Hey there, I'm Alex! I am a Fourth year Physics Masters student at Exeter University, native English Speaker who has studied Physics B (Advancing Physics) on the OCR exam board for A-Level, and Mathematics on the Edexcel board for A-Level and GCSE. I will be able to help with A-Level Physics, Mathematics and GCSE Chemistry, Physics, Maths and Astronomy. I aim to help you not only do well on your exams by regurgitating information, but to actually help you understand what you are learning so that it will stick with you for a long time. I have tutored A-Level students before, helping them attain high grades on their exams. I am a friendly down-to-earth person who will not only feel like your tutor, but also your friend! I am almost always available to help, from around 6pm onwards everyday, or you can e-mail anytime with queries and i'll respond usually within the hour!
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How can I measure the orbital period of a satellite around Earth?
In order to find the orbital period of a satellite around earth, you must
understand the forces at play in this situation. You must equate the two radial
forces acting on the satellite - these are Newton's law of gravitational
attraction between the satellite and the earth, and the centripetal...In order to find the orbital period of a satellite around earth, you must understand the forces at play in this situation. You must equate the two radial forces acting on the satellite - these are Newton's law of gravitational attraction between the satellite and the earth, and the centripetal force acting on the satellite. (You can imagine the centripetal force as the tension in an invisible wire connecting the satellite to the earth as it attempts to move away and is pulled back in as it orbits).
By equating these two forces you will be able to cancel down the like-coefficients and be left with the equation of orbital velocity for the Satellite. After this you must realise that the period can be related to the velocity by the speed-distance-time relation, where orbital period is the inverse of orbital time.see more
2 days ago
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