Currently unavailable: for regular students
Degree: Natural Sciences (Masters) - Durham University
I am a Natural Scientist specialising in maths and physics at Durham university. I believe that in order to confidently answer a question, you must first understand the surrounding topic. In my tutorials I aim to help students understand the material itself by using analogies and examples that simplify or break up more complicated ideas. In order to have a productive tutorial it is important to tailor both the topic and teaching style to the individual student and I aim to adapt my method to the situation at hand.
Over the course of my GCSE and IB (A-level equivalent) qualifications I found myself helping fellow students both inside and outside of lessons and I believe I have developed skills in recognising where someone is struggling to understand and providing a helping hand to facilitate their learning. Looking forward to meeting you all!
|Further Mathematics||A Level||£20 /hr|
|Maths||A Level||£20 /hr|
|Further Mathematics||GCSE||£18 /hr|
|Further Mathematics||IB||£20 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Amelia (Student) December 5 2016
Amelia (Student) November 28 2016
To begin with, chemical energy in the fuel is released through combustion and becomes thermal energy. This thermal energy is used to heat water which evaporates and become steam. The rising steam turns turbines and the system now contains the kinetic energy of the turning turbines. The turbines are finally linked to a generator which converts the kinetic energy into electricity.see more
In an atom, the mass is concentrated in the nucleus which is at the centre of the atom. The nucleus is composed of neutrons and protons, each with a relative mass of 1. By comparison, the third component of an atom is the electrons which orbit the nucleus and have a relatively neglible mass.
The charge of the atom is defined by the total charge of its components. Electrons have a charge of -1, protons of +1 and neutrons have no charge.see more
In order to find the angle that satisfies a trigonometric function, the easiest way is to use the inverse function on a calculator.
E.g. cos(x)=2/3 then one solution is x=cos^-1(2/3).
In order to do this, we can set the subject of the function to u. In other words, we make the inside of the brackets equal to u and then find the new range.
u=17-2x. When x=-180, u=17-2(-180)=377
When x=180, u=17-2(180)=-343.
Therefore, -343 to 377 is our new range for u.
Since sec(u)=-2 and sec(u)=1/cos(u), we can invert both sides to get cos(u)=-1/2.
Using the cos^-1(-1/2) on a calculator we get one solution where u=120. Due to the symmetry around 180 of cos, we can find another solution using the formula 180+(180-120)=240.
To get the two remaining solutions within the range, we can use cos(a)=cos(-a) so the other solutions are -120 and -240.
We have the four solutions: u=-240, -120, 120, 240. And must now convert them back to x.
Since u=17-2x, x=(17-u)/2.
Therefore the solutions are x=128.5, 68.5, -51.5, -111.5 (all in degrees).see more