I am currently studying an Undergraduate Masters in Chemistry at University College London.
I studied Edexcel Chemistry, Edexcel Maths and AQA French to A-level, and AQA Spanish to AS at Sixth Form College.
I am offering tutoring in GCSE and A level Chemistry and GCSE Mathematics.
I took AQA Maths GCSE and got full marks! I also received an A in FSMQ Further Mathematics.
I took separate sciences (Physics, Chemistry and Biology) and received an A* in each.
The Maths curriculum and GCSEs have changed a lot recently but I have been briefed on the most up-to-date syllabi and have access to mock papers, past papers and resources thanks to my mum who is a secondary school Maths teacher. I have a very thorough understanding of what is expected of you as a GCSE student, so you will be in good hands.
I am very enthusiastic and patient. I want my students to be able to understand their studies so that they can enjoy them as much as I do. I like to understand what the student is struggling with and then set aims to track their progress. I try to provide tips and useful skills to improve their studying across the board as well as in a specific subject. I use a variety of resources, including diagrams, board chalks, online games, quizzes and past papers to enhance the student's learning and engagement.
I am back from the my year abroad, ready to plunge into another year of tutoring! I was teaching assistant for two classes at Johns Hopkins, so I have been ever-improving my teaching skills.
If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session' (both accessible through this website). Remember to tell me your exam board and what you're struggling with.
I have no lecture courses now, so I am very flexible with times. My availability often gets booked up fast, so please contact me as soon as possible to get your first choice. I'm looking forward to meeting you!
|Chemistry||A Level||£26 /hr|
|Maths||A Level||£26 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
Please get in touch for more detailed availability
Abdul (Parent) January 13 2017
Ealasade (Student) September 27 2016
Najma (Parent) March 6 2015
Najma (Parent) March 2 2015
Line A has a gradient of 4 and passes through point (5,6).
Line B passes through points C (0,5) and D (2,0).
Find the coordinates of the point where the two lines intersection.
First of all find the equation of line A:
Using y= mx + c,
Applying the gradient, line A has equation, y = 4x + c
To find c, substitute in the coordinates of point P,
6 = (4x5) + c
6 = 20 + c
c = 6 - 20 = -14
Therefore the equation of line A is y = 4x - 14
Now find the equation of line B:
Using ( y2 - y1 ) / ( x2 - x1 ) = gradient of a line
Substitute in coordinates of points C and D,
( yC - yB ) / ( xC - xB ) = ( 5 - 0 ) / ( 0 - 2 ) = 5/-2 or -5/2
Using y = mx + c
Applying the gradient found, line B has the equation, y = -5/2 x + c
To find c, substitute in the coordinates of point C,
5 = ( -5/2 x 0 ) + c
c = 5
Therefore the equation of line B is y = -5/2 x + 5
This can be rearranged,
(multiply everything by 2) --> 2y = -5x + 10
(rearrange) ---> 5x + 2y = 10
You can check your answer by using the coordinates of point D,
( 5 x 2 ) + ( 2 x 0 ) = 10 ---> Yes
Finally find the coordinates where the lines intersect:
A y = 4x - 14
B 5x + 2y = 10
A x2 2y = 8x - 28
Rearrange 8x - 2y = 28
Using simultaneous equations, add A x2 and B, to eliminate y,
5x + 8x + 2y - 2y = 10 + 28
13x = 38
x = 38/13
Substitute in x to A to find y,
y = ( 4 x 38/13 ) - 14
y = 152/13 - 182/13
y = -30/13
Put these coordinates into the equation for line B to check it works,
( 5 x 38/13 ) + (2 x -30/13 ) = 10
190/13 - 60/13 = 130/13 = 10 ----> Yes
The lines cross at coordinate ( 38/13, -30/13 )see more