Ben B. A Level Maths tutor, A Level Further Mathematics  tutor, A Lev...

Ben B.

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Degree: Mathematics and Physics (Masters) - Bristol University

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About me

Hi. I'm Ben and I am a second year mathematician and physicist at the University of Bristol. I am looking for students to tutor for both maths and physics.

Maths and Physics are very beautiful subjects. I hope that, through my enthusiastic approach, we can develop a strong foundation in either maths or physics (or both) that will prove to be extremely useful in your studies and will help you boost your exam grades. I believe that the most important part of learning these subjects is developing a true understanding of the material. Often, a lot of the beauty and elegance of maths and physics is lost by teachers who place a huge emphasis on training students to robotically answer questions. Whilst I appreciate that answering questions and solving problems is a huge part of the learning process and will provide questions and examples in the tutorials, I would love to help you gain a deeper understanding of the theories in order for you to have a greater appreciation of the subjects. I am confident that this approach will prove extremely useful when it comes to helping you prepare for exams.

Maths units I can help you with: C1-C4, FP1-FP3, M1-M2

I look forward to meeting you!

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr
Physics A Level £20 /hr

Qualifications

QualificationLevelGrade
MathematicsA-LevelA*
PhysicsA-LevelA*
BiologyA-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

No

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Questions Ben has answered

differentiate y = (4-x)^2

This is a basic example of a very important result: the chain rule. The difficulty of this sort of example is that we have a "function of a function". That is, we have the function '4-x' and then we square this.  The general approach is as follows. First we will let 'u' be a new function: u=4...

This is a basic example of a very important result: the chain rule. The difficulty of this sort of example is that we have a "function of a function". That is, we have the function '4-x' and then we square this. 

The general approach is as follows. First we will let 'u' be a new function: u=4-x. It is evident that now we have y=u^2 which looks like it might be easier to work with. The chain rule says the following:

dy/dx = (dy/du)*(du/dx)

In this case y=u^2 so, from normal differentiation, we get dy/du = 2u. We also then have u = 4-x. So, again from normal differentiation techniques, we have du/dx=-1.

Using the chain rule gives dy/dx = (2u)*(-1) and if we substitute u=4-x we get

dy/dx = -2(4-x)  = 2x-8    which is the final answer.                                   

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8 months ago

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