Walter  T. A Level Further Mathematics  tutor, A Level Maths tutor

Walter T.

Currently unavailable: for new students

Degree: Civil Engineering (Masters) - Bristol University

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About me

Hi! I'm Walter, a specialist maths tutor and a first year civil engineering student at the University of Bristol. I love maths and it forms a large part of my degree, so my love for it should come across easily in our sessions! I have experience as a tutor, having spent a year teaching maths as part of my school's Community Service Organisation, and running a peer-based maths clinic in my last year of secondary school. Most importantly, I am always smiling and very patient, and I aim to make learning very enjoyable! I believe that in order to get the best grades in A Level Maths, you need to understand the principles behind the maths. We can simply go over past paper questions if more practice in a certain area is required, or right to the basics of a question to understand how to answer it, and why it's answered as it is. I can spend as much time as required on a certain topic, and we can always speed up or slow down depending on how you learn best. My aim is that you will reach the stage where you understand the subject well enough that you can teach others, proving that you really know it.

About my sessions

As far as the structure of the sessions goes I am flexible in my teaching style, so should you simply wish more practice in a certain topic we can go over some exam-style questions together, otherwise I can explain a subject from scratch, in as many different ways as it takes for the concepts to click. We can measure progress in the form of quizzes at the end of sessions, or if the subject matter corresponds to what is being studied in school, the marks in homework set on that topic should indicate how performance is improving.

Subjects offered

SubjectLevelMy prices
Further Mathematics A Level £20 /hr
Maths A Level £20 /hr

Qualifications

QualificationLevelGrade
MathsA-LevelA*
PhysicsA-LevelA
Further MathsA-LevelA
GermanA-LevelB
Disclosure and Barring Service

CRB/DBS Standard

No

CRB/DBS Enhanced

09/03/2017

General Availability

Currently unavailable: for new students

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Ratings and reviews

4.5from 2 customer reviews

María Victoria (Parent) March 19 2017

Karla (Student) March 19 2017

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Questions Walter has answered

Can you express 3 + 4j in polar form?

First, let's imagine the point 3 + 4j as a point on an Argand diagram, with coordinates 3,4. The polar form of an imaginary number is in the form re^(jθ), where r is the modulus of the number (the distance between the point on the graph and the origin), and θ is the argument (the angle the poi...First, let's imagine the point 3 + 4j as a point on an Argand diagram, with coordinates 3,4. The polar form of an imaginary number is in the form re^(jθ), where r is the modulus of the number (the distance between the point on the graph and the origin), and θ is the argument (the angle the point makes with the horizontal). In order to find r, we can simply use Pythagoras' Theorem, giving us the answer r = 5. To find θ, we must use trigonometry, identifying the angle θ as the inverse tangent of (4/3), which is equal to 0.927. Therefore the angle θ is 0.927. This means the polar form of 3 + 4j is 5e^0.927jθ see more

5 months ago

246 views

Differentiate y = √(1 + 3x²) with respect to x

To solve this question, we need to use the chain rule, because the function is too complicated to solve simply by inspection. The chain rule says that dy/dx = dy/du × du/dx, where u is a function of x. In this example, if we let u = 1 + 3x², then we get y = √(u), which means when we differenti...To solve this question, we need to use the chain rule, because the function is too complicated to solve simply by inspection. The chain rule says that dy/dx = dy/du × du/dx, where u is a function of x. In this example, if we let u = 1 + 3x², then we get y = √(u), which means when we differentiate with respect to u, dy/du = 1/(2√(u)). u = 1 + 3x² which means du/dx = 6x, so dy/dx = 6x/(2√(u)), or 3x/√(1 + 3x²). (This can also be expressed as 3x(1 + 3x²)^-0.5). see more

6 months ago

220 views
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