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About me

Hi! My name is Sioned, and I'm a final year law student at University College London (UCL).

I have a great deal of experience in teaching students for the 11+ / 13+, English, Maths, Sciences and History at KS3 and GCSE. I can also help with Personal Statements and the Law National Admissions Test (LNAT).  

I love tutoring and teach regularly on the Schools programme. Having taught approx.100 students, I have come across so many problems that students face with their studies and am always happy to help!

About my sessions

The sessions are structured around you. After our initial 15 minutes free chat about what you need from me, I structure a plan to help you achieve what you set out to achieve....

This includes 

 - Using diagrams, sketches, videos, textbooks and good examples to help you understand a topic

 - Past exam papers and questions that will help you understand what is expected of you 

 -Repetition and revision of things that you don't understand 

 - Marked papers and clear constructive criticism for improvement 

 - I also use worksheets and past exams as homework if you want to consolidate what you learned

Subjects offered

SubjectLevelMy prices
Biology GCSE £24 /hr
English GCSE £24 /hr
History GCSE £24 /hr
Maths GCSE £24 /hr
English 13 Plus £24 /hr
Maths 13 Plus £24 /hr
English 11 Plus £24 /hr
Maths 11 Plus £24 /hr
-Personal Statements- Mentoring £26 /hr
-Personal Statements- Mentoring £26 /hr
.LNAT. Uni Admissions Test £28 /hr

Qualifications

QualificationLevelGrade
EnglishA-LevelA*
HistoryA-LevelA*
BiologyA-LevelA
MusicA-LevelA
Mathematics (AS)A-LevelA
Welsh Baccalaureate A-LevelA
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

13/12/2016

General Availability

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Please get in touch for more detailed availability

Ratings and reviews

5from 22 customer reviews

Liam (Student) May 24 2017

Very good tutor, helped me understand very well, goes completely out of her way to help students understand. Will definitely use this tutor in the future. Thank you Sioned!

Lori (Parent) January 26 2017

Sioned inspired my son to believe that he was good at writing, which resulted in his entrance exam success at a top London independent secondary school. She has been a pleasure to work with, always approaching her work with a sunny disposition. Thank you, Sioned!

Katy (Student) January 15 2017

Very helpful.

Lori (Parent) January 5 2017

Just a good session overall, absolutely perfect
See all reviews

Questions Sioned has answered

Prove that (2n+3)^2-(2n-3)^2 is a multiple of 8 for positive integer values of n

To prove that (2n+3)2-(2n-3)2 is a multiple of 8 we are going to deal with the first bracket and then the second bracket.  When a bracket has 2 next to it, this means that you multiplying the bracket, by the bracket itself.  So, we are going to put them side by side, like this: (2n  +3) (2n ...

To prove that (2n+3)2-(2n-3)is a multiple of 8 we are going to deal with the first bracket and then the second bracket. 

When a bracket has next to it, this means that you multiplying the bracket, by the bracket itself. 

So, we are going to put them side by side, like this:

(2n  +3) (2n + 3) 

To multiply everything in the first bracket, by everything in the second bracket, we can use a multiplication square, or, we can use this easy way to remember how to multiply out the bracket. 

F O I L 

This stands for: 

First 

Outside 

Inside 

Last 

This means that you are going to multiply the first two terms in the brackets by each other

2n x 2n =4n2

Then you are going to multiply the outside terms in the brackets by each other. 

2n x 3 = 6n

Then you multiply the inside terms by each other, 

2n x 3 = 6n

Then you multiply the last two terms in each bracket by each other. 

3 x 3 = 9 (be careful of the negatives here)

Putting all of this together, we get:

4n2 + 6n + 6n +9

Well done, first bit complete!

*****************************************

Then you deal with the second bit 

- (2n-3)2

So, be very careful here. There is a negative sign in front of the bracket. To avoid confusion later on, let's put a big bracket around it. 

- [(2n-3)2]

everything we do in this section is going to be inside that big square bracket...

-[(2n-3)(2n-3)]

following FOIL again and keeping that big bracket in place...

-[4n-6n -6n +9]

make sure you watch out for that (-3 x -3) which makes a +9

and then, because we have that big bracket around this equation, we are going to multiply it out. 

so, 

-4n2 + 12n -9

********************************************************

So putting the first bit and the second bit together (and watching out for those negatives!), we get...

4n+12n +9 - 4n2 + 12n -9

now we are going to tidy that up a little bit, collecting the like terms....

4n2 -4n=0

and +9 -9 =0

So, we are just left with 24n 

If you didn't know what an integer was... it means WHOLE NUMBER. So to show that the integer is a multiple of 8, we are going to show that 

to get 24n you can take out a factor of 8...

and this leaves you with 8(3n). 

this shows that if you take out a factor of 8 you still get a whole number in front of n, which answers the question!

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6 months ago

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