PremiumHenri F.

Henri F.

£30 - £32 /hr

Aerospace Engineering PhD Spacecraft Control (Doctorate) - Bristol University

5.0
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41 reviews

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This tutor is also part of our Schools Programme. They are trusted by teachers to deliver high-quality 1:1 tuition that complements the school curriculum.

63 completed lessons

About me

I am a PhD candidate in Aerospace Engineering studying at the University of Bristol where I completed my MEng (Master of Engineering) with first class honours. I specialise in spaceceraft control and always aim to bring the excitement of cutting-edge research into tutorials. I always aim to provide context and application for all that I teach so that students are never left asking the question "When will I ever use this?". I offer both short term reactive tuition where we deal with issues when they arise or long-term structured and proactive tuition where I will guide you through the syllabus, which is also suitable for those students studying qualifications without teacher-led support. 

I am a PhD candidate in Aerospace Engineering studying at the University of Bristol where I completed my MEng (Master of Engineering) with first class honours. I specialise in spaceceraft control and always aim to bring the excitement of cutting-edge research into tutorials. I always aim to provide context and application for all that I teach so that students are never left asking the question "When will I ever use this?". I offer both short term reactive tuition where we deal with issues when they arise or long-term structured and proactive tuition where I will guide you through the syllabus, which is also suitable for those students studying qualifications without teacher-led support. 

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About my sessions

I have been teaching for 7 years in physics, electronics, maths and further maths. I've taught students ranging from GCSE age to adult learners coming back to education through their workplace. I firmly believe in leading with a concept based approach, then backing up that teaching with relevant questions, both basic and advanced, to continually test your understanding. Most of all I hope to inspire each and every one of you to love your subjects by revealing the beauty in the mathematics. We all learn differently, and as an experienced tutor I understand this better than most. Some students prefer diagrams and physical demonstrations, other prefer sticking to the mathematics, while some others again may prefer analogies with things from other disciplines. I hope to work with you to get the very most out of our sessions. Still reading? You must be interested! Feel free to send me a message through mytutor or arrange a 15 minute 'Meet the Tutor' session, free of charge!

I have been teaching for 7 years in physics, electronics, maths and further maths. I've taught students ranging from GCSE age to adult learners coming back to education through their workplace. I firmly believe in leading with a concept based approach, then backing up that teaching with relevant questions, both basic and advanced, to continually test your understanding. Most of all I hope to inspire each and every one of you to love your subjects by revealing the beauty in the mathematics. We all learn differently, and as an experienced tutor I understand this better than most. Some students prefer diagrams and physical demonstrations, other prefer sticking to the mathematics, while some others again may prefer analogies with things from other disciplines. I hope to work with you to get the very most out of our sessions. Still reading? You must be interested! Feel free to send me a message through mytutor or arrange a 15 minute 'Meet the Tutor' session, free of charge!

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Personally interviewed by MyTutor

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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23/11/2016

Ratings & Reviews

5
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41 customer reviews
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HJ
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Hailan Parent from London Lesson review 25 Nov, 16:00

3 Dec

Henri is a great tutor, my son Hugo really enjoyed his lesson!

AA
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Aaliah Student Lesson review 18 Oct '17, 20:00

18 Oct, 2017

Really helpful

AC
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Andrew Parent from Ramsgate Lesson review 27 Feb '17, 18:30

27 Feb, 2017

Fantastic...very patient...great teacher.

RR
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Rob Student Lesson review 7 Feb '17, 16:00

7 Feb, 2017

An excellent tutorial - Henri has an in depth subject knowledge with an ability to clearly explain concepts - He is able to connect abstract concepts to real life scenarios. Thank you Henri!

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Qualifications

SubjectQualificationGrade
MathsA-level (A2)A
Further MathsA-level (A2)A
PhysicsA-level (A2)A*
Aerospace Engineering BEngDegree (Bachelors)FIRST CLASS
ElectronicsA-level (A2)A*
Aerospace Engineering MEngDegree (Masters)FIRST CLASS

General Availability

MonTueWedThuFriSatSun
Pre 12pm
12 - 5pm
After 5pm

Pre 12pm

12 - 5pm

After 5pm
Mon
Tue
Wed
Thu
Fri
Sat
Sun

Subjects offered

SubjectQualificationPrices
Extended Project QualificationA Level£30 /hr
MathsA Level£30 /hr
PhysicsA Level£30 /hr

Questions Henri has answered

Find the area of the region, R, bounded by the curve y=x^(-2/3), the line x = 1 and the x axis . In addition, find the volume of revolution of this region when rotated 2 pi radians around the x axis.

As we are looking to find the area under a curve we can use integration. The area under a curve with equation y = f(x), bounded by the lines x = a and x = b and the x axis can be expressed as:A = integral (from a to b) f(x) dxThus, the area of the region, R, can be expressed as:R = integral (from 1 to infinity) x^(-2/3) dxR = [3*x^(1/3)] (from 1 to infinity)R = (3*infinity(1/3))-(3*1^(1/3)) = infinity - 3 = infinityR = infinityTherefore the region has infinite area, Considering now the volume of revolution, again using integration:The volume of revolution 2pi radians around the x axis of the same region described above can be expressed:V = pi * integral (from a to b) f(x)^2 dxThus, for the curve in question:V = pi * integral (from 1 to infinity) [x^(-2/3)]^2 dx = pi * integral (from 1 to infinity) x^(4/3) dxV = [-3*x^(-1/3)] (from 1 to infinity) = (-3*infinity^(-1/3))-(-3*1^(-1/3)) = 0 - (-3) = 3V = 3This interesting problem shows that a region can have infinity area but its revolution can have fininte volume  As we are looking to find the area under a curve we can use integration. The area under a curve with equation y = f(x), bounded by the lines x = a and x = b and the x axis can be expressed as:A = integral (from a to b) f(x) dxThus, the area of the region, R, can be expressed as:R = integral (from 1 to infinity) x^(-2/3) dxR = [3*x^(1/3)] (from 1 to infinity)R = (3*infinity(1/3))-(3*1^(1/3)) = infinity - 3 = infinityR = infinityTherefore the region has infinite area, Considering now the volume of revolution, again using integration:The volume of revolution 2pi radians around the x axis of the same region described above can be expressed:V = pi * integral (from a to b) f(x)^2 dxThus, for the curve in question:V = pi * integral (from 1 to infinity) [x^(-2/3)]^2 dx = pi * integral (from 1 to infinity) x^(4/3) dxV = [-3*x^(-1/3)] (from 1 to infinity) = (-3*infinity^(-1/3))-(-3*1^(-1/3)) = 0 - (-3) = 3V = 3This interesting problem shows that a region can have infinity area but its revolution can have fininte volume 

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2 years ago

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