__About Me__

My name is Philippa, and I'm a third year Maths and Physics student at the University of Manchester. So many disciplines rely on maths knowledge when you get to an advanced study level, and I've met countless people who feel that 'not having a head for maths' has held them back - I want to make sure that doesn't happen to you! I have a huge passion for maths and sciences; I am always delighted to help students who struggle to enjoy these subjects just because they may not immediately grasp the numerical concepts behind them. I fully understand how intimidating these exams can be - that's why I'm here to help you get your head round them.

**My Teaching**

I despise rote learning. In maths and sciences especially, a** **solid understanding will take you further that being able to memorise a textbook verbatim. Once I know what areas you are struggling with, we will first focus on fostering a **solid understanding** of the material, and then focus on** exam technique. **My aim is to ensure you understand the topics as well as I do, and during our sessions I hope that some of my enthusiasm will rub off!

Knowing the material is only half the battle, and we will work not just on getting the answers, but also on the methods and techniques that examiners are looking for. For maths-based subjects, only a fraction of the question marks are awarded for bottom line answers; we will also be spending time on how to set up questions and lay out your answers in a way that will impress the examiner and hit all those mark scheme points.

** If you are interested or want to know more,** get in contact and drop me a message! Let me know your exam board, what papers you are taking and the areas that you're struggling with and I will be happy to help you out.

__About Me__

My name is Philippa, and I'm a third year Maths and Physics student at the University of Manchester. So many disciplines rely on maths knowledge when you get to an advanced study level, and I've met countless people who feel that 'not having a head for maths' has held them back - I want to make sure that doesn't happen to you! I have a huge passion for maths and sciences; I am always delighted to help students who struggle to enjoy these subjects just because they may not immediately grasp the numerical concepts behind them. I fully understand how intimidating these exams can be - that's why I'm here to help you get your head round them.

**My Teaching**

I despise rote learning. In maths and sciences especially, a** **solid understanding will take you further that being able to memorise a textbook verbatim. Once I know what areas you are struggling with, we will first focus on fostering a **solid understanding** of the material, and then focus on** exam technique. **My aim is to ensure you understand the topics as well as I do, and during our sessions I hope that some of my enthusiasm will rub off!

Knowing the material is only half the battle, and we will work not just on getting the answers, but also on the methods and techniques that examiners are looking for. For maths-based subjects, only a fraction of the question marks are awarded for bottom line answers; we will also be spending time on how to set up questions and lay out your answers in a way that will impress the examiner and hit all those mark scheme points.

** If you are interested or want to know more,** get in contact and drop me a message! Let me know your exam board, what papers you are taking and the areas that you're struggling with and I will be happy to help you out.

We only take tutor applications from candidates who are studying at the UK’s leading universities. Candidates who fulfil our grade criteria then pass to the interview stage, where a member of the MyTutor team will personally assess them for subject knowledge, communication skills and general tutoring approach. About 1 in 7 becomes a tutor on our site.

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5from 11 customer reviews

Freyja (Student)

March 21 2017

Really explains things thoroughly, has helped me with things that I have never got before!

Monisha (Student)

December 8 2016

very detailed tutorial and clear explanation

Jo (Parent from Wirral)

June 23 2017

Jo (Parent from Wirral)

June 20 2017

This question is simply a matter of finding and applying the correct equation of motion.

First, draw a diagram - even if the situation in the questions seems really simple, it's always useful to draw a diagram.

The card is being dropped** from rest**; as the only force acting on it is gravity, the acceleration - and therefore final velocity - will be purely vertical. The question also specifies that the card is dropped from a given **vertical **distance - this is all good news as we will not have to resolve anything into horizontal and vertical components.

Now we write down all the quantities that we might find in an equation of motion that relate to the question.

s = distance travelled = 0.75m

u = initial velocity = 0 m/s

v = final velocity = 3.84 m/s

a = acceleration = g, **to be found**

t = time elapsed. We are not given t, nor are we at any point required to find it - so as far as we are concerned t is** irrelevant!**

The only quantities that matter are **s, u, v and a**; so we just find the equation of motion that includes these four, and substitute our values in.

From either memory or the formula sheet, we have the equation:

v^{2 }- u^{2 }= 2as.

Simply rearrange in terms of the value we are trying to find, in this case **a**, and plug in the numbers to get our estimate for g,

a = 9.83 m/s^{2.}

You might notice this is actually slightly different from the accepted value of 9.81 - this is fine! The exam board will rarely have you calculate a known constant that comes out exactly right; this is to prevent you just looking up the answer in the formula booklet. As our answer is very close, we can be confident that the calculations are correct.

This question is simply a matter of finding and applying the correct equation of motion.

First, draw a diagram - even if the situation in the questions seems really simple, it's always useful to draw a diagram.

The card is being dropped** from rest**; as the only force acting on it is gravity, the acceleration - and therefore final velocity - will be purely vertical. The question also specifies that the card is dropped from a given **vertical **distance - this is all good news as we will not have to resolve anything into horizontal and vertical components.

Now we write down all the quantities that we might find in an equation of motion that relate to the question.

s = distance travelled = 0.75m

u = initial velocity = 0 m/s

v = final velocity = 3.84 m/s

a = acceleration = g, **to be found**

t = time elapsed. We are not given t, nor are we at any point required to find it - so as far as we are concerned t is** irrelevant!**

The only quantities that matter are **s, u, v and a**; so we just find the equation of motion that includes these four, and substitute our values in.

From either memory or the formula sheet, we have the equation:

v^{2 }- u^{2 }= 2as.

Simply rearrange in terms of the value we are trying to find, in this case **a**, and plug in the numbers to get our estimate for g,

a = 9.83 m/s^{2.}

You might notice this is actually slightly different from the accepted value of 9.81 - this is fine! The exam board will rarely have you calculate a known constant that comes out exactly right; this is to prevent you just looking up the answer in the formula booklet. As our answer is very close, we can be confident that the calculations are correct.

We start with £800 in the bank. As we are earning **compound interest, **it means that each year we get 3.5% of the original £800, plus 3.5% of __any interest that has already been earned. __So, at the end of the year, you will have

1.035 x (however much money was in the account at the start of the year).

Let's start with year 1. You have £800 at the start, and at the end you have

£800 x 1.035 = £828.

Now let's think about year 2. You start with £828, and end with

£828 x 1.035 = £856.98

We can also write it like this:

Money at end of year 2 = £828 x 1.035 = £800 x 1.035 x 1.035

Do you see how for each year we earn interest, we just multiply the original £800 by another 1.035?

So, after n years, the total in the account is:

£800 x 1.035^{n}

This makes it easy to work out the total after 7 years, which is just:

£800 x 1.035^{7 }= £1017.82 (rounded to the nearest penny)

To find the interest earned, just subtract the original amount (in this case £800), and we get our answer:

£1017.82 - £800 = £217.82 interest

We start with £800 in the bank. As we are earning **compound interest, **it means that each year we get 3.5% of the original £800, plus 3.5% of __any interest that has already been earned. __So, at the end of the year, you will have

1.035 x (however much money was in the account at the start of the year).

Let's start with year 1. You have £800 at the start, and at the end you have

£800 x 1.035 = £828.

Now let's think about year 2. You start with £828, and end with

£828 x 1.035 = £856.98

We can also write it like this:

Money at end of year 2 = £828 x 1.035 = £800 x 1.035 x 1.035

Do you see how for each year we earn interest, we just multiply the original £800 by another 1.035?

So, after n years, the total in the account is:

£800 x 1.035^{n}

This makes it easy to work out the total after 7 years, which is just:

£800 x 1.035^{7 }= £1017.82 (rounded to the nearest penny)

To find the interest earned, just subtract the original amount (in this case £800), and we get our answer:

£1017.82 - £800 = £217.82 interest