I am currently studying an Undergraduate Masters in Chemistry at University College London.
I studied Edexcel Chemistry, Edexcel Maths and AQA French to A-level, and AQA Spanish to AS at Sixth Form College.
I am offering tutoring in GCSE and A level Chemistry and GCSE Mathematics.
I took AQA Maths GCSE and got full marks! I also received an A in FSMQ Further Mathematics.
I took separate sciences (Physics, Chemistry and Biology) and received an A* in each.
The Maths curriculum and GCSEs have changed a lot recently but I have been briefed on the most up-to-date syllabi and have access to mock papers, past papers and resources thanks to my mum who is a secondary school Maths teacher. I have a very thorough understanding of what is expected of you as a GCSE student, so you will be in good hands.
I am very enthusiastic and patient. I want my students to be able to understand their studies so that they can enjoy them as much as I do. I like to understand what the student is struggling with and then set aims to track their progress. I try to provide tips and useful skills to improve their studying across the board as well as in a specific subject. I use a variety of resources, including diagrams, board chalks, online games, quizzes and past papers to enhance the student's learning and engagement.
I am back from the my year abroad, ready to plunge into another year of tutoring! I was teaching assistant for two classes at Johns Hopkins, so I have been ever-improving my teaching skills.
If you have any questions, send me a 'WebMail' or book a 'Meet the Tutor Session' (both accessible through this website). Remember to tell me your exam board and what you're struggling with.
My availability often gets booked up fast, so please contact me as soon as possible to get your first choice. I'm looking forward to meeting you!
|Chemistry||A Level||£26 /hr|
|Maths||A Level||£26 /hr|
|Before 12pm||12pm - 5pm||After 5pm|
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Ealasade (Student) September 27 2016
Najma (Parent) March 6 2015
Najma (Parent) March 2 2015
Najma (Parent) March 2 2015
Line A has a gradient of 4 and passes through point (5,6).
Line B passes through points C (0,5) and D (2,0).
Find the coordinates of the point where the two lines intersection.
First of all find the equation of line A:
Using y= mx + c,
Applying the gradient, line A has equation, y = 4x + c
To find c, substitute in the coordinates of point P,
6 = (4x5) + c
6 = 20 + c
c = 6 - 20 = -14
Therefore the equation of line A is y = 4x - 14
Now find the equation of line B:
Using ( y2 - y1 ) / ( x2 - x1 ) = gradient of a line
Substitute in coordinates of points C and D,
( yC - yB ) / ( xC - xB ) = ( 5 - 0 ) / ( 0 - 2 ) = 5/-2 or -5/2
Using y = mx + c
Applying the gradient found, line B has the equation, y = -5/2 x + c
To find c, substitute in the coordinates of point C,
5 = ( -5/2 x 0 ) + c
c = 5
Therefore the equation of line B is y = -5/2 x + 5
This can be rearranged,
(multiply everything by 2) --> 2y = -5x + 10
(rearrange) ---> 5x + 2y = 10
You can check your answer by using the coordinates of point D,
( 5 x 2 ) + ( 2 x 0 ) = 10 ---> Yes
Finally find the coordinates where the lines intersect:
A y = 4x - 14
B 5x + 2y = 10
A x2 2y = 8x - 28
Rearrange 8x - 2y = 28
Using simultaneous equations, add A x2 and B, to eliminate y,
5x + 8x + 2y - 2y = 10 + 28
13x = 38
x = 38/13
Substitute in x to A to find y,
y = ( 4 x 38/13 ) - 14
y = 152/13 - 182/13
y = -30/13
Put these coordinates into the equation for line B to check it works,
( 5 x 38/13 ) + (2 x -30/13 ) = 10
190/13 - 60/13 = 130/13 = 10 ----> Yes
The lines cross at coordinate ( 38/13, -30/13 )see more