have any questions feel free to send me a message or book a 'Meet the Tutor Session'. Remember to include your exam board and details of what bits you're struggling with the most. I look forward to meeting you!

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A*
Further MathsA-level (A2)A*
PhysicsA-level (A2)A*

General Availability

Before 12pm12pm - 5pmAfter 5pm
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tuesdays
wednesdays
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fridays
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sundays

Subjects offered

SubjectQualificationPrices
Further Mathematics A Level£20 /hr
MathsA Level£20 /hr
Further Mathematics GCSE£18 /hr
MathsGCSE£18 /hr

Questions Maisie has answered

Factorise and solve: x^2 - 8x = -15

Step 1: The first step is to rewrite the equation in the form ax2 bx + c = 0. So in this case, we achieve this by adding 15 to both sides:    x2 - 8x + 15 = -15 + 15
                                          x- 8x + 15 = 0

Step 2: Now we need to factorise the equation. To factorise this equation we start with finding two numbers which add up to -8 and multiply to make 15. These numbers must be -5 and -3. So the factorisation of this equation is:                       (x - 5)(x - 3) = 0

Step 3: Finally, we can solve by saying:          
                                           x - 5 = 0 or  x - 3 = 0, so
                                           x = 5 or x = 3  

CHECK:  You can check your two answers, 5 and 3, by subsituting them into the orginal equation, x- 8x = -15.
So firstly for x = 5:              (5)2 - 8(5) =  -15
                                           25   - 40   =  -15
                                                   -15   =  -15 which is clearly true, so we have confirmed that x = 5 is a solution.
We can proceed in exactly the same way for x = 3, and if you try it you will find that it works out and we can confirm that x = 3 is a solution too. 

NEAT ANSWER: Here is an example what you should write in the exam to get full marks:
                                          x2 - 8x = -15
                                          x2 - 8x + 15 = 0
                                         (x - 5)(x - 3) = 0 
                                         So, x = 5 or x = 3

 

Step 1: The first step is to rewrite the equation in the form ax2 bx + c = 0. So in this case, we achieve this by adding 15 to both sides:    x2 - 8x + 15 = -15 + 15
                                          x- 8x + 15 = 0

Step 2: Now we need to factorise the equation. To factorise this equation we start with finding two numbers which add up to -8 and multiply to make 15. These numbers must be -5 and -3. So the factorisation of this equation is:                       (x - 5)(x - 3) = 0

Step 3: Finally, we can solve by saying:          
                                           x - 5 = 0 or  x - 3 = 0, so
                                           x = 5 or x = 3  

CHECK:  You can check your two answers, 5 and 3, by subsituting them into the orginal equation, x- 8x = -15.
So firstly for x = 5:              (5)2 - 8(5) =  -15
                                           25   - 40   =  -15
                                                   -15   =  -15 which is clearly true, so we have confirmed that x = 5 is a solution.
We can proceed in exactly the same way for x = 3, and if you try it you will find that it works out and we can confirm that x = 3 is a solution too. 

NEAT ANSWER: Here is an example what you should write in the exam to get full marks:
                                          x2 - 8x = -15
                                          x2 - 8x + 15 = 0
                                         (x - 5)(x - 3) = 0 
                                         So, x = 5 or x = 3

 

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12 months ago

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