Emily R. 13 Plus  English tutor, 11 Plus English tutor, GCSE English ...

Emily R.

£18 - £25 /hr

Currently unavailable:

Studying: Law with Spanish Law (Bachelors) - Oxford, Magdalen College University

5.0
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

5 reviews| 7 completed tutorials

Contact Emily

About me

Hi, I'm Emily!

I am a third-year Law with Spanish Law student at the University of Oxford and currently on my year-abroad in Spain.

Whilst I am new to mytutor, I have previous experience of tutoring Maths and English for KUMON UK.

I tutor Maths, English and Spanish (my three International Baccalaureate Higher Level subjects), all of which I adore. I am excited to both pass on my enthusiasm for these subjects and, of course, to help students achieve their best grades

I am also happy to help with preparation for the LNAT and with Oxbridge applications. Having been through the process myself recently, I can entirely empathise with how stressful it can be and how reassuring it is to be given extra guidance. 

If you are interested, please just drop me an email and I will get back to you as soon as I can :)

Hi, I'm Emily!

I am a third-year Law with Spanish Law student at the University of Oxford and currently on my year-abroad in Spain.

Whilst I am new to mytutor, I have previous experience of tutoring Maths and English for KUMON UK.

I tutor Maths, English and Spanish (my three International Baccalaureate Higher Level subjects), all of which I adore. I am excited to both pass on my enthusiasm for these subjects and, of course, to help students achieve their best grades

I am also happy to help with preparation for the LNAT and with Oxbridge applications. Having been through the process myself recently, I can entirely empathise with how stressful it can be and how reassuring it is to be given extra guidance. 

If you are interested, please just drop me an email and I will get back to you as soon as I can :)

Show more

No DBS Icon

No DBS Check

Ratings & Reviews

5from 5 customer reviews
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Zoe (Parent)

December 15 2016

Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Elle (Student)

December 15 2016

Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Paul (Parent)

December 13 2016

Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.
Star 1 Created with Sketch.

Paul (Parent)

December 2 2016

Show more reviews

Qualifications

SubjectQualificationGrade
English Higher LevelInternational Baccalaureate (IB)7
Spanish Higher LevelInternational Baccalaureate (IB)7
Mathematics Higher LevelInternational Baccalaureate (IB)6
Economics Standard LevelInternational Baccalaureate (IB)7
Biology Standard LevelInternational Baccalaureate (IB)7
History Standard LevelInternational Baccalaureate (IB)6

General Availability

Before 12pm12pm - 5pmAfter 5pm
mondays
tuesdays
wednesdays
thursdays
fridays
saturdays
sundays

Subjects offered

SubjectQualificationPrices
EnglishGCSE£18 /hr
MathsGCSE£18 /hr
SpanishGCSE£18 /hr
EnglishIB£20 /hr
SpanishIB£20 /hr
English13 Plus£18 /hr
Maths13 Plus£18 /hr
Spanish13 Plus£18 /hr
English11 Plus£18 /hr
Maths11 Plus£18 /hr
-Oxbridge Preparation-Mentoring£22 /hr
.LNAT.Uni Admissions Test£25 /hr

Questions Emily has answered

How do I simplify fully (p^3 x p^4)/p^2?

At first this looks quite daunting as it combines a number of different indices (powers) and a fraction. 

The rules for indices are just something that you have to learn - so don't worry if you don't know them yet. Once you do, the answer to this problem will be clear. 

First, let's step back from the question and learn the rules:

x^2 x x^4 = x^6 (the indices are added together)

x^8 / x^3 = x^5 (the second index is subtracted from the first)

Remeber that this only works when the base number (in this case 'x') is the same!

Second, let's look at the question. Let's start with the numerator (top) of the fraction. When the base number is the same (in this case 'p') and being multiplied, the indices are added together. So the top of the fracticion can be simplified to get: p^7.

That means we are now left with: p^7/p^2.

Next, we are going to consider how to simplify the fraction. We need to subtract the value of the denominator's index from the numerator's index. Therefore, we are left with p^5. 

And there is your answer! So (p^3 x p^4)/p^2 simplified is p^5.

If you want to practice, try this one: (x^10)/(x^2 x x^6).

At first this looks quite daunting as it combines a number of different indices (powers) and a fraction. 

The rules for indices are just something that you have to learn - so don't worry if you don't know them yet. Once you do, the answer to this problem will be clear. 

First, let's step back from the question and learn the rules:

x^2 x x^4 = x^6 (the indices are added together)

x^8 / x^3 = x^5 (the second index is subtracted from the first)

Remeber that this only works when the base number (in this case 'x') is the same!

Second, let's look at the question. Let's start with the numerator (top) of the fraction. When the base number is the same (in this case 'p') and being multiplied, the indices are added together. So the top of the fracticion can be simplified to get: p^7.

That means we are now left with: p^7/p^2.

Next, we are going to consider how to simplify the fraction. We need to subtract the value of the denominator's index from the numerator's index. Therefore, we are left with p^5. 

And there is your answer! So (p^3 x p^4)/p^2 simplified is p^5.

If you want to practice, try this one: (x^10)/(x^2 x x^6).

Show more

1 year ago

817 views

Arrange a free video meeting


To give you a few options, we can ask three similar tutors to get in touch. More info.

Contact Emily

How do we connect with a tutor?

Where are they based?

How much does tuition cost?

How do tutorials work?

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this. Dismiss

mtw:mercury1:status:ok